1. Physics

2. ELECTROSTATICS - I

3. Session Objectives Charges and their properties Coulomb’s law
Introduction to electric field

4. Electric Charge
Intrinsic property of matter by virtue of which it can (interact) exert force (electric) on other matter having the same intrinsic property
Two types – positive and negative (arbitrarily assigned) - +
SI unit of charge – Coulomb (C)

5. Methods of charging a body
Frictional rubbing
Transfer of electrons from one body to another cause charging
Induction
A charged body induces its opposite charge on the
Nearby side of another body
Conduction
Charge on a body conducts to another

6. Properties of charge - - Like charges repel + + + -
Unlike charges attract
Hair stands out - each strand has the same electric charge and is being repelled from every other strand and her body

7. Properties of charge Additivity Sign should be taken into account
Total charge on a system – the algebraic sum of all charges contained in it. q 3q 4q + = 5q
–7q
–2q + =
Quantisation
Charge cannot be sub-divided indefinitely. The smallest unit of charge is equal to that of an electron I.e. e = 1.6 x 10-19
Conservation
Charge is conserved— Neither created nor destroyed,
Can be just transferred
Other charges – integral multiple of e 2e e
–3e
1.4e
3.5e

8. Solved Example – 1 What kind of charges is produced on each, when
(a) A glass rod is rubbed with silk?
(b) An ebonite rod is rubbed with wool?
Solution:
(a) On glass rod – positive charge
On silk – negative charge
(electrons are transferred from glass to silk)
(b) On ebonite rod – negative charge
On wool – positive charge
(Electrons are transferred from wool to ebonite)

9. Solved Example – 2 From a neutral body, 107 electrons are removed.
Find the charge the body acquires.
Solution:
Charge q = ne
= 107 x 1.6 x 10–19
= 1.6 x 10–12 C
Since the electrons have been removed, the body is positively charged.

10. Coulomb’s Law Force between two charges or charged bodies q1 q2 d
q1q2 > 0 repulsive
q1q2 < 0 attractive
F acts along the line joining the two charges
When SI system is used,
in air / vacuum
Absolute permittivity of vacuum
in a medium of dielectric constant K

11. Coulomb’s Law Vector form Force on q1 by q2 q1 q2 q1q2 < 0

12. Coulomb’s Law Definition of coulomb in vacuum
Put q1 = q2 = 1 C and d = 1 m, then,
One coulomb is that charge, which when placed at 1 m
from an equal and similar charge in vacuum, repels it
with a force of 9×109 N

13. Solved Example - 3 Why is Coulomb’s force a central force? Solution:
Coulomb’s force between two charges always acts along the line joining them and hence, it is a central force.

14. Solved example – 4 Give the dissimilarities between Coulomb’s force
and force of gravitation.
Solution:
Coulomb’s force
Force of gravitation
(i) Force between charges
(ii) Repulsive or attractive
(iii) Not active over large distance
(iv) Affected by the medium between the charges
Force between masses
Always attractive
Active over very large distance
Unaffected by the medium between the bodies

15. Addition of coulomb’s forces
When a test charge is introduced to a system of charges, each of the charges of the system exert electric force on the test charge and the resultant force on it is the vector sum of the individual forces.
Net force on q0 , q0 q1 q2 q3
In general,

16. Solved Example – 5 A charge q is placed at the midpoint of the line
joining two identical charges Q. What should be the value of q if this system of three charges is to be in equilibrium?
Solution:
For equilibrium, Q q
2 x

17. Continuous charge distribution
Does not mean that charge is continuous, but distribution of discrete charges is continuous
A system of closely spaced charges form a continuous charge distribution
Charge distribution
Linear charge
distribution
Surface charge
distribution
Volume distribution
of charge
Force on q0

18. Electric field (intro.)
A charge creates a physical condition in the space surrounding itself called the electric field such that, any other charge present in that space experience electric force.
No boundary, but strength considerably decreases away from the charge responsible for that.
Intensity of field at a point – Force on unit positive charge placed at that point.
A vector represented by
SI unit: N C–1
At a point, where strength of the filed is E,
a charge q experiences a force
of magnitude F = q E

19. Solved Example – 7
If an oil drop of weight 3.2 x 10–13 N is balanced in an electric field of 5 x 105 N C–1, then find the
charge on the oil drop.
Solution:
W = 3.2×10–13 N, E = 5×105 N C–1
W = q E

20. Thank you