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Bellringer.

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Presentation on theme: "Bellringer."— Presentation transcript:

1 Bellringer

2 Chapter 6: Section 2 Slope-Intercept Form

3 Linear Equation Any equation whose graph is a line
Since a function rule can form a line, a function can be linear f(x) = 2x + 5

4 Y-Intercept Represented by the variable b
The y-coordinate of the point where the line crosses the y-axis Graph y = 2x + 5 to see where is crosses the y-axis. What is its slope?

5 Slope-Intercept Form y = mx + b m = slope b = y-intercept

6 Find the slope and y-intercept
y = 3x – 5 y = x + 1 y = (2/3)x – 3 y = -2x

7 Write an equation of the line from the given slope and y-intercept.
m = 2/9 b = 3 m = 0 b = 1 m = -1/4 b = -2 m = 3 b = 0

8 Write the slope-intercept form from the graph of the equation

9 Use the slope and the y-intercept to graph the equation
y = ½ x +4 y = 2x +5 y = -3/2 x

10 Assignment Page 294 Numbers 3-39 multiples of 3 Number 40


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