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Explorations in Artificial Intelligence Prof. Carla P. Gomes Module 3 Logic Representations (Part 2)

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Presentation on theme: "Explorations in Artificial Intelligence Prof. Carla P. Gomes Module 3 Logic Representations (Part 2)"— Presentation transcript:

1 Explorations in Artificial Intelligence Prof. Carla P. Gomes gomes@cs.cornell.edu Module 3 Logic Representations (Part 2)

2 Satisfiability

3 Propositional Satisfiability problem Satifiability (SAT): Given a formula in propositional calculus, is there a model (i.e., a satisfying interpretation, an assignment to its variables) making it true? We consider clausal form, e.g.: ( a   b   c ) AND ( b   c) AND ( a  c) possible assignments SAT: prototypical hard combinatorial search and reasoning problem. Problem is NP-Complete. (Cook 1971) Surprising “power” of SAT for encoding computational problems.

4 Effective propositional inference Two families of algorithms for propositional inference (checking satisfiability) based on model checking (which are quite effective in practice): Complete backtracking search algorithms DPLL algorithm (Davis, Putnam, Logemann, Loveland) Incomplete local search algorithms –WalkSAT algorithm

5 The DPLL algorithm Determine if an input propositional logic sentence (in CNF) is satisfiable. Improvements over truth table enumeration: 1.Early termination A clause is true if any literal is true. A sentence is false if any clause is false. 2.Pure symbol heuristic Pure symbol: always appears with the same "sign" in all clauses. e.g., In the three clauses (A   B), (  B   C), (C  A), A and B are pure, C is impure. Make a pure symbol literal true. 3.Unit clause heuristic Unit clause: only one literal in the clause The only literal in a unit clause must be true.

6 The DPLL algorithm

7 The WalkSAT algorithm Incomplete, local search algorithm Evaluation function: The min-conflict heuristic of minimizing the number of unsatisfied clauses Balance between greediness and randomness

8 The WalkSAT algorithm

9 Hard satisfiability problems Consider random 3-CNF sentences. e.g., (  D   B  C)  (B   A   C)  (  C   B  E)  (E   D  B)  (B  E   C) m = number of clauses n = number of symbols –Hard problems seem to cluster near m/n = 4.3 (critical point)

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11 Intuition At low ratios: –few clauses (constraints) –many assignments –easily found At high ratios: –many clauses –inconsistencies easily detected

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13 Satisfiability as an Encoding Language

14 Encoding Latin Square Problems in Propositional Logic Variables: Each variables represents a color assigned to a cell. Clauses: Some color must be assigned to each cell (clause of length n); No color is repeated in the same row (sets of negative binary clauses); No color is repeated in the same column (sets of negative binary clauses);

15 3D Encoding or Full Encoding This encoding is based on the cubic representation of the quasigroup: each line of the cube contains exactly one true variable; Variables: Same as 2D encoding. Clauses: Same as the 2 D encoding plus: –Each color must appear at least once in each row; –Each color must appear at least once in each column; –No two colors are assigned to the same cell;

16 Dimacs format At the top of the file is a simple header. p cnf Each variable should be assigned an integer index. Start at 1, as 0 is used to indicate the end of a clause. The positive integer a positive literal, whereas a negative interger represents a negative literal. Example -1 7 0  (  x1  x7)

17 Extended Latin Square 2x2 p cnf 8 24 -1 -2 0 -3 -4 0 -5 -6 0 -7 -8 0 -1 -5 0 -2 -6 0 -3 -7 0 -4 -8 0 -1 -3 0 -2 -4 0 -5 -7 0 -6 -8 0 1 2 0 3 4 0 5 6 0 7 8 0 1 5 0 2 6 0 3 7 0 4 8 0 1 3 0 2 4 0 5 7 0 6 8 0 order 2 -1 -1 1/2 3/4 5/6 7/8 A cell gets at most a colorNo repetition of color in a column No repetition of color in a rowA cell gets a color A given color goes in each column A given color goes in each row 1 – cell 11 is red 2 – cell 11 is green 3 – cell 12 is red 4 – cell 12 is green 5 – cell 21 is red 6 – cell 21 is green 7 – cell 22 is red 8 – cell 22 is green


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