Download presentation

Presentation is loading. Please wait.

Published byJeffery Weaver Modified over 7 years ago

1
DETERMING CONCENTRATIONS OF SOLUTIONS

2
MOLAR Molar is mol solube/1 L solution Making molar solution 1)Add ½ of the total solvent 2)Add required amount of solute 3)Add water until final volume of solution

3
MAKE 2 L OF 3 M SODIUM CHLORIDE Determine how much NaCl is needed (3 mol NaCl/1 L solution) * 2 L solution = 6 mol NaCl (6 mol NaCl) * (58.44 g NaCl/1 mol NaCl) = 350.64 g NaCl Mix solution 1)Add 1 L water to beaker or flask 2)Add 350.64 g NaCl and stir until dissolved 3)Add water until there is exactly 2 L of solution

4
MAKE 1.7 L OF 2 M SODIUM CHLORIDE Determine how much NaCl is needed (2 mol NaCl/1 L solution) * 1.7 L solution = 3.4 mol NaCl (3.4 mol NaCl) * (58.44 g NaCl/1 mol NaCl) = 198.70 g NaCl Mix solution 1)Add.9 L water to beaker or flask 2)Add 198.70 g NaCl and stir until dissolved 3)Add water until there is exactly 1.7 L of solution

5
DETERMINING THE CONCENTRATION Molar is mol solute/L solution Determine concentration 1)Determine how many moles of solute 2)Divide by total liters of solution

6
WHAT IS THE CONCENTRATION? What is the concentration if 43.12 g NaCl is dissolved in 2.2 L of solution? 1)Determine moles of NaCl 43.12 g NaCl (1 mol NaCl/58.44 g NaCl) =.74 mol NaCl 2) Divide moles by volume.74 mol NaCl/2.2 L solution =.34 M NaCl

7
WHAT IS THE CONCENTRATION? What is the concentration if 97.63 g NaCl is dissolved in 2.7 L of solution? 1)Determine moles of NaCl 97.63 g NaCl (1 mol NaCl/58.44 g NaCl) = 1.67 mol NaCl 2) Divide moles by volume 1.67 mol NaCl/2.7 L solution =.62 M NaCl

8
HOW MANY GRAMS? How much NaCl is in 2 L of 4 M NaCl? It’s all dimensional analysis (4 mol NaCl/1 L solution)(2 L solution)(58.44 g NaCl/1 mol NaCl) = 467.52 g NaCl

9
HOW MANY GRAMS? How much NaCl is in 617 mL of 3.5 M NaCl? (3.5 mol NaCl/1 L solution)(617 mL solution)(1 L solution/1000 mL solution)(58.44 g NaCl/1 mol NaCl) = 467.52 g NaCl

10
HOW MANY GRAMS? How much NaCl is in 617 mL of 3.5 M NaCl? (3.5 mol NaCl/1 L solution)(617 mL solution)(1 L solution/1000 mL solution)(58.44 g NaCl/1 mol NaCl) = 467.52 g NaCl

11
DILUTING A SOLUTION Adding water to a solution dilutes it, reducing the concentration A new concentration of a diluted solution is found using the following formula C1V1 = C2V2 C1 = original concentration V1 = amount of original solution C2 = new concentration V2 = new volume (original solution volume + volume of water added)

12
What is the new concentration if 10 mL of 4M NaCl is combined with 40 mL of water? C1V1 = C2V2 (4M)(10 mL) = C2(50 mL) C2 =.8M NaCl

Similar presentations

© 2023 SlidePlayer.com Inc.

All rights reserved.

To make this website work, we log user data and share it with processors. To use this website, you must agree to our Privacy Policy, including cookie policy.

Ads by Google