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SOLUBILITY AND CRYSTAL RADIUS R nc Liquid Solid a a + b Liquid a + b a r.

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Presentation on theme: "SOLUBILITY AND CRYSTAL RADIUS R nc Liquid Solid a a + b Liquid a + b a r."— Presentation transcript:

1 SOLUBILITY AND CRYSTAL RADIUS R nc Liquid Solid a a + b Liquid a + b a r

2 C sinf = 10  g/cm 3 (37°C, water) Carbon Nitrogen Oxigen Sulphur M w = 308.5 NIMESULIDE (non steroidal antiinflammatory drug) (crystal cell side = 0.87 nm)

3 C sinf polymer nanocrystrals amorphous NIMESULIDE RELEASE FROM CROSSLINKED PVP (water 37°C)

4 Liquid a + b a r Kelvin equation 9  sl = solid-liquid surface tension v s = solid solute molar volume R = universal gas constant T = temperature C snc = nanocrystal solubility C sinf = macrocrystal solubility It holds for an ideal solution

5  lv  Vapour  sv  sl Solid substrate Liquid drop EQUAZIONE DI YOUNG Per sostanza pura  = 0 ===>

6 Melting temperature and enthalpy dependence on crystal radius solid liquid vapor

7  sl = solid-liquid interfacial tension  sv = solid-vapour interfacial tension  lv = liquid-vapour interfacial tension A sv = solid-vapour interfacial area A sl = solid-liquid interfacial area A lv = liquid-vapour interfacial area liquid-vapour surface first curvature liquid-vapour surface second curvaturesolid-liquid surface second curvature Solid-liquid surface first curvature solid-vapour surface second curvaturesolid-vapour surface first curvature constants For a sphere: r sl, r sv, r lv curvature radii

8 Closed system thermal equilibrium chemical equilibrium Remembering that: PsPs PlPl PvPv 1) 2) Young eq. for a pure substance

9 mechanical equilibrium S LV R sl R sv

10 Considering the Gibbs-Duhem equation k = 1 ===> only one component (pure substance) 12 3 2113 From the mechanical equilibrium conditions, it follows:

11 then: Assuming v l and v s << v v

12 R nc R lv ≈  TWO LIMITING CONDITIONS R sv does not exist R lv ≈ R sl =R nc R nc R lv

13 R nc R lv ≈  R lv ≈ R sl =R nc R nc R lv X ncr ≈ 1 Many nanocrystals X ncr ≈ 0 Very few nanocrystals

14 General equation  h mr and T mr dependence on R nc and X cnr requires an iterative solution of these equations assuming a starting value of X cnr [M. Zhang, et al., Physical Review B 62 (2000) 10548]

15 X ncr = X ncr 1A Yes Solution: X ncr,  h mr (R nc ), T mr (R nc ) No Numerical solution of: ?  d (drug mass fraction)  h mix (mixture melt. enthalpy) 01  h md (drug melt. enthalpy)  d  h r +  h T )

16 Nanocrystals size distribution volume occupied by crystals ranging in [R nc – (R nc +dR nc )]

17 Solubility dependence on crystal radius R nc thermodynamic equilibrium Liquid(a+b) a drug solubility fugacity of pure drug in the state of under-cooled liquid at the system temperature (T) and pressure (P)

18 1 Solid drug nanocrystals T, P 2 Solid drug nanocrystals T mr, P 3 Liquid drug T mr, P 4 Under-cooled liquid drug T, P isobaric heating Isobaric-isotermic melting isobaric cooling

19  d is calculated knowing macro-crystal solubility in the desired solvent

20 Case study: nimesulide + crosslinked polyvinylpyrrolidone co-ground Ratio 1:3 Co-grinding time: 1, 2 and 4 hours DSC analysis

21

22 Nanocrystals differential size distribution

23  h mr and T mr dependence on R nc and X ncr (crystal cell side = 0.87 nm)

24 Nanocrystals solubility dependence on R nc and X ncr (crystal cell side = 0.87 nm)


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