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Normal Normal Distributions  Family of distributions, all with the same general shape.  Symmetric about the mean  The y-coordinate (height) specified.

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Presentation on theme: "Normal Normal Distributions  Family of distributions, all with the same general shape.  Symmetric about the mean  The y-coordinate (height) specified."— Presentation transcript:

1 normal Normal Distributions  Family of distributions, all with the same general shape.  Symmetric about the mean  The y-coordinate (height) specified in terms of the mean and the standard deviation of the distribution

2 normal Normal Probability Density for all x Note: e is the mathematical constant, 2.718282 

3 normal Standard Normal Distribution for all x. The normal distribution with  =0 and  =1 is called the standard normal

4 normal Transformations Normal distributions can be transformed to the standard normal. We use what is called the z-score which is a value that gives the number of standard deviations that X is from the mean.

5 normal Standard Normal Table Use the table in the text to verify the following. P(z < -2) = F(2) = 0.0228 F(2) = 0.9773 F(1.42) = 0.9222 F(-0.95) = 0.1711

6 normal Example of the Normal The amount of instant coffee that is put into a 6 oz jar has a normal distribution with a standardard deviation of 0.03. oz. What proportion of the jar contain: a) less than 6.06 oz? b) more than 6.09 oz? c) less than 6 oz?

7 normal Normal Example - part a) Assume = 6 and  =.03. The problem requires us to find P(X < 6.06) Convert x = 6.06 to a z-score z = (6.06 - 6)/.03 = 2 and find P(z < 2) =.9773 So 97.73% of the jar have less than 6.06 oz.

8 normal Normal Example - part b) Again = 6 and  =.03. The problem requires us to find P(X > 6.09) Convert x = 6.09 to a z-score z = (6.09 - 6)/.03 = 3 and find P(z > 3) = 1- P(x < 3) = 1-.9987= 0.0013 So 0.13% of the jar havemore than 6.09oz.

9 normal Preview Probabiltiy Plots Normal Approximation of the Binomial Random Sampling The Central Limit Theorem


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