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Limits and an Introduction to Calculus

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1 Limits and an Introduction to Calculus
12 Limits and an Introduction to Calculus Copyright © Cengage Learning. All rights reserved.

2 Copyright © Cengage Learning. All rights reserved.
Techniques for Evaluating Limits 12.2 Copyright © Cengage Learning. All rights reserved.

3 Objectives Use the dividing out technique to evaluate limits of functions. Use the rationalizing technique to evaluate limits of functions. Approximate limits of functions graphically and numerically. Evaluate one-sided limits of functions. Evaluate limits from calculus.

4 Dividing Out Technique

5 Dividing Out Technique
You studied several types of functions whose limits can be evaluated by direct substitution. In this section, you will study several techniques for evaluating limits of functions for which direct substitution fails.

6 Dividing Out Technique
Suppose you want to find the following limit. Direct substitution produces 0 in both the numerator and denominator. (–3)2 + (–3) – 6 = 0 –3 + 3 = 0 The resulting fraction, , has no meaning as a real number. It is called an indeterminate form because you cannot, from the form alone, determine the limit. Numerator is 0 when x = –3. Denominator is 0 when x = –3.

7 Dividing Out Technique
By using a table, however, it appears that the limit of the function as x  –3 is –5. When you try to evaluate a limit of a rational function by direct substitution and encounter the indeterminate form , you can conclude that the numerator and denominator must have a common factor.

8 Dividing Out Technique
After factoring and dividing out, you should try direct substitution again. Example 1 shows how you can use the dividing out technique to evaluate limits of these types of functions.

9 Example 1 – Dividing Out Technique
Find the limit: Solution: From the discussion above, you know that direct substitution fails. So, begin by factoring the numerator and dividing out any common factors. Factor numerator.

10 Example 1 – Solution cont’d Divide out common factor and simplify.
Direct substitution

11 Rationalizing Technique

12 Rationalizing Technique
A way to find the limits of some functions is to first rationalize the numerator of the function. This is called the rationalizing technique. Recall that rationalizing the numerator means multiplying the numerator and denominator by the conjugate of the numerator. For instance, the conjugate of is

13 Example 3 – Rationalizing Technique
Find the limit: Solution: By direct substitution, you obtain the indeterminate form . Indeterminate form

14 Example 3 – Solution cont’d In this case, rewrite the fraction by rationalizing the numerator. Multiply. Simplify. Divide out common factor.

15 Example 3 – Solution Now, evaluate the limit by direct substitution.
cont’d Now, evaluate the limit by direct substitution. Simplify.

16 Example 3 – Solution cont’d To reinforce your conclusion that the limit is , construct a table, as shown below, or by sketch a graph, as shown in Figure 12.8. Figure 12.8

17 Using Technology

18 Using Technology The dividing out and rationalizing techniques may not work for finding limits of nonalgebraic functions. You often need to use more sophisticated analytic techniques to find limits of these types of functions.

19 Example 4 – Approximating a Limit
Approximate the limit: Solution: Let f (x) = (1 + x)1/x. you can use the table feature of a graphing utility to create a table that shows the values of f for x starting at x = –0.003 and has a step of 0.001, as shown in below.

20 Example 4 – Solution cont’d Because 0 is halfway between –0.001 and 0.001, use the average of the values of f at these two x-coordinates to estimate the limit, as follows. The actual limit can be found algebraically to be e 

21 One-Sided Limits

22 One-Sided Limits You know that one way in which a limit can fail to exist is when a function approaches a different value from the left side of c than it approaches from the right side of c. This type of behavior can be described more concisely with the concept of a one-sided limit.

23 Example 6 – Evaluating One-Sided Limits
Find the limit as x  0 from the left and the limit as x  0 from the right for Solution: From the graph of f, shown to right, you can see that f (x) = –2 for all x < 0.

24 Example 6 – Solution cont’d So, the limit from the left is Because f (x) = 2 for all x > 0, the limit from the right is Limit from the left: f (x)  –2 as x  0– Limit from the right: f (x)  2 as x  0+

25 One-Sided Limits In Example 6, note that the function approaches different limits from the left and from the right. In such cases, the limit of f (x) as x  c does not exist. For the limit of a function to exist as x  c, it must be true that both one-sided limits exist and are equal.

26 Limits from Calculus

27 A Limit from Calculus You will study an important type of limit from calculus—the limit of a difference quotient.

28 Example 9 – Evaluating a Limit from Calculus
For the function f (x) = x2 – 1, find Solution: Begin by substituting for f (3 + h) and f (3) and simplifying.

29 Example 9 – Solution cont’d By factoring and dividing out, you obtain the following. So, the limit is 6.

30 A Limit from Calculus Note that for any x-value, the limit of a difference quotient is an expression of the form Direct substitution into the difference quotient always produces the indeterminate form . For instance,


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