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Solve Absolute Value Equations © Evergreen Public Schools 2010.

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Presentation on theme: "Solve Absolute Value Equations © Evergreen Public Schools 2010."— Presentation transcript:

1 Solve Absolute Value Equations © Evergreen Public Schools 2010

2 I can write and solve an absolute value equation from a given situation with one variable. What do you think is the solution to | x + 1| = 5? What do you think is the solution to | x + 1| = 5? 2 Learning Target

3 Think about the card games we played yesterday. Make a list of numbers that are not changed by the absolute value bars. Make another list of numbers that are changed by the absolute value bars. Write down a general rule that describes what absolute value does to any given number. 3 LaunchLaunch

4 ©Evergreen Public Schools 2010 4 ExploreExplore

5 Let’s think about | x | 5 Share with your partner how you answered the questions. I will be asking you to tell us what your partner wrote.

6 Think about the card games we played yesterday. If x is non-negative then just write it without the bars. 6 |7| = ? Let’s think about | x | |7| = 7

7 If x is non-negative then just write it without the bars. If x is negative then make it the opposite value. 7 |-4| = ? Let’s think about | x | |-4| = 4

8 Think about the card game yesterday If we knew the answer was 7, what card could give us that answer? A positive 7 A negative 7 8

9 Let’s Solve 7 = | x | Since we do not know the value of x, use the definition for either possibility… 9 x = 7 -x = 7 x = -7 So the solution is x = 7 or x = – 7 How is this related to our card game?

10 Let’s Practice 1.| x |= 3 2.| x |= 0 3.– | x |= 5 4.| – x |= 7 5.| x |= – 12 Private think time Elbow Partner 10

11 Remember Round 4 of the Game? If the dealer turned over a distance card of positive 5, Starting card Distance card The two solutions are … -7 - 5 5 2 12 0 11 and the caller turned over a negative of positive 7

12 Remember Round 4 of the Game? So, you can add 2 to -7 and be 5 units from zero, and you can add 12 to -7 and be 5 units from zero. -7 - 5 5 2 12 0

13 Let’s Solve: 5 = | x – 7| Since we do not know the value of x – 7, use the definition for either possibility… x – 7 = 5 x = 12 So the solution is x = 12 or x = 2 The same solution as the previous slide, but a little faster. x – 7 = – 5 x = 2 13

14 1.| x – 1|= 0 2.|- x + 3|= 8 3.|9 – x |= 2 4.|2 x – 9|= 7 5.| x – 1|= -¾ Private think time Elbow Partner 14

15 1.| x – 1|= 0 2.|- x + 3|= 8 3.3|9 – x |= 6 4.|2 x – 9|= 7 5.| x – 1|= -3/4 1. x = 1 2. x = -5 or x = 11 3. x = -11 or x = 7 4. x = 1 or x = 8 5. no solution 15

16 ©Evergreen Public Schools 2010 16 Debrief Make a mini poster to explain your understanding of solving absolute value equations. Write an absolute value equation. Show how the following are related number line equation solution explanation

17 ©Evergreen Public Schools 2010 17 5 3 1 2 4 Learning Target Did you hit the target? I can solve inequalities in one variable. Rate your understanding of the target from 1 to 5. 5 is a bullseye!

18 ©Evergreen Public Schools 2010 18 Practice Practice 5. ___

19 ©Evergreen Public Schools 2010 19 Solve


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