Presentation on theme: "Inverse Operations (x&/) By: Me Math Period 2. Benchmark: Topic #22: Benchmark:MA.7.2.3: Apply inverse relationships between addition and subtraction,"— Presentation transcript:
Inverse Operations (x&/) By: Me Math Period 2
Benchmark: Topic #22: Benchmark:MA.7.2.3: Apply inverse relationships between addition and subtraction, and multiplication and division, to solve one- step problems.
Definition: Operations that undo each other. Multiplying and dividing are inverse operations and so are addition and subtraction.
Example/ Drawing/ Formula: First you do the inverse of multiplying 3 which is dividing 3. That cancels out. Then I do 6/3, which equals 2. Next, you take the 9x and divide by 9 which now means you are left with x. Now you bring the 2 down and divide 2 and 9 (2/9). Therefore, x= 2/9. Equation: 9x * 3 = 6 9x * 3 = 6 /3 /3 9x 9x = 2 /9 /9 x = 2/9
Create A Question: Can you solve this equation?
My Question: 14x / 4 = 7
Solution to question: x= 2 How did I get 2? Here… look at this
Explanation To Question: What you have to do is do the inverse of dividing 4 which is multiplying 4. That cancels out. Then you do the same to the other side. 7x4=28. Bring that down(28). Next, 14x/14equals it canceling out. X is left over. So, 28/14=2. Therefore, x=2. 14x / 4 = 7
Credits: I would like to thank: Google (for the images) Mr. Imamura (for the math) Kahiki ( for helping me to put the image as the background) Mom( for letting me use the computer)