2. Stoichiometry Mrs. Russotto

3. Best Ever Chewy Chocolate Chunk Cookies INGREDIENTS: 1/2 cup butter, softened 1/3 cup chocolate syrup 1 cup packed brown sugar 1/2 cup white sugar 2 eggs 2 tablespoons corn syrup 2 teaspoons vanilla extract 2 1/2 cups all-purpose flour 1 teaspoon baking soda 1/2 teaspoon salt 1 (11.5 ounce) package semi-sweet chocolate chunks Recipe makes 3 dozen cookies. DIRECTIONS: Preheat the oven to 375 degrees F (190 degrees C). In a medium bowl, cream together the butter, chocolate syrup, brown sugar and white sugar until smooth. Beat in the eggs, one at a time, then stir in the corn syrup and vanilla. Combine the flour, baking soda and salt; stir into the creamed mixture until just blended. Mix in the chocolate chunks by hand. Drop cookies by 1/4 cupfuls onto ungreased cookie sheets. Bake for 12 to 14 minutes in the preheated oven. Allow cookies to cool on baking sheet for 5 minutes before removing to a wire rack to cool completely.

4. What would happen if I wanted to make six dozen cookies, and the recipe only called to make three dozen cookies? What would I have to do? What if I had two packages of semi- sweet chocolate chunks and wanted to use them both. How many cookies could I make?

5. For You… Bacon Double Cheeseburger Recipe –1 hamburger bun –2 hamburger patties –2 slices of cheese –4 stripes of bacon If I have 5 bacon double cheeseburgers: –How may hamburger buns do I have? –How many strips of bacon do I have?

6. Bacon Double Cheeseburger Recipe –1 hamburger bun –2 hamburger patties –2 slices of cheese –4 stripes of bacon How many bacon double cheeseburgers can you make if you start with: –2 buns, 4 patties, 4 slices of cheese, 8 strips of bacon –1 dozen buns, 2 dozen patties, 2 dozen slices of cheese, 4 dozen strips of bacon –1 mole buns, 2 moles patties, 2 moles slices of cheese, 4 moles strips of bacon

7. Chemical Stoichiometry Stoichiometry - The study of quantities of materials consumed and produced in chemical reactions. Stoichiometry - The study of quantities of materials consumed and produced in chemical reactions.

8. CaC 2 + 2H 2 O → C 2 H 2 + Ca(OH) 2 Coefficients: 1 2 11 Representations: 1 Mole CaC 2 2 Moles H 2 O 1 Mole C 2 H 2 1 Mole Ca(OH) 2 1 mole of CaC 2 reacts with 2 moles of H 2 O to produce 1 moles of C 2 H 2 and 1 mole of Ca(OH) 2

9. CaC 2 + 2H 2 O → C 2 H 2 + Ca(OH) 2 Representations: 1 Molecule CaC 2 2 Molecules Water 1 Molecule C 2 H 2 1 Molecule Ca(OH) 2

10. CaC 2 + 2H 2 O → C 2 H 2 + Ca(OH) 2 Representations: 22.4 Liter CaC 2 44.8 Liters Water 22.4 Liter C 2 H 2 22.4 Liter Ca(OH) 2

11. How much water would I need if I started with 2 moles of CaC 2 ? –Remember the coefficients: 1,2,1,1 –The same ratio present in the basic equation is maintained all the time, no matter the multiplier of any coefficient. Answer: 4 CaC 2 + 2H 2 O → C 2 H 2 + Ca(OH) 2

12. What if I wanted to make 2 moles of Ca(OH) 2 instead of just one? (Remember the cookies) How many moles of CaC 2 would I need? 2 How many moles of H 2 O would I need? 4 CaC 2 + 2H 2 O → C 2 H 2 + Ca(OH) 2

13. Mole ratio: In our equation:

14. Complete list of mole ratios: CaC 2 → H2O→H2O→ C2H2→C2H2→ Ca(OH) 2 →

15. Use the chart given in your aid packet to help you with your mole conversions! This is similar to the road map you used before! MOLE STEP 6.02 X 10 23 22.4 dm 3 perio dic table

16. Stoichiometry Road Map – p. 363

17. Working a Stoichiometry Problem 4 K + O 2  2 K 2 O = 0.56 mol K ? mol O 2 1 mol O 2 4 mol K 0.14 mol O 2 A) How many moles of O 2 are needed to react with 0.56 moles of K to produce potassium oxide? 1

18. Try this with your partner… 4 K + O 2  2 K 2 O = 1.26 mol K ? mol K 2 O 2 mol K 2 O 4 mol K 0.630 mol K 2 O B) How many moles of K 2 O are produced when 1.26 moles of K is reacted with excess oxygen?

19. Questions???

20. Working a Stoichiometry Problem 4 KO 2  2 K 2 O 4 K + O 2  2 K 2 O 0.040 mol O 2 1 C) How many moles of O 2 are needed to make 7.6 g of K 2 O? = 7.6 g K 2 O ? mol O 2 1 mol K 2 O 94.20 g K 2 O 2 mol K 2 O 1 mol O 2

21. Try this with your partner… 4 KO 2  2 K 2 O 4 K + O 2  2 K 2 O 0.382 mol K D) How many moles of K are needed to make 18.0 g of K 2 O? = 18.0 g K 2 O ? mol K 1 mol K 2 O 94.20 g K 2 O 2 mol K 2 O 4 mol K

22. Questions???

23. Reaction: 2NO + O 2 → 2NO 2 1.How many moles of oxygen are required to react completely with 17.33 L of NO? 2.How many grams of nitrogen dioxide are produced from 1.22 moles of nitrogen monoxide? 3.How many moles of oxygen are needed to produce 7.3 x 10 24 molecules of nitrogen dioxide? 4.Calculate the mass of NO that is needed to react completely with 0.557 moles O 2 ? 5.What volume of nitrogen dioxide would be produced from 2.44 moles of nitrogen monoxide?

24. Stoichiometry Road Map – p. 363

25. Working a Stoichiometry Problem 4 K + 1 O 2  2 K 2 O 0.60 g K 2 O E) How many grams of K 2 O will be produced from 0.50 g of K? = 0.50 g K ? g K 2 O 1 mol K 39.10 g K 4 mol K 2 mol K 2 O 1 mol K 2 O 94.20 g K 2 O

26. Try this with your partner… 4 K + 1 O 2  2 K 2 O 0.49 g O 2 F) How many grams of O 2 are needed to react with 2.4 grams of K? = 2.4 g K ? g O 2 1 mol K 39.10 g K 4 mol K 1 mol O 2 32.0 g O 2

27. Questions???