1. AREA AND VOLUME
Form 1 Mathematics
Chapter 7

2. Reminder Lesson requirement Before lessons start Textbook 1B
Workbook 1B
Notebook
Folder
Before lessons start
Desks in good order!
No rubbish around!
No toilets!

3. Result of CBQ (Ch. 9) Result of Close Book Quiz Major Problems
Full mark: 40 and 10 bonus
Highest: 44
Lowest: 10
Average: 23.8
Number of students between 10 – 19: 13
Number of students between 0 – 9: 0
Major Problems
Cannot get the drawing in rotation
Cannot get the coordinates in transformation
Mix up the rotation and reflection

4. Result of CBQ (Ch. 9) Result of Close Book Quiz
9th place: KO Ka Chung Boston
LIN Long Chak, Vincent
8th place: FU Ling Yin, Larry
7th place: LAU Cheuk Hei, Anson
6th place: CHEN Yi, David
5th place: CHAN Tsz Long, Sam
4th place: YUEN Tin Wai, Timmy
2nd place: LI Ming Chun, Edward
WU SHAN Hao Yi
1st place LI Sai Kong
Congratulations!!!!!! Well done!!!!!!

5. Area of plane figures (p.2)
1. Area of triangle
=  base  height 1 2
2. Area of square
= length  length
3. Area of rectangle
= length  width

6. Area of plane figures (p.2)
4. Area of parallelogram
= base  height
5. Area of trapezium
=  sum of lengths of parallel sides  height 1 2

7. Calculating areas (p.3) Splitting Method Filling Method
Area of the figure 1 2
=  (3 + 6)  2 cm2
= cm2
Area of the figure
=  4 –  2  2 cm2 1 2
= 38 cm2

8. Time for Practice Pages 10 – 11 of Textbook 1B
Questions 5 – 18
Pages 1 – 3 of Workbook 1B
Questions 1 – 5

9. WORKBOOK

10. WORKBOOK 16 36 10
260
cm2 36 36 10
(18  26) cm2
= cm2
260
468
728 cm2

11. WORKBOOK 3 3
18 cm2
728 18
710 cm2

12. Volume of Simple Solids (p.3)
1. Volume of cube
= length  length  length
2. Volume of cuboid
= length  width  height

13. PRISMS (柱體, P.12)
A solid with uniform cross- section in the shape of a polygon is called a prism.
A prism is named and classified according to the shape of its base.
The perpendicular distance between the two parallel bases of a prism is called its height (or length).
The faces (other than the two bases) of a prism are called lateral faces.
base
height
lateral faces
base
Triangular prism

14. Volume of Prisms (p.17) Volume = area of base  height
e.g. Volume of the solid
= 260  20 cm3
= 5200 cm3

15. Surface Areas of Prisms (p.14)
Total surface area
= areas of the two bases
+ total area of all lateral faces
e.g. Total surface area of the solid
= [2   (20  10)] cm2
= 1720 cm2

16. Volume of Prisms Volume of the triangular prism = ?
Area of the base of the prism
= ( 7  4  2 ) cm2
= 14 cm2
So, the volume
= ( 14  10 ) cm3
= 140 cm3

17. Volume of Prisms Volume of the rectangular prism (cuboid) = ?
The volume
= [ ( 5  3 )  6 ] cm3
= 90 cm3
= [ ( 3  6 )  5 ] cm3
= [ ( 5  6 )  3 ] cm3

18. Volume of Prisms Find the volume of the prism. Area of base
= (12  7 – 8  5) cm2
= 44 cm2
= 44  11 cm3
= 484 cm3

19. Volume & Surface Area of Prisms
The figure shows a gold ingot in the shape of a prism. Its base is a trapezium, and the other faces are rectangles. If the volume of the gold ingot is 540 cm3, find (a) the value of d,
(b) the total surface area of the gold ingot. 1 2
= (6 + 12)  4 cm2
(a) Area of trapezium
∴ The volume of the gold ingot
i.e. 36d = 540
d = 15
(b) Total surface area of the gold ingot
= [2   (15  5) + 15   6] cm2
= 492 cm2
= 36 cm2
= 36d cm3

20. Time for Practice Pages 22 – 23 of Textbook 1B
Questions 10 – 20
Pages 6 – 7 of Workbook 1B
Questions 3 – 6

21. WORKBOOK

22. WORKBOOK 8 8 8
512 5 10 4
200
cm3
200
12d
512 4 3 d
12d = 312
12d
cm3 26

23. WORKBOOK
2.5 1 6 15
cm2 19 15
4 cm2 4
2 cm2 2
2.5 5
cm3 1 2 3
6 cm3
6 cm3
5 cm3 B

24. Reminder Missing Homework, Re-do Homework SHW (I) SHW (II)
Today!
SHW (I)
SHW (II)
22 Mar (Fri)
Open Book Quiz
Close Book Quiz
26 Mar (Tue)

25. Enjoy the world of Mathematics!
Ronald HUI