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Algebra 1(A/B) Fall 2012.  Class Announcements  Homework Check  Warm-Up  4.3 Notes  Begin Homework.

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Presentation on theme: "Algebra 1(A/B) Fall 2012.  Class Announcements  Homework Check  Warm-Up  4.3 Notes  Begin Homework."— Presentation transcript:

1 Algebra 1(A/B) Fall 2012

2  Class Announcements  Homework Check  Warm-Up  4.3 Notes  Begin Homework

3  Compare your answers with the person next to you. This is not chat time!  Ask about questions that you are not sure about.  Correct those questions in class.  Study from those questions!

4  Look at the ordered pair on your desk.  This ordered pair represents your location on a coordinate plane.  Stand up if your point matches the following descriptions.  You will need scratch paper!

5 you are in Quadrant III.

6 you are on the x-axis.

7 you are in Quadrant I.

8 you are the origin.

9 you are in Quadrant IV.

10 you are on the y-axis.

11 you are in Quadrant II.

12 you are a solution to the equation 3y = 3x + 3. (0, 1), (-1, 0), (-2, -1), and (-3, -2)

13 you are on the line y = -2.

14 you are a solution to the equation 4x + 2y = 6. (1, 1) and (2, -1)

15 you are on the line y = 1.

16 you are a solution to the equation 6y = -12 + 6x. (0, -2), (1, -1), (2, 0), and (3, 1)

17 you are on the line x = -4.

18 Objectives:  Find the intercepts of a graph of a linear equation.

19 1 2 3 5 6 4 7 -6 -2 -4 12 34567 -6 -4-2 y = 4

20 1 2 3 5 6 4 7 -6 -2 -4 12 34567 -6 -4-2 x = -6

21 1 2 3 5 6 4 7 -6 -2 -4 12 34567 -6 -4-2 y = -1

22 1 2 3 5 6 4 7 -6 -2 -4 12 34567 -6 -4-2 x = 2

23 1 2 3 5 6 4 7 -6 -2 -4 12 34567 -6 -4-2 y = 0

24 We need at least two points to determine a line.

25 1 2 3 5 6 4 7 -6 -2 -4 12 34567 -6 -4-2

26 x-intercept – the point where a line or curve crosses the x-axis. This is always written as (x, 0). y-intercept – the point where a line or curve crosses the y-axis. This is always written as (0, y).

27 1 2 3 5 6 4 7 -6 -2 -4 12 34567 -6 -4-2 x-intercept? y-intercept? (0, 3) y = 3 (2, 0) x = 2

28 1 2 3 5 6 4 7 -6 -2 -4 12 34567 -6 -4-2 x-intercept? y-intercept? (0, -3) y = -3 (6, 0) x = 6

29  Use this time to relax or try the following rebus puzzles. All over againYou are up in arms over it

30

31  x-intercept by setting y = 0  y-intercept by setting x = 0

32  To find the x-intercept, set y = 0 and solve for x.  To find the y-intercept, set x = 0 and solve for y. 2x + 3y = 6

33 1 2 3 5 6 4 7 -6 -2 -4 12 34567 -6 -4-2 (3, 0) and (0, 2)

34 1 2 3 5 6 4 7 -6 -2 -4 12 34567 -6 -4-2 2x – y = 4

35 1 2 3 5 6 4 7 -6 -2 -4 12 34567 -6 -4-2 y – 2x = 3

36 1 2 3 5 6 4 7 -6 -2 -4 12 34567 -6 -4-2 y = 2x + 4

37 1 2 3 5 6 4 7 -6 -2 -4 12 34567 -6 -4-2 2y – 3 = 5 Variable x does not show up  no x- intercept!

38 1 2 3 5 6 4 7 -6 -2 -4 12 34567 -6 -4-2

39 1 2 3 5 6 4 7 -6 -2 -4 12 34567 -6 -4-2

40 1. The x-intercept and y-intercept are the points at which a line or curve cross the x and y-axis, respectively. 2. To find the x-intercept, set y = 0. 3. To find the y-intercept, set x = 0. 4. We can graph a line by connecting the two intercepts. Homework: pgs. 221-222 #14-19, 26-28, 35-37, 44-46


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