Download presentation

1
**© 2011 Pearson Education, Inc**

2
**Statistics for Business and Economics**

Chapter 3 Probability © 2011 Pearson Education, Inc

3
**© 2011 Pearson Education, Inc**

Contents Events, Sample Spaces, and Probability Unions and Intersections Complementary Events The Additive Rule and Mutually Exclusive Events Conditional Probability The Multiplicative Rule and Independent Events Random Sampling Baye’s Rule As a result of this class, you will be able to ... © 2011 Pearson Education, Inc

4
**© 2011 Pearson Education, Inc**

Learning Objectives Develop probability as a measure of uncertainty Introduce basic rules for finding probabilities Use probability as a measure of reliability for an inference As a result of this class, you will be able to ... © 2011 Pearson Education, Inc

5
**© 2011 Pearson Education, Inc**

Thinking Challenge What’s the probability of getting a head on the toss of a single fair coin? Use a scale from 0 (no way) to 1 (sure thing). So toss a coin twice. Do it! Did you get one head & one tail? What’s it all mean? © 2011 Pearson Education, Inc

6
**© 2011 Pearson Education, Inc**

Many Repetitions!* Total Heads Number of Tosses 1.00 0.75 0.50 0.25 0.00 25 50 75 100 125 Number of Tosses © 2011 Pearson Education, Inc

7
**Events, Sample Spaces, and Probability**

3.1 Events, Sample Spaces, and Probability :1, 1, 3 © 2011 Pearson Education, Inc

8
**Experiments & Sample Spaces**

Process of observation that leads to a single outcome that cannot be predicted with certainty Sample point Most basic outcome of an experiment Sample space (S) Collection of all possible outcomes Sample Space Depends on Experimenter! © 2011 Pearson Education, Inc

9
**Sample Space Properties**

Mutually Exclusive 2 outcomes can not occur at the same time Male & Female in same person Collectively Exhaustive One outcome in sample space must occur. Male or Female Experiment: Observe Gender © 2011 Pearson Education, Inc © T/Maker Co.

10
**Visualizing Sample Space**

1. Listing S = {Head, Tail} 2. Venn Diagram H T S © 2011 Pearson Education, Inc

11
**© 2011 Pearson Education, Inc**

Sample Space Examples Experiment Sample Space Toss a Coin, Note Face {Head, Tail} Toss 2 Coins, Note Faces {HH, HT, TH, TT} Select 1 Card, Note Kind {2♥, 2♠, ..., A♦} (52) Select 1 Card, Note Color {Red, Black} Play a Football Game {Win, Lose, Tie} Inspect a Part, Note Quality {Defective, Good} Observe Gender {Male, Female} © 2011 Pearson Education, Inc

12
**© 2011 Pearson Education, Inc**

Events Specific collection of sample points Simple Event Contains only one sample point Compound Event Contains two or more sample points © 2011 Pearson Education, Inc

13
**© 2011 Pearson Education, Inc**

Venn Diagram Experiment: Toss 2 Coins. Note Faces. Sample Space S = {HH, HT, TH, TT} Compound Event: At least one Tail Other compound events could be formed: Tail on the second toss {HT, TT} At least 1 Head {HH, HT, TH} TH HT Outcome HH TT S © 2011 Pearson Education, Inc

14
**© 2011 Pearson Education, Inc**

Event Examples Experiment: Toss 2 Coins. Note Faces. Sample Space: HH, HT, TH, TT Event Outcomes in Event Typically, the last event (Heads on Both) is called a simple event. 1 Head & 1 Tail HT, TH Head on 1st Coin HH, HT At Least 1 Head HH, HT, TH Heads on Both HH © 2011 Pearson Education, Inc

15
**© 2011 Pearson Education, Inc**

Probabilities © 2011 Pearson Education, Inc

16
**© 2011 Pearson Education, Inc**

What is Probability? 1. Numerical measure of the likelihood that event will cccur P(Event) P(A) Prob(A) 2. Lies between 0 & 1 3. Sum of sample points is 1 1 Certain .5 Impossible © 2011 Pearson Education, Inc

17
**Probability Rules for Sample Points**

Let pi represent the probability of sample point i. 1. All sample point probabilities must lie between 0 and 1 (i.e., 0 ≤ pi ≤ 1). 2. The probabilities of all sample points within a sample space must sum to 1 (i.e., pi = 1). © 2011 Pearson Education, Inc

18
**Equally Likely Probability**

P(Event) = X / T X = Number of outcomes in the event T = Total number of sample points in Sample Space Each of T sample points is equally likely — P(sample point) = 1/T © T/Maker Co. © 2011 Pearson Education, Inc

19
**Steps for Calculating Probability**

1. Define the experiment; describe the process used to make an observation and the type of observation that will be recorded 2. List the sample points 3. Assign probabilities to the sample points 4. Determine the collection of sample points contained in the event of interest 5. Sum the sample points probabilities to get the event probability © 2011 Pearson Education, Inc

20
**© 2011 Pearson Education, Inc**

Combinations Rule A sample of n elements is to be drawn from a set of N elements. The, the number of different samples possible is denoted by and is equal to where the factorial symbol (!) means that For example, 0! is defined to be 1. © 2011 Pearson Education, Inc

21
**Unions and Intersections**

3.2 Unions and Intersections :1, 1, 3 © 2011 Pearson Education, Inc

22
**© 2011 Pearson Education, Inc**

Compound Events Compound events: Composition of two or more other events. Can be formed in two different ways. © 2011 Pearson Education, Inc

23
**Unions & Intersections**

Outcomes in either events A or B or both ‘OR’ statement Denoted by symbol (i.e., A B) 2. Intersection Outcomes in both events A and B ‘AND’ statement Denoted by symbol (i.e., A B) © 2011 Pearson Education, Inc

24
**Event Union: Venn Diagram**

Experiment: Draw 1 Card. Note Kind, Color & Suit. Ace Black Event Black: 2, 2,..., A Sample Space: 2, 2, 2, ..., A S Event Ace: A, A, A, A Event Ace Black: A, ..., A, 2, ..., K © 2011 Pearson Education, Inc

25
**Event Union: Two–Way Table**

Experiment: Draw 1 Card. Note Kind, Color & Suit. Color Simple Event Ace: A, A, A, A Sample Space (S): 2, 2, 2, ..., A Type Red Black Total Ace Ace & Ace & Ace Red Black Non-Ace Non & Non & Non- Red Black Ace Total Red Black S Event Ace Black: A,..., A, 2, ..., K Simple Event Black: 2, ..., A © 2011 Pearson Education, Inc

26
**Event Intersection: Venn Diagram**

Experiment: Draw 1 Card. Note Kind, Color & Suit. Ace Black Event Black: 2,...,A Sample Space: 2, 2, 2, ..., A S Event Ace: A, A, A, A Event Ace Black: A, A © 2011 Pearson Education, Inc

27
**Event Intersection: Two–Way Table**

Experiment: Draw 1 Card. Note Kind, Color & Suit. Color Simple Event Ace: A, A, A, A Sample Space (S): 2, 2, 2, ..., A Type Red Black Total Ace Ace & Ace & Ace Red Black Non-Ace Non & Non & Non- Red Black Ace Event Ace Black: A, A Total Red Black S Simple Event Black: 2, ..., A © 2011 Pearson Education, Inc

28
**Compound Event Probability**

1. Numerical measure of likelihood that compound event will occur 2. Can often use two–way table Two variables only © 2011 Pearson Education, Inc

29
**Event Probability Using Two–Way Table**

Total 1 2 A P(A B ) P(A B ) P(A ) 1 1 1 1 2 1 A P(A B ) P(A B ) P(A ) 2 2 1 2 2 2 Total P(B ) P(B ) 1 1 2 Joint Probability Marginal (Simple) Probability © 2011 Pearson Education, Inc

30
**© 2011 Pearson Education, Inc**

Two–Way Table Example Experiment: Draw 1 Card. Note Kind & Color. Color Type Red Black Total Ace 2/52 2/52 4/52 Non-Ace 24/52 24/52 48/52 P(Ace) Total 26/52 26/52 52/52 P(Red) P(Ace Red) © 2011 Pearson Education, Inc

31
**© 2011 Pearson Education, Inc**

Thinking Challenge P(A) = P(D) = P(C B) = P(A D) = P(B D) = What’s the Probability? Event C D Total A 4 2 6 B 1 3 5 10 Let students solve first. Allow about 20 minutes for this. © 2011 Pearson Education, Inc

32
**© 2011 Pearson Education, Inc**

Solution* The Probabilities Are: P(A) = 6/10 P(D) = 5/10 P(C B) = 1/10 P(A D) = 9/10 P(B D) = 3/10 Event C D Total A 4 2 6 B 1 3 5 10 © 2011 Pearson Education, Inc

33
**© 2011 Pearson Education, Inc**

3.3 Complementary Events :1, 1, 3 © 2011 Pearson Education, Inc

34
**© 2011 Pearson Education, Inc**

Complementary Events Complement of Event A The event that A does not occur All events not in A Denote complement of A by AC S AC A © 2011 Pearson Education, Inc

35
**© 2011 Pearson Education, Inc**

Rule of Complements The sum of the probabilities of complementary events equals 1: P(A) + P(AC) = 1 S AC A © 2011 Pearson Education, Inc

36
**Complement of Event Example**

Experiment: Draw 1 Card. Note Color. Black Sample Space: 2, 2, 2, ..., A S Event Black: 2, 2, ..., A Complement of Event Black, BlackC: 2, 2, ..., A, A © 2011 Pearson Education, Inc

37
**The Additive Rule and Mutually Exclusive Events**

3.4 The Additive Rule and Mutually Exclusive Events :1, 1, 3 © 2011 Pearson Education, Inc

38
**Mutually Exclusive Events**

Events do not occur simultaneously A B does not contain any sample points © 2011 Pearson Education, Inc

39
**Mutually Exclusive Events Example**

Experiment: Draw 1 Card. Note Kind & Suit. Outcomes in Event Heart: 2, 3, 4 , ..., A Sample Space: 2, 2, 2, ..., A Mutually Exclusive What is the intersection of mutually exclusive events? The null set. S Event Spade: 2, 3, 4, ..., A Events and are Mutually Exclusive © 2011 Pearson Education, Inc

40
**© 2011 Pearson Education, Inc**

Additive Rule Used to get compound probabilities for union of events P(A OR B) = P(A B) = P(A) + P(B) – P(A B) For mutually exclusive events: P(A OR B) = P(A B) = P(A) + P(B) © 2011 Pearson Education, Inc

41
**© 2011 Pearson Education, Inc**

Additive Rule Example Experiment: Draw 1 Card. Note Kind & Color. Color Type Red Black Total Ace 2 4 Non-Ace 24 48 26 52 Try other examples using this table. P(Ace Black) = P(Ace) + P(Black) – P(Ace Black) = – = © 2011 Pearson Education, Inc

42
**© 2011 Pearson Education, Inc**

Thinking Challenge Using the additive rule, what is the probability? P(A D) = P(B C) = Event C D Total A 4 2 6 B 1 3 5 10 Let students solve first. Allow about 10 minutes for this. © 2011 Pearson Education, Inc

43
**© 2011 Pearson Education, Inc**

Solution* Using the additive rule, the probabilities are: 1. P(A D) = P(A) + P(D) – P(A D) = – = 2. P(B C) = P(B) + P(C) – P(B C) = – = © 2011 Pearson Education, Inc

44
**Conditional Probability**

3.5 Conditional Probability :1, 1, 3 © 2011 Pearson Education, Inc

45
**Conditional Probability**

1. Event probability given that another event occurred 2. Revise original sample space to account for new information Eliminates certain outcomes 3. P(A | B) = P(A and B) = P(A B) P(B) P(B) © 2011 Pearson Education, Inc

46
**Conditional Probability Using Venn Diagram**

Black ‘Happens’: Eliminates All Other Outcomes Ace Black Black S (S) Event (Ace Black) © 2011 Pearson Education, Inc

47
**Conditional Probability Using Two–Way Table**

Experiment: Draw 1 Card. Note Kind & Color. Color Type Red Black Total Ace 2 4 Non-Ace 24 48 26 52 Revised Sample Space Try other examples using this table. © 2011 Pearson Education, Inc

48
**© 2011 Pearson Education, Inc**

Thinking Challenge Using the table then the formula, what’s the probability? P(A|D) = P(C|B) = Event C D Total A 4 2 6 B 1 3 5 10 Let students solve first. Allow about 20 minutes for this. © 2011 Pearson Education, Inc

49
**© 2011 Pearson Education, Inc**

Solution* Using the formula, the probabilities are: © 2011 Pearson Education, Inc

50
**The Multiplicative Rule and Independent Events**

3.6 The Multiplicative Rule and Independent Events :1, 1, 3 © 2011 Pearson Education, Inc

51
**© 2011 Pearson Education, Inc**

Multiplicative Rule 1. Used to get compound probabilities for intersection of events 2. P(A and B) = P(A B) = P(A) P(B|A) = P(B) P(A|B) 3. For Independent Events: P(A and B) = P(A B) = P(A) P(B) © 2011 Pearson Education, Inc

52
**Multiplicative Rule Example**

Experiment: Draw 1 Card. Note Kind & Color. Color Type Red Black Total Ace 2 2 4 Try other examples using this table. Non-Ace 24 24 48 Total 26 26 52 P(Ace Black) = P(Ace)∙P(Black | Ace) © 2011 Pearson Education, Inc

53
**Statistical Independence**

1. Event occurrence does not affect probability of another event Toss 1 coin twice 2. Causality not implied 3. Tests for independence P(A | B) = P(A) P(B | A) = P(B) P(A B) = P(A) P(B) © 2011 Pearson Education, Inc

54
**© 2011 Pearson Education, Inc**

Thinking Challenge Using the multiplicative rule, what’s the probability? Event C D Total A 4 2 6 B 1 3 5 10 P(C B) = P(B D) = P(A B) = Let students solve first. Allow about 10 minutes for this. © 2011 Pearson Education, Inc

55
**© 2011 Pearson Education, Inc**

Solution* Using the multiplicative rule, the probabilities are: © 2011 Pearson Education, Inc

56
**© 2011 Pearson Education, Inc**

Tree Diagram Experiment: Select 2 pens from 20 pens: 14 blue & 6 red. Don’t replace. Dependent! R P(R R)=(6/20)(5/19) =3/38 5/19 R 6/20 14/19 B P(R B)=(6/20)(14/19) =21/95 R 6/19 P(B R)=(14/20)(6/19) =21/95 14/20 B 13/19 B P(B B)=(14/20)(13/19) =91/190 © 2011 Pearson Education, Inc

57
**© 2011 Pearson Education, Inc**

3.7 Random Sampling :1, 1, 3 © 2011 Pearson Education, Inc

58
**Importance of Selection**

How a sample is selected from a population is of vital importance in statistical inference because the probability of an observed sample will be used to infer the characteristics of the sampled population. © 2011 Pearson Education, Inc

59
**© 2011 Pearson Education, Inc**

Random Sample If n elements are selected from a population in such a way that every set of n elements in the population has an equal probability of being selected, the n elements are said to be a random sample. © 2011 Pearson Education, Inc

60
**Random Number Generators**

Most researchers rely on random number generators to automatically generate the random sample. Random number generators are available in table form, and they are built into most statistical software packages. © 2011 Pearson Education, Inc

61
**© 2011 Pearson Education, Inc**

3.8 Bayes’s Rule :1, 1, 3 © 2011 Pearson Education, Inc

62
**© 2011 Pearson Education, Inc**

Bayes’s Rule Given k mutually exclusive and exhaustive events B1, B1, Bk , such that P(B1) + P(B2) + … + P(Bk) = 1, and an observed event A, then © 2011 Pearson Education, Inc

63
**© 2011 Pearson Education, Inc**

Bayes’s Rule Example A company manufactures MP3 players at two factories. Factory I produces 60% of the MP3 players and Factory II produces 40%. Two percent of the MP3 players produced at Factory I are defective, while 1% of Factory II’s are defective. An MP3 player is selected at random and found to be defective. What is the probability it came from Factory I? © 2011 Pearson Education, Inc

64
**© 2011 Pearson Education, Inc**

Bayes’s Rule Example Defective 0.02 Factory I 0 .6 0.98 Good Defective 0.01 0 .4 Factory II 0.99 Good © 2011 Pearson Education, Inc

65
**© 2011 Pearson Education, Inc**

Key Ideas Probability Rules for k Sample Points, S1, S2, S3, , Sk ≤ P(Si) ≤ 1 2. © 2011 Pearson Education, Inc

66
**© 2011 Pearson Education, Inc**

Key Ideas Random Sample All possible such samples have equal probability of being selected. © 2011 Pearson Education, Inc

67
**© 2011 Pearson Education, Inc**

Key Ideas Combinations Rule Counting number of samples of n elements selected from N elements © 2011 Pearson Education, Inc

68
**© 2011 Pearson Education, Inc**

Key Ideas Bayes’s Rule © 2011 Pearson Education, Inc

Similar presentations

OK

© 2003 Prentice-Hall, Inc.Chap 4-1 Basic Probability IE 440 PROCESS IMPROVEMENT THROUGH PLANNED EXPERIMENTATION Dr. Xueping Li University of Tennessee.

© 2003 Prentice-Hall, Inc.Chap 4-1 Basic Probability IE 440 PROCESS IMPROVEMENT THROUGH PLANNED EXPERIMENTATION Dr. Xueping Li University of Tennessee.

© 2018 SlidePlayer.com Inc.

All rights reserved.

Ads by Google

Ppt on vision and mission statements Ppt on population census 2011 data Ppt on green building technology Ppt on wildlife and vegetation conservation Ppt on history of vedic maths pdf Ppt on online crime file management in java A ppt on social networking sites Ppt on green revolution vs organic farming Ppt on forests in india Ppt on vegetarian and non vegetarian