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Kinematics in 2-D Concept Map

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Presentation on theme: "Kinematics in 2-D Concept Map"— Presentation transcript:

1 Kinematics in 2-D Concept Map
Physics Previous content New content Studies Math Skills Vectors and Described by Motion Can be Can be Described by Constant Velocity Constant Acceleration Kinematic Equations The concept map of vectors and kinematics in two dimensions is shown here. Also apply in May occur in 2 Dimensions

2 Projectile Motion A projectile is any object moving through the air or space that is only acted on by gravity. A projectile is any object moving through the air or space that is only acted on by gravity.

3 Projectile Examples A projectile could take many forms: A cannon ball
A high jumping athlete A ball thrown through the air A projectile could take many forms: A cannon ball A high jumping athlete A ball thrown through the air

4 Classic Projectile Question
A ball is dropped vertically, and one is launched horizontally, each from the same height. Which one hits the ground first? v A ball is dropped vertically, and one is launched horizontally, each from the same height. Which one hits the ground first? Same time! Same time!

5 Why does it work this way?
The Explanation Why does it work this way? They both hit at the same time because they both fall the same vertical distance. Although the thrown one has an additional horizontal velocity, that doesn’t affect its vertical motion. Breaking an objects motion into horizontal and vertical components is very useful!! They both hit at the same time because they both fall the same vertical distance. Although the thrown one has an additional horizontal velocity, that doesn’t affect its vertical motion. Breaking an objects motion into horizontal and vertical components is very useful!!

6 Further Explanation In the vertical direction, both the balls experience the usual acceleration from gravity. Notice the increasing falling distance and speed in the vertical direction. In the horizontal direction, the projected ball has a constant velocity. Thus, it covers regular, consistent horizontal distances. In the vertical direction, both the balls experience the usual acceleration from gravity. Notice the increasing falling distance and speed in the vertical direction. In the horizontal direction, the projected ball has a constant velocity. Thus, it covers regular, consistent horizontal distances.

7 Thought Question: At the same time that a high speed bullet is fired horizontally from a rifle, another bullet is simply dropped from the same height. Which bullet strikes the ground first? Bullet to be dropped Horizontal line of sight At the same time that a high speed bullet is fired horizontally from a rifle, another bullet is simply dropped from the same height. Which bullet strikes the ground first? If we could see far downrange, we would notice that they both hit at the same time! If we could see far downrange, we would notice that they both hit at the same time!

8 Thought Question Explanation
Why does it work this way? Both fall the same vertical distance, and are accelerated the same by gravity, thus the times would be equal. The fired bullet simply has a very large extra horizontal component. This is usually never observed since it would require a large flat open area. Both fall the same vertical distance, and are accelerated the same by gravity, thus the times would be equal. The fired bullet simply has a very large extra horizontal component. This is usually never observed since it would require a large flat open area.

9 The Monkey and the Hunter
A big game hunter spots a monkey in the tree and aims directly at him. If the monkey releases the branch exactly as the hunter fires the bullet, approximately where will the bullet land? Line of sight Hit! A big game hunter spots a monkey in the tree and aims directly at him. If the monkey releases the branch exactly as the hunter fires the bullet, approximately where will the bullet land?

10 Monkey Explanation You might think the bullet would go above the monkey since he is falling. Since they are in the air for the same amount of time, the bullet hits the target! However, the bullet is falling with the same vertical acceleration too. You might think the bullet would go above the monkey since he is falling. However, the bullet is falling with the same vertical acceleration too. Since they are in the air for the same amount of time, the bullet hits the target!

11 Formulas There are no new mathematical formulas for this tutorial topic. However, all the old formulas from motion in 1 dimension still apply. There are no new mathematical formulas for this tutorial topic. However, all the old formulas from motion in 1 dimension still apply.

12 Projectile Example A cannon fires a ball from the top of a 50m high cliff. The projectile is fired at 100m/s. How far away from the base of the cliff will it land? 100 m/s 50m A cannon fires a ball from the top of a 50m high cliff. The projectile is fired at 100m/s. How far away from the base of the cliff will it land?

13 “v” refers to the vertical direction
Projectile Solution When only the vertical direction is considered: Its initial vertical velocity is 0 m/s The distance is -50 m (negative refers to down) Its acceleration is -9.8 m/s2 The time in the air, t, is unknown. We can use one of the previous kinematic formulas. When only the vertical direction is considered: Its initial vertical velocity is 0 m/s The distance is -50 m (negative refers to down) Its acceleration is -9.8 m/s2 The time in the air, t, is unknown. We can use one of the previous kinematic formulas. “v” refers to the vertical direction

14 Mathematics of Solution
Since vi =0m/s, that term drops out. Time isn’t the final answer, but it will lead us to the distance. Notice algebraic steps in solution. The initial velocity term drops out. This time value will lead us to the value for the distance traveled.

15 Obtaining the Horizontal Distance
When only the horizontal motion of the projectile is considered: Since gravity acts only vertically, there is 0 acceleration. Horizontally, the projectile moves with a constant speed. We can use one of the previous kinematic formulas When only the horizontal motion of the projectile is considered: Since gravity acts only vertically, there is 0 acceleration. Horizontally, the projectile moves with a constant speed. We can use one of the previous kinematic formulas Constant horizontal velocity.

16 More Mathematics of Solution
Don’t confuse this distance with the vertical distance previously used. Notice that the vertical distance and velocity are used here. Measured from the base of the cliff.

17 Projectiles at an Angle
Again a projectile is fired at 100 m/s. This time there is no cliff, but the barrel is elevated at 30° with the ground. How far away will this projectile land? V=100m/s Again a projectile is fired at 100 m/s. This time there is no cliff, but the barrel is elevated at 30° with the ground. How far away will this projectile land? 30o

18 Separate into Components
Resolve the diagonal motion of the cannonball into horizontal and vertical components. These separate components will be used when motion in only 1 direction is addressed. V=100m/s Resolve the diagonal motion of the cannonball into horizontal and vertical components. These separate components will be used when motion in only 1 direction is addressed. 30o

19 Calculation of Components
Consider the cannonball velocity and its components like the sides of a right triangle. Simple trig functions can be used to calculate all components. Opposite side V=100m/s 100m/s hypotenuse Consider the cannonball velocity and its components like the sides of a right triangle. Simple trig functions can be used to calculate all components. 30o Adjacent side

20 Component Values Vertical component: Horizontal component:
Using the definition of sine and cosine, calculate the vertical and horizontal components.

21 Calculating Time in Air
We now know that the cannonball initially moves upwards at 50m/s. (vertical component) Thus, it will be moving downward at -50 m/s when it returns to the Earth. Next, use our old acceleration definition. We now know that the cannonball initially moves upwards at 50m/s. (vertical component) Thus, it will be moving downward at -50 m/s when it returns to the Earth. Next, use our old acceleration definition.

22 Calculating Distance Traveled
Finally, since we still have a constant horizontal velocity, we can use our old constant velocity formula again. Notice the horizontal component is used here. Finally, since we still have a constant horizontal velocity, we can use our old constant velocity formula again. Be sure to use the horizontal velocity and distance here.

23 Launches at Various Angles
Notice how two angles yield the same horizontal distance. These are complimentary angles; they add up to 90°. Horizontal distance Vertical distance The larger angle of each pair simply puts the projectile higher into the air and for a longer time. Notice how two angles yield the same horizontal distance. These are complimentary angles; they add up to 90°. The larger angle of each pair simply puts the projectile higher into the air and for a longer time. Without air resistance, an angle of 45° will yield the maximum range. Without air resistance, an angle of 45° will yield the maximum range.

24 Summary Continue to use old kinematics formulas.
Use the appropriate component when describing motion in a certain direction. For projectiles, the horizontal motion has zero acceleration. Split vectors into components using mathematics. (trigonometry) For projectiles, the vertical motion is accelerated due to gravity. Vectors have magnitude and direction. Scalars have magnitude only. Add vectors tip to tail. The resultant is the sum of two vectors. Split vectors into components using mathematics. (trigonometry) Use the appropriate component when describing motion in a certain direction. Use old kinematics formulas.

25 Assignment Page 78 Problems #21,22,24


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