# Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Chapter 11 Systems of Equations.

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Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Chapter 11 Systems of Equations

Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. 11.3 Solving Systems of Linear Equations by Addition

Martin-Gay, Developmental Mathematics, 2e 33 Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. The Addition Method Another method that can be used to solve a system of linear equations is called the addition or elimination method. The addition method is based on the addition property of equality: Adding equal quantities on both sides of an equation results in an equivalent equation.

Martin-Gay, Developmental Mathematics, 2e 44 Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Solve the following system: x + y = 7 x – y = 9 Example continued Add the equations to eliminate y. x + y = 7 x – y = 9 2x = 16 Divide both sides by 2. x = 8

Martin-Gay, Developmental Mathematics, 2e 55 Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Substitute 8 for x into one of the original equations and solve for y. x + y = 7 continued Our computations have produced the point (8, –1). Replace the x value with 8 in the first equation. 8 + y = 7 Add 8 to both sides of the equation. y = –1 continued

Martin-Gay, Developmental Mathematics, 2e 66 Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Check the point in the original equations. continued The solution of the system is (8, –1). 8 + (–1) = 7 x – y = 9x + y = 7 8 – (–1) = 9 True

Martin-Gay, Developmental Mathematics, 2e 77 Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Solve the following system of equations 6x – 3y = –3 4x + 5y = –9 Multiply both sides of the first equation by 5 and the second equation by 3. 5(6x – 3y) = 5(–3)30x – 15y = –15 Add the equations. 3(4x + 5y) = 3(–9)12x + 15y = –27 Solve for y. Example continued 42x = –42 x = –1 Divide both sides by 42.

Martin-Gay, Developmental Mathematics, 2e 88 Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Substitute –1 for x into one of the original equations and solve for y. 6x – 3y = –3 6(–1) – 3y = –3 Replace the x value in the first equation. –6 – 3y = –3 Simplify. –3y = 3 Add 6 to both sides. y = –1 Divide both sides by –3. Our computations have produced the point (–1, –1). continued

Martin-Gay, Developmental Mathematics, 2e 99 Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Check the point in the original equations. First equation, 6x – 3y = –3 6(–1) – 3(–1) = –3 True Second equation, 4x + 5y = –9 4(–1) + 5(–1) = –9 True The solution of the system is (–1, –1). continued

Martin-Gay, Developmental Mathematics, 2e 10 Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. To Solve a System of Two Linear Equations by the Addition Method Step 1: Rewrite each equation in standard form, Ax + By = C. Step 2: If necessary, multiply one or both equations by a nonzero number so that the coefficients of a chosen variable in the system are opposites. Step 3: Add the equations. Step 4: Find the value of one variable by solving equation from Step 3. Step 5: Find the value of the second variable by substituting the value found in Step 4 into either of the original equations. Step 6: Check the proposed solution in the original system. The Addition Method

Martin-Gay, Developmental Mathematics, 2e 11 Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Solve the system of equations using the addition method. First multiply both sides of the equations by a number that will clear the fractions out of the equations. Example continued

Martin-Gay, Developmental Mathematics, 2e 12 Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Multiply both sides of each equation by 12. (Note: You do not have to multiply each equation by the same number, but in this case it will be convenient to do so.) First equation, Multiply both sides by 12. Simplify. continued

Martin-Gay, Developmental Mathematics, 2e 13 Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Add the two resulting equations. 8x + 3y = – 18 6x – 3y = – 24 14x = – 42 x = –3 Divide both sides by 14. Second equation, Multiply both sides by 12. Simplify. continued

Martin-Gay, Developmental Mathematics, 2e 14 Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Substitute –3 for x into one of the original equations. 8x + 3y = –18 8(–3) + 3y = –18 –24 + 3y = –18 3y = –18 + 24 = 6 y = 2 We need to check the ordered pair (–3, 2) in both equations of the original system. continued

Martin-Gay, Developmental Mathematics, 2e 15 Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. Check the point in the original equations. First equation: True Second equation: True The solution is (–3, 2). continued

Martin-Gay, Developmental Mathematics, 2e 16 Copyright © 2011 Pearson Education, Inc. Publishing as Prentice Hall. In a similar fashion to what you found in the last section, use of the addition method to combine two equations might lead you to results like... 5 = 5 (which is always true, thus indicating that there are infinitely many solutions, since the two equations represent the same line), or 0 = 6 (which is never true, thus indicating that there are no solutions, since the two equations represent parallel lines). Special Cases