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The Volume of the Classroom Answer from Bucharest.

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Presentation on theme: "The Volume of the Classroom Answer from Bucharest."— Presentation transcript:

1 The Volume of the Classroom Answer from Bucharest

2 Description This is what Marius wrote: “All the corners of our classroom have right angles, so we can call it a big cuboid (not as big as the French one, as we’ll see later). As we measured it, we noticed that there are several beams: 3 on the ceiling, 3 on the widow wall, 3 on the opposite wall and a narrow one in a corner. The volume of the beams must be subtracted from the volume of the classroom. Fotunately, they all are shaped as cuboids, so we only need to use one formula: the volume is length by width by height.”

3 3D model These are the 3D models made by Justinian. He used a tool called Google SketchUp.

4 3D model

5 Dimensions Anca and Cristina were in charge with measuring the classroom. Here are the measurements they have taken: Room: l=8,1m, w=6,32 m, h=2,75 m Beam no. 1 (the small one): l=19 cm, w=14 cm, h=2,75 m Beam no. 2 (the horizontal one ones): w=30 cm, h=15,5 cm, l=the width of the room- 2 times the length of beam no.3 Beam no. 3 (the vertical ones): l=29,5 cm, w=35 cm, h=2,75 m We decided to calculate the volume of the air like this: V=V class -(V 1 +3V 2 +6V 3 )

6 At work

7 Results After using the formula for each volume, this is what we obtained: V class =140,778 m 3 V 1 =0,073 m 3 V 2 =0,261 m 3 V 3 =0,284 m 3 V= 140,778-(0,073+3x0,261+6x0,284)=138,218 m 3 The weight of the air is 179,683 kg

8 Thank you and good-bye!


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