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5-minute check 50.26 in. 12.3 SURFACE AREA OF PYRAMIDS AND CONES May 3, 2013.

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Presentation on theme: "5-minute check 50.26 in. 12.3 SURFACE AREA OF PYRAMIDS AND CONES May 3, 2013."— Presentation transcript:

1 5-minute check 50.26 in

2 12.3 SURFACE AREA OF PYRAMIDS AND CONES May 3, 2013

3 12.3 Objective(s) Students will find surface areas of pyramids and cones. Why? So you can find the surface area of a volcano, as seen in Ex 33. Mastery is 80% or better on 5-minute checks and practice problems.

4 Concept Dev-Finding the surface area of a pyramid A pyramid is a polyhedron in which the base is a polygon and the lateral faces are triangles with a common vertex. The intersection of two lateral faces is a lateral edge. The intersection of the base and a lateral face is a base edge. The altitude or height of a pyramid is the perpendicular distance between the base and the vertex.

5 More on pyramids A regular pyramid has a regular polygon for a base and its height meets the base at its center. The slant height of a regular pyramid is the altitude of any lateral face. A nonregular pyramid does not have a slant height.

6 Pyramid Arena

7 Ex. 1: Finding the Area of a Lateral Face Architecture. The lateral faces of the Pyramid Arena in Memphis, Tennessee, are covered with steal panels. Use the diagram of the arena to find the area of each lateral face of this regular pyramid.

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9 Hexagonal Pyramids A regular hexagonal pyramid and its net are shown at the right. Let b represent the length of a base edge, and let l represent the slant height of the pyramid. The area of each lateral face is 1/2b l and the perimeter of the base if P = 6b. So the surface area is as follows:

10 Hexagonal Pyramid S = (Area of base) + 6(Area of lateral face) S = B + 6( ½ b l ) S = B + (6b) l S = B + P l Substitute Rewrite 6( ½ b l ) as ½ (6b) l. Substitute P for 6b Surface Area of a Regular Pyramid The surface area S of a regular pyramid is: S = B + ½ P l, where B is the area of the base, P is the perimeter of the base, and l is the slant height.

11 Ex. 2: Finding the surface area of a pyramid To find the surface area of the regular pyramid shown, start by finding the area of the base. Use the formula for the area of a regular polygon, ½ (apothem)(perimeter). A diagram of the base is shown to the right.

12 Ex. 2: Finding the surface area of a pyramid After substituting, the area of the base is ½ (3 )(6 6), or 54 square meters.

13 Surface area Now you can find the surface area by using 54 for the area of the base, B.

14 Think….Ink….Share Find the surface area of pyramid with a base edge of 40ft and a height of 21ft. Remember the formula S= B + 1/2Pl Answer 580 square feet per Lateral Face 1600 + 580*4 = 3920 sq ft

15 Part 1 HW Page 814 #1-9 all

16 Finding the Surface Area of a Cone A circular cone, or cone, has a circular base and a vertex that is NOT in the same plane as the base. The altitude, or height, is the perpendicular distance between the vertex and the base. In a right cone, the height meets the base at its center and the slant height is the distance between the vertex and a point on the base edge.

17 Finding the Surface Area of a Cone The lateral surface of a cone consists of all segments that connect the vertex with points on the base edge. When you cut along the slant height and like the cone flat, you get the net shown at the right. In the net, the circular base has an area of  r 2 and the lateral surface area is the sector of a circle.

18 More on cones... You can find the area of this sector by using a proportion, as shown below. Area of sector Area of circle = Arc length Circumference Set up proportion Area of sector l2l2 = 2r2r 2l2l Substitute Area of sector =  l 2 2r2r 2l2l Multiply each side by  l 2 Area of sector =  r l Simplify  The surface area of a cone is the sum of the base area and the lateral area,  r l.

19 Theorem Surface Area of a Right Cone The surface area of a right cone is S =  r 2 +  r l, where r is the radius of the base and l is the slant height

20 Ex. 3: Finding the surface area of a cone To find the surface area of the right cone shown, use the formula for the surface area. S =  r 2 +  r l Write formula S =  4 2 +  (4)(6) Substitute S = 16  + 24  Simplify S = 40  Simplify  The surface area is 40  square inches or about 125.7 square inches.

21 Think….Ink….Share Find the surface area of a cone with a radius of 6m and a height of 8m. Answer 96  m 2

22 ExIt slips What was the objective for today? Students will find surface areas of pyramids and cones. Why? So you can find the surface area of a volcano, as seen in Ex 33. Mastery is 80% or better on 5-minute checks and practice problems.

23 Home work Page 814-815 # 10-24 TODO….ALL


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