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7-6 Congruence Course 3 Warm Up Warm Up Problem of the Day Problem of the Day Lesson Presentation Lesson Presentation.

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Presentation on theme: "7-6 Congruence Course 3 Warm Up Warm Up Problem of the Day Problem of the Day Lesson Presentation Lesson Presentation."— Presentation transcript:

1 7-6 Congruence Course 3 Warm Up Warm Up Problem of the Day Problem of the Day Lesson Presentation Lesson Presentation

2 Warm Up Find the measure of the indicated angle. Course 3 7-6 Congruence 1. the fourth angle in a quadrilateral containing angles of 100°, 130°, and 75° 2. the third angle of a right triangle with an angle of 60° 3. the supplement of a 35° angle 55° 30° 145°

3 Problem of the Day The measure of ABC is 14° less than the measure of its complement, CBD. What is the measure of each angle? Course 3 7-6 Congruence mABC = 38°; mCBD = 52°

4 M8G1.d : How do I use the properties of congruent figures to solve problems? Course 3 7-6 Congruence

5 Course 3 7-6 Congruence correspondence Vocabulary

6 Course 3 7-6 Congruence A correspondence is a way of matching up two sets of objects. If 2 polygons are congruent, all of their corresponding sides and angles are congruent. In a congruence statement, the vertices (each vertex) in the 2nd polygon are written in order of correspondence with the 1st polygon.

7 Course 3 7-6 Congruence Marks on the sides of a figure can be used to show congruence. AB QR (2 marks) BC PR (3 marks) AC = PQ (1 mark) Helpful Hint __

8 Course 3 7-6 Congruence Example 1A: Writing Congruent Statements The first triangle can be named triangle ABC. To complete the congruence statement, the vertices in the second triangle have to be written in order of the correspondence. A Q, so A corresponds to Q. B R, so B corresponds to R. C P, so C corresponds to P. *The congruence statement is triangle ABC triangle QRP. Write a congruence statement for each pair of polygons. 65

9 Course 3 7-6 Congruence Example 1B: Writing Congruent Statements The vertices in the first pentagon are written in order around the pentagon starting at any vertex. D M, so D corresponds to M. E N, so E corresponds to N. F O, so F corresponds to O. *The congruence statement is pentagon DEFGH pentagon MNOPQ. G P, so G corresponds to P. H Q, so H corresponds to Q. Write a congruence statement for each pair of polygons.

10 Course 3 7-6 Congruence Check It Out: Example 1A The first trapezoid can be named trapezoid ABCD. To complete the congruence statement, the vertices in the second trapezoid have to be written in order of the correspondence. A S, so A corresponds to S. B T, so B corresponds to T. C Q, so C corresponds to Q. *The congruence statement is trapezoid ABCD trapezoid STQR. A B C D Q R ST D R, so D corresponds to R. | || ||| |||| | || ||| |||| Write a congruence statement for each pair of polygons. 60° 120° 60° 120°

11 Course 3 7-6 Congruence Check It Out: Example 1B The vertices in the first pentagon are written in order around the pentagon starting at any vertex. A M, so A corresponds to M. B N, so B corresponds to N. C O, so C corresponds to O. *The congruence statement is hexagon ABCDEF hexagon MNOPQL. D P, so D corresponds to P. E Q, so E corresponds to Q. A B C D E F N O P Q L M F L, so F corresponds to L. Write a congruence statement for each pair of polygons. 140° 110° 140° 110°

12 Course 3 7-6 Congruence Example 2A: Using Congruence Relationships to Find Unknown Values In the figure, quadrilateral VWXY quadrilateral JKLM. a = 16 –8 –8 Subtract 8 from both sides. Find a. a + 8 = 24 WX KL

13 Course 3 7-6 Congruence In the figure, quadrilateral VWXY quadrilateral JKLM. 6 6 6b = 30 Divide both sides by 6. Find b. 6b = 30 ML YX b = 5 Example 2B: Using Congruence Relationships to Find Unknown Values

14 Course 3 7-6 Congruence 5c = 85 J V 5 5 5c = 85 Divide both sides by 5. Find c. c = 17 In the figure, quadrilateral VWXY quadrilateral JKLM. Example 2C: Using Congruence Relationships to Find Unknown Values

15 Course 3 7-6 Congruence Check It Out: Example 2A In the figure, quadrilateral JIHK quadrilateral QRST. Find a. 3a3a 4b° 6 30° Q 120° R S H I J K 3a = 6 3 3 a = 2 c + 10° T 3a = 6 IH RS Divide both sides by 3.

16 Course 3 7-6 Congruence Find b. Divide both sides by 4. 4 4 4b = 120 b = 30° 4b = 120 H S Check It Out: Example 2B In the figure, quadrilateral JIHK quadrilateral QRST. 3a3a 4b° 6 30° Q 120° R S H I J K c + 10° T

17 Course 3 7-6 Congruence Find c. c = 20° Subtract 10 from both sides. –10 c + 10 = 30 K T Check It Out: Example 2C 3a3a 4b° 6 30° 90° Q 120° 90° R S H I J K T c + 10° In the figure, quadrilateral JIHK quadrilateral QRST.

18 Course 3 7-6 Congruence Lesson Quiz In the figure, WXYZ ABCD 2. Find mB. 4. Find mZ. 10 80° 8 90° 1. Find XY. 3. Find CD.


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