1. I. The Modern Synthetic Theory of Evolution A. Initial Structure – 1940 Sources of VariationAgents of Change MutationNatural Selection RecombinationDrift - crossing overMutation - independent assortmentMigration Non-random Mating

2. B. Population Genetics 1. Hardy Weinberg a. Definitions: b. Basic computations: 1. Determining the Gene and Genotypic Array: AAAaaa Individuals608060(200)

3. B. Population Genetics 1. Hardy Weinberg a. Definitions: b. Basic computations: 1. Determining the Gene and Genotypic Array: AAAaaa Individuals608060(200) Genotypic Array 60/200 = 0.30 80/200 =.4060/200 = 0.30 = 1 ''A' alleles120800200/400 = 0.5 'a' alleles080120200/400 = 0.5

4. B. Population Genetics 1. Hardy Weinberg a. Definitions: b. Basic computations: 1. Determining the Gene and Genotypic Array 2. Short Cut Method: - Determining the Gene Array from the Genotypic Array a. f(A) = f(AA) + f(Aa)/2 =.30 +.4/2 =.30 +.2 =.50 b. f(a) = f(aa) + f(Aa)/2 =.30 +.4/2 =.30 +.2 =.50 KEY: The Gene Array CAN ALWAYS be computed from the genotypic array; the process just counts alleles instead of genotypes. No assumptions are made when you do this.

5. B. Population Genetics 1. Hardy Weinberg a. Definitions: b. Basic computations: c. Hardy-Weinberg Equilibrium: 1. If a population acts in a completely probabilistic manner, then: - we envision an infinitely large population with no migration, mutation, or selection, and random mating. - we could calculate genotypic arrays from gene arrays - the gene and genotypic arrays would equilibrate in one generation

6. B. Population Genetics 1. Hardy Weinberg a. Definitions: b. Basic computations: c. Hardy-Weinberg Equilibrium: AAAaaa Initial genotypic freq. 0.4 0.21.0 Gene freq.f(A) = p =.4 +.4/2 = 0.6f(a) = q =.2 +.4/2 = 0.4 Genotypes, F1p 2 =.362pq =.48q 2 =.16 = 1.00 Gene Freq'sf(A) = p =.36 +.48/2 = 0.6f(a) = q =.16 +.48/2 = 0.4 Genotypes, F2.36.48.161.00

7. B. Population Genetics 1. Hardy Weinberg 2. Effects of Different Agents - mutation 1. Consider a population with: f(A) = p =.6 f(a) = q =.4 2. Suppose 'a' mutates to 'A' at a realistic rate of: μ = 1 x 10 -5 3. Well, what fraction of alleles will change? 'a' will decline by: qm =.4 x 0.00001 = 0.000004 'A' will increase by the same amount. 4. So, the new gene frequencies will be: p1 = p + μq =.600004 q1 = q - μq = q(1-μ) =.399996…. VERY LITTLE EFFECT on GENE FREQ’s

8. B. Population Genetics 1. Hardy Weinberg 2. Effects of Different Agents - migration p2 = 0.7 q2 = 0.3 suppose migrants immigrate at a rate such that the new immigrants represent 10% of the new population p1 = 0.2 q1 = 0.8

9. B. Population Genetics 1. Hardy Weinberg 2. Effects of Different Agents - migration p2 = 0.7 q2 = 0.3 suppose migrants immigrate at a rate such that the new immigrants represent 10% of the new population p1 = 0.2 q1 = 0.8 p(new) = p1(1-m) + p2(m) = (0.2)(0.9) + (0.7)(0.1) = 0.25 IMPORTANT EFFECT, BUT MAKES POPULATIONS SIMILAR AND INHIBITS DIVERGENCE AND ADAPTATION TO LOCAL CONDITIONS (EXCEPT IT MAY INTRODUCE NEW ADAPTIVE ALLELES)

10. B. Population Genetics 1. Hardy Weinberg 2. Effects of Different Agents - non-random mating 1. Positive Assortative Mating AAAaaa.2.6.2 offspringALL AA1/4AA:1/2Aa:1/4aaALL aa.2.15 +.3 +.15.2 F1.35.3.35

11. B. Population Genetics 1. Hardy Weinberg 2. Effects of Different Agents - non-random mating 1. Positive Assortative Mating B. Inbreeding - reduction of heterozygosity across the entire genome, at a rate that correlates with the degree of relatedness.

12. B. Population Genetics 1. Hardy Weinberg 2. Effects of Different Agents - Genetic Drift 1. The organisms that actually reproduce in a population may not be representative of the genetics structure of the population; they may vary just due to sampling error

13. B. Population Genetics 1. Hardy Weinberg 2. Effects of Different Agents - Genetic Drift 2. patterns

14. B. Population Genetics 1. Hardy Weinberg 2. Effects of Different Agents - Genetic Drift 2. patterns

15. - “Genetic Bottleneck” If a population crashes (perhaps as the result of a plague) there will be both selection and drift. There will be selection for those resistant to the disease (and correlated selection for genes close to the genes conferring resistance), but there will also be drift at other loci simply by reducing the size of the breeding population. European Bison, hunted to 12 individuals, now number over 1000. Cheetah have very low genetic diversity, suggesting a severe bottleneck in the past. They can even exchange skin grafts without rejection… Fell to 100’s in the 1800s, now in the 100,000’s

16. A. Measuring “fitness” – differential reproductive success 1. The mean number of reproducing offspring (or females)/female 2. Components of fitness: - probability of female surviving to reproductive age - number of offspring the female produces - probability that offspring survive to reproductive age B. Population Genetics 1. Hardy Weinberg 2. Effects of Different Agents - Selection: Differential reproductive success

17. p = 0.4, q = 0.6AAAaaa Parental "zygotes"0.160.480.36 = 1.00 prob. of survival (fitness)0.8 0.2 Relative Fitness110.25 Survival to Reproduction0.160.480.09 = 0.73 Geno. Freq., breeders0.220.660.12 = 1.00 Gene Freq's, gene poolp = 0.55q = 0.45 Genotypes, F10.30250.4950.2025 = 100 B. Population Genetics 1. Hardy Weinberg 2. Effects of Different Agents - Selection: Differential reproductive success