1. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-1 Electronics Principles & Applications Eighth Edition Chapter 7 More About Small-Signal Amplifiers Charles A. Schuler

2. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-2 Amplifier Coupling Voltage Gain FET Amplifiers Negative Feedback Frequency Response Positive Feedback INTRODUCTION

3. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-3 V CC These two points are at different dc voltages. Capacitive coupling is convenient in cascade ac amplifiers.

4. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-4 V CC Direct coupling is required for dc gain.

5. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-5 V CC The Darlington is a popular dc arrangement.

6. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-6 V CC P S 10:1 10  Z RATIO = T RATIO 2 = 10 2 = 100 Z COLLECTOR = 100 x 10  = 1000  Transformer coupling offers the advantage of impedance matching.

7. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-7 Transformer coupling is used in 70.7 volt sound systems.

8. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-8 V CC Transformer coupling can be used in bandpass amplifiers to achieve selectivity. fRfR Gain

9. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-9 Amplifier coupling quiz Capacitive coupling is not useful for _________ amplifiers. dc Dc frequency response requires ________ coupling. direct Transformer coupling offers the advantage of _________ matching. impedance Tuned transformer coupling provides frequency _____________. selectivity A Darlington amplifier is an example of _________ coupling. direct

10. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-10 R B1 E B C RLRL V CC R B2 RERE = 12 V 2.7 k  22 k  = 2.2 k  More about solving the practical circuit for its ac conditions: = 220  Z in = ?

11. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-11 R B1 E B C RLRL V CC R B2 RERE = 12 V 2.7 k  22 k  = 2.2 k  Z in is a combination of R B1, R B2, and r in of the transistor. = 220  r in =  (R E + r E ) r in =  (220  + 9.03  ) r in = 34.4 k  Note: r in =  r E when R E is bypassed. Determine r in first:

12. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-12 R B1 E B C RLRL V CC R B2 RERE = 12 V 2.7 k  22 k  = 2.2 k  = 220  Z in = 1 R B2 1 r in 1 + R B1 1 +++ Z in = 1 2.7 k  1 34.4 k  1 22 k  1 Z in = 2.25 k  R B1, R B2, and r in act in parallel to load the input signal.

13. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-13 R B1 V CC R B2 RERE = 12 V 2.7 k  22 k  RLRL = 2.2 k  = 220  Load = 2.2 k  What happens when an amplifier is loaded? R L and the Load act in parallel. R P = 1.1 k 

14. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-14 R B1 R B2 RERE V CC = 12 V 2.7 k  22 k  RLRL = 2.2 k  = 220  Load = 2.2 k  There are two saturation currents for a loaded amplifier. R P = 1.1 k  I SAT(DC) = V CC R L + R E = 4.96 mA I SAT(AC) = V CC R P + R E = 9.09 mA

15. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-15 0 24 6 8 1012 14 16 18 2 4 6 8 10 12 14 V CE in Volts I C in mA 20  A 0  A 100  A 80  A 60  A 40  A There are two load lines for a loaded amplifier. DC TEMPORARY AC The DC load line connects V CC and I SAT(DC). A temporary AC load line connects V CC and I SAT(AC).

16. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-16 0 24 6 8 1012 14 16 18 2 4 6 8 10 12 14 V CE in Volts I C in mA 20  A 0  A 100  A 80  A 60  A 40  A 5.3 V DC AC TEMP. AC The quiescent V CE is projected to the DC load line to establish the Q-point. The AC load line is drawn through the Q-point, parallel to the temporary AC load line.

17. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-17 0 24 6 8 1012 14 16 18 2 4 6 8 10 12 14 V CE in Volts I C in mA 20  A 0  A 100  A 80  A 60  A 40  A 5.3 V AC The AC load line shows the limits for V CE and if the Q-point is properly located. With loaded amplifiers, the Q-point is often closer to saturation.

18. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-18 R B1 R B2 RERE V CC = 12 V 2.7 k  22 k  RLRL = 2.2 k  = 220  Load = 2.2 k  What about voltage gain for a loaded amplifier? R P = 1.1 k  A V = RPRP R E + r E A V = 1.1 k  220  9.03  = 4.8

19. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-19 V CC Z in of the 2nd stage loads the 1st stage. When analyzing cascade amplifiers, remember: 2nd 1st

20. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-20 Amplifier ac conditions quiz Emitter bypassing _________ an amplifier’s input impedance. decreases Loading at the output of an amplifier ________ its voltage gain. decreases A loaded amplifier has two load lines: dc and ___________. ac The clipping points of a loaded amplifier are set by its _______ load line. ac In a cascade amplifier, the Z in of a stage _______ the prior stage. loads

21. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-21 Drain Source Gate V DD = 20 V V GS = 1.5 V RGRG C R L = 5 k  Input signal Common-source JFET amplifier. Fixed bias I SAT = 20 V 5 k  = 4 mA Phase-inverted output

22. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-22 0 2 4 1 V DS in Volts I D in mA 5 10 15 20 25 3 -2.5 -2.0 -1.5 -0.5 0 N-channel JFET characteristic curves V GS in Volts Load line The Q-point is set by the fixed bias. 8 V P-P 1 V P-P A V = 8

23. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-23 0 2 4 1 V DS in Volts I D in mA 5 10 15 20 25 3 -2.5 -2.0 -1.5 -0.5 0 Determining forward transfer admittance: Y fs = IDID  V GS V GS in Volts V DS 1.6 mA = 1.6 mS

24. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-24 D S G V DD = 20 V V GS = 1.5 V RGRG C R L = 5 k  When the forward transfer admittance is known, the voltage gain can be determined using: A V = Y fs x R L = 1.6 mS x 5 k  = 8 This agrees with the graphic solution.

25. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-25 D S G V DD V GS = I D x R S RGRG C RLRL RSRS Source bias eliminates the need for a separate V GS supply. I S = I D This resistor also provides ac negative feedback which decreases the voltage gain.

26. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-26 JFET amplifier quiz In a common-source amplifier, the input signal goes to the _______. gate In a common-source amplifier, the input to output phase relationship is ____. 180 o The voltage gain of a C-S amplifier is equal to Y fs x _________. load resistance Source bias is produced by current flow through the _______ resistor. source An unbypassed source resistor _______ the voltage gain of a C-S amp. decreases

27. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-27 V in - BV out A(V in - BV out ) BV out A = open loop gain Summing junction V in V out A B Feedback A negative feedback model B = feedback ratio V out = A(V in - BV out ) V out = AV in - ABV out AV in V out 1 = - AB AV in V out AB +1 = V in V out AB +1 A = V in V out AB +1 A = A V in V out A simplified model

28. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-28 D S G V DD RGRG C RLRL RSRS = 5 k  = 800  The feedback ratio (B) for this circuit is easy to determine since the source and drain currents are the same. B = 800  5 k  = 0.16

29. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-29 AB +1 A V in V out Use the simplified model: A (WITH NEG. FEEDBACK) = 8 (8)(0.16) + 1 = 3.51

30. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-30 CSCS D G V DD RGRG C RLRL RSRS The source bypass capacitor will eliminate the ac negative feedback and restore the voltage gain.

31. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-31 Amplifier Negative Feedback DC reduces sensitivity to device parameters DC stabilizes operating point DC reduces sensitivity to temperature change AC reduces gain AC increases bandwidth AC reduces signal distortion and noise AC may change input and output impedances

32. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-32 0.707 A max A f The frequency response curve of an ac amplifier Bandwidth The gain is maximum in the midband. A max Midband The bandwidth spans the -3 dB points which are called the break frequencies. -3dB

33. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-33 50  10  F 1 k  100  1k  6.8 k  The emitter bypass capacitor in this amplifier has a significant effect on both gain and bandwidth.

34. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-34 Gain in dB 0 50 Frequency 10 Hz 100 MHz BW 1 BW 2 Gain and bandwidth with and without the emitter bypass

35. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-35 Amplifier frequency response The lower break frequency is partly determined by coupling capacitors. It is also influenced by emitter bypass capacitors. The upper break frequency is partly determined by transistor internal capacitance. Both break frequencies can be influenced by negative feedback.

36. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-36 Positive Feedback Is the opposite of negative feedback Increases gain and reduces bandwidth Can be used in some circuits to reduce the effects of noise The next slide shows a circuit with a noise problem.

37. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-37 This circuit is supposed to convert the input signal to a rectangular output signal. It works, but the output waveform shows an extra pulse caused by noise. The trip points are equal.

38. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-38 UTP LTP This circuit has positive feedback and two trip points. The hysteresis is the difference between the trip points (UTP and LTP) and that makes this circuit less sensitive to noise. The output waveform is noise free. R5 provides positive feedback back from the output amplifier to the input amplifier.

39. © 2013 The McGraw-Hill Companies, Inc. All rights reserved. McGraw-Hill 7-39 REVIEW Amplifier Coupling Voltage Gain FET Amplifier Negative Feedback Frequency Response Positive Feedback