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Unit 4 : Solutions 8.4 – Dilution and Solution Preparation.

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1 Unit 4 : Solutions 8.4 – Dilution and Solution Preparation

2 Context Remember: c=n/v Why would this be an important formula to know for chemistry? Lab Work: Preparation of Solutions!!

3 Solution Preparation Solutions need to be known for multiple reasons Concentrations need to be known Two methods: 1.Solution preparation from a solid solute 2.Solution preparation from a liquid solute

4 Solution Terms “Standard Solution”: a solution which you have made, and for which you know the accurate concentration “Stock Solution”: a concentrated solution that you make or buy, and then will use to make more dilute solutions

5 Equipment Solutions are made in volumetric flasks Volumetric flasks and pipettes are very, very accurate pieces of glassware ▫Look on the vessel for +/- accuracy, generally +/- 0.1mL Graduated cylinders and pipettes have intermediate accuracy Beaker are NOT actually for measuring volume

6 Solutions from Solids 1.Do the math – find out what mass of solute you require 2.Mass out the solid into a beaker or onto a weighing paper 3.Dissolve the solid in approximately half of the total volume of the solution, in a beaker 4.Transfer the contents of the beaker to a volumetric flask

7 5.Rinse the beaker and stirring rod, and transfer that liquid to the volumetric flask 6.Carefully add water until the meniscus reaches the etched line 7.Stopper, and invert to mix

8 Solutions from liquid solute You want to dilute the stock solution you have, by adding more solvent … you are diluting the solution, which lowers the concentration c 1 v 1 = c 2 v 2 “1” means the initial conditions “2” means the final conditions ** New Total Volume

9 Example How much 2.0 M NaCl solution would you need to make 250 mL of 0.15 M NaCl solution? c 1 v 1 = c 2 v 2 c 1 = 2.0 mol/L v 1 = ? L c 2 = 0.15 mol/L v 2 = 0.250 L v 1 = 0.0188 L = 18.8 mL

10 Example 2 What is the final concentration of NaCl if 300mL of water is added to 400 mL of a 1.23 M solution of NaCl? c 1 v 1 = c 2 v 2 c 1 = 1.23 mol/L v 1 = 400 mL = 0.400 L c 2 = ? v 2 = 0.70 L c 2 = 0.703 mol/L

11 Note Check for the “reasonableness” of answers If you are diluting something, the final concentration will be LESS

12 Solutions for Liquid Stock Solutions 1.Do the math – find the volume of liquid required to make your solution 2.Measure that volume using a pipette (measure the meniscus properly) 3.Transfer the liquid to the volumetric flask 4.Carefully add water until the meniscus reaches the etched line 5.Stopper, and invert to mix

13 Homework Worksheet


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