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How to do Stoichiometry. The Question What mass of Fe 2 S 3 is produced when 4.68 grams of Fe reacts with 2.88 grams of S? What mass of Fe 2 S 3 is produced.

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Presentation on theme: "How to do Stoichiometry. The Question What mass of Fe 2 S 3 is produced when 4.68 grams of Fe reacts with 2.88 grams of S? What mass of Fe 2 S 3 is produced."— Presentation transcript:

1 How to do Stoichiometry

2 The Question What mass of Fe 2 S 3 is produced when 4.68 grams of Fe reacts with 2.88 grams of S? What mass of Fe 2 S 3 is produced when 4.68 grams of Fe reacts with 2.88 grams of S?

3 Step One Look at the problem and figure out how many Stoichiometry problems you need to set up. Look at the problem and figure out how many Stoichiometry problems you need to set up. What mass of Fe 2 S 3 is produced when 4.68 grams of Fe reacts with 2.88 grams of S? What mass of Fe 2 S 3 is produced when 4.68 grams of Fe reacts with 2.88 grams of S? 2 1

4 Step One 1 is wrong because you need to find two answers in this equation because you are solving for Fe and S 1 is wrong because you need to find two answers in this equation because you are solving for Fe and S GO Back

5 Step One Correct the answer is two Correct the answer is two In this problem there is two because it is asking for the mass of Fe 2 S 3 so you need to solve for Iron and Sulfur In this problem there is two because it is asking for the mass of Fe 2 S 3 so you need to solve for Iron and Sulfur

6 Step Two Now you need to set up your problem for both of your problems too find the answers Now you need to set up your problem for both of your problems too find the answers What mass of Fe 2 S 3 is produced when 4.68 grams of Fe reacts with 2.88 grams of S? What mass of Fe 2 S 3 is produced when 4.68 grams of Fe reacts with 2.88 grams of S?

7 Step Two Which one do you think is the right Stoichiometry equation to find the mass of Fe 2 ? Which one do you think is the right Stoichiometry equation to find the mass of Fe 2 ? 4.68Fe x 1molFe x 1mol x 207.9gFe 2 S 3 55.85gFe 2molFe 207.9gFe2S3 x 2mol x 1molFe x 4.68Fe 1molFe 55.85gFe

8 Step Two The second one is wrong because it does not use the right Stoichiometry set up The second one is wrong because it does not use the right Stoichiometry set up The numbers are mixed up and the mole are opposite. The numbers are mixed up and the mole are opposite. Go Back

9 Step Two This answerer is correct it uses all the right equations and formula’s This answerer is correct it uses all the right equations and formula’s This problem is ready to be solved This problem is ready to be solved

10 Step Three Step three all you need to do is solve the problem like a math problem. Step three all you need to do is solve the problem like a math problem. So what you do is you multiply across the numerator and denominator and divide the two numbers So what you do is you multiply across the numerator and denominator and divide the two numbers 4.68Fe x 1molFe x 1mol x 207.9gFe 2 S 3 55.85gFe 2molFe

11 Step Three Use this formula and find out the answerer of how much Fe you would get if you had 4.68 grams of Fe and 2.88 grams of S. Use this formula and find out the answerer of how much Fe you would get if you had 4.68 grams of Fe and 2.88 grams of S. 8.712.459.56 6.99

12 Step Three This answerer is wrong you need to make go back and make sure you did it right This answerer is wrong you need to make go back and make sure you did it right Go back and recheck what you did. Go back and recheck what you did.

13 Step Three 8.71 is correct now all you need to do is to find the limiting factor in the equation. 8.71 is correct now all you need to do is to find the limiting factor in the equation.

14 Step Four Now that you know how to do Stoichiometry problems you can find the second answerer your self just solve for S now. Now that you know how to do Stoichiometry problems you can find the second answerer your self just solve for S now.

15 Step Four What is the limiting factor??? What is the limiting factor??? 6.22 8.88 2.458.71

16 Step Four This is right 6.22 is the limiting reactant because it is smaller than 8.71 This is right 6.22 is the limiting reactant because it is smaller than 8.71 6.22 is your answer now you know Stoichiometry 6.22 is your answer now you know Stoichiometry

17 Step Four This answer is wrong remember the limiting factor is the smaller number This answer is wrong remember the limiting factor is the smaller number


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