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Simplifying Radicals Definitely radical, debatably simple.

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Presentation on theme: "Simplifying Radicals Definitely radical, debatably simple."— Presentation transcript:

1 Simplifying Radicals Definitely radical, debatably simple.

2 Simplifying Radicals So What is a Radical…? A Radical is nothing more than a square root sign EXAMPLES: The expression is read as “radical 20” and The expression is read as “ 5 radical 3.

3 Simplifying Radicals There are some radicals easy to simplify… For Example: and Other radicals take more work… Like: and … neither has an easy answer, but both can be simplified

4 Simplifying Radicals So how do we simplify and … ? Let’s start with. Check with a calculator: and Now let’s try.

5 Simplifying Radicals So what are the rules? What steps can I follow? Step 1: Either know or have a list of your perfect squares present. 4,9,16,25,36,49,64,81,100… These are the numbers that have nice sqrts. Step 2: Determine if any of the square roots divide into your radical evenly. Let’s try : 50/4 =12.5 50/9 = 5.555 50/16 = 3.125 50/25 = 2 So 50 = 25 x 2

6 Simplifying Radicals Step 3: Rewrite the radical as the product of two parts. Step 4: Replace the radical that has a perfect square root with a regular number. The answer is read “5 times the square root of 2” or “5 radical 2”

7 Simplifying Radicals The are other ways to simplify as well… Sometimes we can just use multiplication and division. For Example: and There are also some radicals that cannot be simplified… cannot be broken into two parts.

8 Simplifying Radicals There is one final method of simplification that we must consider. We are allowed to multiply two radicals or divide two radicals, BUT you cannot divide a regular number by a radical. Example: So what to we do… ?

9 Simplifying Radicals We have to “rationalize the denominator”… Step 1: Multiply the top and bottom of the fraction by the bottom. Step 2: Simplify Step 1 These =

10 Simplifying Radicals Let’s try two problems…

11 Simplifying Radicals HW: P 355 (1-23 odd) Work on this assignment in pairs for the remainder of class.


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