1 Molarity. 2 Review of Converstions Fractions that = 1 Different units and numbers that equal each other Example: 1 in. = 2.54 cm Factors: 1 in. OR 2.54.

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1 Molarity

2 Review of Converstions Fractions that = 1 Different units and numbers that equal each other Example: 1 in. = 2.54 cm Factors: 1 in. OR 2.54 cm 2.54 cm 1 in

3 How many Liters are in 8,392 milliliters? Conversion factor 8,392 ml X 1 L = 8.392 L 1,000 ml 1,000 ml

4 What is the number of moles in 20.0 grams of NaOH? Use a conversion factor. Converting Grams To Moles

5 Molar mass of NaOH Na = 23.0 + 1 O =16.0 + 1 H = 1.0 total = 40.0 grams in 1 mole 2. Conversion factor 40.0 g 1 mole 3. Setup 20.0 g x 1 mole = 20.0 = 0.50 moles 40.0 g 40.0 Converting Grams To Moles

6 What is the number of moles in 185 grams of CCl 4 ? Use a conversion factor. Converting Grams To Moles

7 Molar mass of CCl 4 C = 12.0 + 4 Cl =142.0 total = 154.0 grams in 1 mole 2. Conversion factor 154.0 g 1 mole 3. Setup 185 g x 1 mole = 185 = 1.2 moles 154.0 g 154.0 Converting Grams To Moles

8 Concentration of Solutions Mass Percentage = Mass of Solute Total Mass of Solution. (Water + Solute) Molarity (M) = Moles of Solute Liters of Solution 1000 ml = 1 Liter

9 Steps to Finding Molarity 1. First convert grams of solute into moles. 2. Convert volume to Liters of solution. 3. Divide Moles of Solute by Liters of Solution.

10 What is the Molarity of 20.0 grams of Ca(OH) 2 dissolved into 250 ml of solution? Use a conversion factor to find moles. Practice

11 Molar mass of Ca(OH) 2 Ca = 40.1 +2 O =32.0 + 2 H = 2.0 total = 74.0 grams in 1 mole 2. Setup 20.0 g x 1 mole = 20.0 = 0.27 moles 74.0 g 74.0 3. Volume = 250 ml x 1 Liter = 0.25 L 1,000 ml 4. Molarity = 0.27 moles = 1.08 or 1.1 0.25 L Molarity of 20.0 g Ca(OH) 2 in 250 ml solution

12 What is the molarity of 185 grams of CrCl 4 dissolved into 500 ml of solution? Use a conversion factor. Calculate the Molarity

13 Molar mass of CCl 4 Cr = 52.0 + 4 Cl =142.0 total = 194.0 grams in 1 mole 2. Setup 185 g x 1 mole = 185 = 0.95 moles 194.0 g 194.0 3. Volume 500 ml x 1 Liter = 0.5 Liter 1,000 ml 4. Molarity = 0.95 moles = 1.9 M 0.500 L Calculate the Molarity of 185 g of CrCl 4 in 500 ml of solution

14 THE END – GOOD BYE!

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