Presentation on theme: "Projectile Motion Neglecting air resistance, what happens when you throw a ball up from the back of a moving truck? Front? Behind? In?"— Presentation transcript:
1Projectile MotionNeglecting air resistance, what happens when you throw a ball up from the back of a moving truck?Front?Behind?In?
2Curved Motion Projectile Motion motion of an object that is projected into the earth’s gravitational pull.A projectile will follow the curved path of a parabola, so sometimes it is called parabolic motion.Curved motion is produced by a constant horizontal velocity coupled with an vertical velocity that is accelerating (due to gravity).The affects of air resistance are neglected in order to account for constant horizontal velocity.
3An object is thrown from a height of 44 An object is thrown from a height of 44.1 m with a horizontal speed of 35.0 m/s. (It will hit in 3 s.)Horizontally:vertically35 m35 m35 m4.9 m14.7 m24.5 m
9Aim at monkey with gravity, but using a smaller muzzle velocity:
10Tips for solving Projectile Motion Problems Remember that the curved motion is because the object is moving at a constant rate across while it accelerates due to gravity!The time the object is in the air is independent of the horizontal velocity!How far it falls (or rises) depends upon the vertical components: velocity and the height!
11A man throws a ball off of a tower that is 35 A man throws a ball off of a tower that is 35.0 m tall with a horizontal velocity of 45.0 m/s. How far from the base of the tower will the ball hit?Horizontally:∆d = vh∆t= (45.0 m/s)(2.67 s)vh = 45.0 m/s= 121 m∆ d = ?2∆daVertically:∆t =v0 = 0a = g =-9.80 m/s2=2(-35.0 m)-9.80 m/s2∆h = m= 2.67 s∆t = ?
12Sparky the human cannonball sets his cannon so that it will launch him with a velocity of 25.0 m/s at an angle of 35.0˚ with the horizontal. The ceiling of the arena is 10.0 m above his launch point. How far away should he place his landing net? Will Sparky need that net (will he clear the ceiling?)Horizontally:vh = (cos 35.0˚)(25.0 m/s)25.0 m/s= 20.5 m/svvVertically:35.0˚vv = (sin 35.0˚)(25.0 m/s)vh= 14.3 m/s
14But does he clear the ceiling? Vertically Upward:∆d = v0∆t + .5a∆t2∆t = .5(2.92 s) = 1.46 sv0 = 14.3 m/s= (14.3 m/s)(1.46 s)+ .5(-9.80m/s2)(1.46 s)2v0 = 0a = g = m/s2∆d = ?= mTo land, he would have to rise 10.4 m, but the ceiling is only 10.0 m!He will not make it!
15A) What are the components of a projectile that is fired at 35 A) What are the components of a projectile that is fired at ˚?B) What would be the minimum speed of the projectile mentioned previously?C) A man throws a baseball off of a roof at the exact same time he drops a rock off of the same roof. Which one hits the ground first? Do they have the same speed when they hit the ground?D) In order to hit a monkey hanging from a tree, should a hunter aim (his banana gun)at the monkey, above the monkey, or below the monkey? Assume the monkey will just sit in the tree like a dope.
161) A plane flying horizontally at 352 m/s wants to drop a package so that it lands exactly 1250 m horizontally away from the drop point. At what height should the pilot fly in order to accomplish this?2) A cannonball is launched with a velocity of 50.0 m/s at an angle of 40.0˚ with the horizontal. What is the range (the farthest horizontal distance) of the cannonball and to what height will it rise?
173) A man throws a baseball horizontally off of the top of a 45 3) A man throws a baseball horizontally off of the top of a 45.5 m tower and it lands 89.5 m away from the base of the tower. With what velocity did the man throw the ball?4) A cannonball is fired in such a way that its range (the total horizontal distance traveled) is 325 m and the maximum height it reaches is 65.0 m. What must have been the magnitude and direction of the cannonball’s velocity at its launch?