Presentation is loading. Please wait.

Presentation is loading. Please wait.

Measuring chance Probabilities FETP India. Competency to be gained from this lecture Apply probabilities to field epidemiology.

Similar presentations


Presentation on theme: "Measuring chance Probabilities FETP India. Competency to be gained from this lecture Apply probabilities to field epidemiology."— Presentation transcript:

1 Measuring chance Probabilities FETP India

2 Competency to be gained from this lecture Apply probabilities to field epidemiology

3 Key issues Probabilities Rule of addition Rule of multiplication Non-independent events

4 Question 1 Suppose:  The success rate of a programme to stop smoking is 75% compared to the expected 70% Can we really be certain that the programme is successful? Probabilities

5 Question 2 Suppose:  The mean height of 200 adults in a suburban area of a city is 165 cm compared to the city’s mean height of 170 cm Can we really be certain that people in the suburb have a shorter height? Probabilities

6 Question 3 Suppose:  In a trial involving 100 patients, treatment A is better than treatment B Can we really be certain that treatment A is better than treatment B? Probabilities

7 Probabilities and statistical inference In statistics, we infer from a sample to a population In that process, there is a element of chance We study probabilities (science) to measure this element of chance (intuitive notion) Probabilities

8 Tossing a coin Two possible events (Outcomes):  Head or tail Probability of getting a head in a toss:  1/2 = 50% Probability of getting a tail in a toss:  1/2 = 50% Probabilities

9 Throwing a dice Six possible events (Outcomes):  1,2,3,4,5 or 6 Probability of getting a score of 1:  1/6 Probability of getting a score of 4:  1/6 Probability of getting a score of 6:  1/6 Probabilities

10 Drawing a card from a pack There are 52 cards in a pack of playing cards which includes:  4 aces, 2 red and 2 black A card is randomly picked from the pack:  Probability of getting an ace: 4/52  Probability of getting a black ace: 2/52  Probability of getting a red ace: 2/52 Probabilities

11 Using experience as a relative frequency Suppose a coin is tossed 10,000 times and head (H) has occurred 4,980 times The relative frequency of head is:  H = 4,980  10,000 = 0.498  0.5 Probabilities

12 Theoretical approach Assuming that the coin is fair, both head (H) and tail (T) have equal chance of occurring Probability of the event “head”: Number of outcomes of interest (say, Head) Number of possible outcomes i.e., P(H) = 1/2 and P(T) = 1/2 Probabilities

13 Generic concept of probabilities Numerator  Event of interest Denominator  All the possible events that may occur Probabilities are proportions:  They range between 0 and 1  The numerator is part of the denominator Probabilities

14 Definition of probabilities Probability is defined as a proportionate frequency If a variable can take any of N values and n of these constitute the event of interest to us, the probability of the event is given by n/N Number of outcomes of interest Total number of outcomes Probabilities

15 Rule of addition Mutually exclusive events  P(A) = Probability of event A occurring  P(B) = Probability of event B occurring The two events A and B are said to be mutually exclusive if they cannot occur together In this case, the probability that one OR the other occurs is the sum of the two individual probabilities  P(A or B) = P(A) + P(B) Rule of addition

16 “OR”: Additive probabilities What is the probability of getting a 3 (1/6) OR a 5 from a dice (1/6)  Probability of getting a score of 3 = 1/6  Probability of getting a score of 5 = 1/6 3 and 5 cannot occur at the same throw The total number of possible events remains 6 “1 OR 6” constitute 2 of the 6 possible events  Probability: 2 / 6 The probability of getting an event or the other is the sum of the individual probabilities  1/6 + 1/6 = 2/6 Rule of addition

17 Additive probabilities When the events are mutually exclusive and collectively exhaustive, the probability of each event add up to 1 Probability of getting a head in a coin toss:  0.5 Probability of getting a tail in a coin toss:  0.5 Probability of getting a head OR a tail  0.5 + 0.5 = 1 Rule of addition

18 Rule of multiplication P(A) = Probability of an event A occurring P(B) = Probability of an event B occurring The two events A and B are said to be independent if the occurrence of one has no implications on the other In this case, the probability of both A and B occurring at the same time is the product of the two individual probabilities  P (AB) = P (A) x P (B) Rule of multiplication

19 “AND”: Multiplicative probabilities A coin is tossed and a dice is thrown simultaneously The outcome of the toss of the coin has no implication on the result of the throw of the dice What is the probability of getting a head from a coin (1/2) AND a 6 from a dice (1/6) The total number of possible events is a multiplication of the possible events  2 x 6 = 12 “Head AND 6” is only one of the 12 possible events  Probability: 1 / 12 The probability of getting a combination of events is a multiplication of the individual probabilities  1/6 x 1/2 = 1/12

20 Properties of the events considered so far Mutually exclusive  If the tossed coin shows head, it does not shows tail Independent  The outcome of the coin tossing does not influence the dice throwing Rule of multiplication

21 Considering non-independent events Village survey Event A:  Being female  P (A): Probability of being female Event B:  Being under 5  P (B): Probability of being under 5 Event A and event B are not independent Non independent events

22 Change in the additive rule in the case of non-mutually exclusive events If the events are not mutually exclusive, the total probabilities exceed one Probability of being female, P(A) also includes female under 5 Probability of being under 5, P(B) also includes female under 5 Female under 5 are counted twice Subtract the probability of the combined events  P(A OR B) = P(A) + P (B) - P (A AND B) Non independent events

23 In Example from a clinical trial Proportion of male patients = 0.60 Proportion of young patients = 0.80 We wish to determine the probability of patients who were either male or young or both 0.6 + 0.8 = 1.4, absurd result  (Male and Young are counted twice) Sex and age are independent Probability of being male and young  0.6 x 0.8 = 0.48 Proportion who are either male or young ( or both)  0.6 + 0.8 - 0.48 = 0.92 Non independent events

24 Change in the multiplicative rule in the case of non-independent events: Conditional probabilities The probability of being a female under 5 is not equal to P (A) x P (B) P (A AND B) = P (A) x P (B, given A) = P (B) x P (A, given B) P (B, given A) is the probability of getting the event “under 5” (B) GIVEN that the event “female” occurred (A) Non independent events

25 Selection of a subject in a survey Survey in a small community of 800 subjects  128 are aged under 5 years of age  192 are 5–15 years of age  480 are aged above 15 years A subject is selected at random Probability of selecting a child under 5 years of age  128 / 800 = 0.16 Probability of selecting a child 5 to 15 years of age  192 / 800 = 0.24 Probability of selecting a child older than 15 years  128+192 / 800 = 320 / 800 = 0.40 Non independent events

26 Illustration of conditional probabilities Consider a group of 5 persons  3 males (M1, M2, M3) and 2 females (F1, F2) One person is selected at random and then a second is selected again at random from the remaining 4 What is the probability of selecting a male twice? First round:  Probability of selecting a male = 3 / 5 (M2) Second round:  There are 4 persons left (M1, M3, F1, F2)  Probability of selecting a male = 2 / 4 Probability of selecting a male on both occasions 3 / 5 x 2 / 4 = 6 / 20 Non independent events

27 Checking from first principles The first person can be selected in 5 ways  M1 or M2 or M3 or F1 or F2 With each of these the second person can be selected in 4 ways  (e.g., M1 or M3 or F1 or F2 following M2) Total number of ways to select 2 persons  5 x 4 = 20 Selection of a male  First round: 3 ways  Second round: 2 ways Total number of ways to select a male twice  3 x 2 = 6, required Probability = 6 / 20 Non independent events

28 Laboratory example Probability of ‘0’ contaminations  0.728 Probability of getting at least 2 contaminations  Probability of getting 2 contaminated cultures +  Probability of getting 3 contaminated cultures 0.026 + 0.002 = 0.028 Non independent events

29 Random variables and probability distributions Statistical experiment is any process by which an observation (or measurement) is obtained  Counting the number of sick patients  Measuring the birth weight of infants Variable is called random variable  Discrete random variable The observation can take only a finite number of values  Continuous random variable The observation can take infinite number of values The probability distribution is simply an assignment of probabilities:  To the specific values of the random variable  To a range of values of the random variable Non independent events

30 Key messages Probabilities quantify chance The probability of occurrence of one or another mutually exclusive events are added The probability of occurrence of one and another independent event are multiplied Non-independent events are addressed through conditional probabilities


Download ppt "Measuring chance Probabilities FETP India. Competency to be gained from this lecture Apply probabilities to field epidemiology."

Similar presentations


Ads by Google