1. 1 Homework for Ch.29 Alternating Current Circuits 19, 23, 25, 31, 39

2. 2 29 Overview why & how to use rms values determine impedance of L & C why & how: phase relationships in ac circuits

3. 3 sinusoidal current “ac” I ~ sine, cosine variation with time: (I = Io cos(wt + phi)) w = 2pf, e.g. US grid uses 60 cycles/sec, w = 2p(60) = 377 rad/s

4. 4 basic circuits with:

5. 5 resistors: V R ~ I

6. 6 inductors: V L ~ dI/dt voltage “leads” current

7. 7 capacitors: V C ~ Q current “leads” voltage

8. 8 impedance Z = “ac R”

9. 9 Example: 55mH Inductor, r = 0, connected to household 120VAC (60 hertz).

10. 10 Example: 10  F capacitor: connected to household 120VAC (60 hertz).

11. 11 exponential notation used to replace cosine or sine dependence

12. 12 exp derivatives

13. 13 RLC exp application: From dx/dt = I, Z and phase are:

14. 14 ac LR lab measure: voltages calculate: L & phase angle

15. 15 Student Data (L ~ 1mH, f ~ 10,000Hz) 15ohm60ohm100ohm V6.76.36.5 V-ind6.64.83.9 V-R1.04.35.4 angle795036

16. 16 Trig Calculations

17. 17 Phasor Calculation     phase

18. 18 Phasor Calculation     phase

19. 19 phasor

20. 20 Exercise Use trig identity & phasor method to show that has amplitude 5.66 and phase 45°.

21. 21

22. 22 Resonance in an RLC Circuit min. Z: when XL = XC result: large currents application: radio tuner hi power at tuned freq. low power at other f’s Ex. calc LC for f = 10,000

23. 23 Summary sine dependent I has I rms = 0.707 Io other rms values from direct calculation phase relations: R: phi = 0 L: voltage on inductor leads I. C: I to capacitor leads voltage. impedance & resonance in RLC circuit

24. 24 Transformer

25. 25 AC Power average

26. 26 AC Power

27. 27 Example I(t) = 0.577 I o

28. 28 An I(t) current source continuously repeats the following pattern: {1 seconds @ 3 ampere, 1 second @ 0 ampere} Calculate average, rms I.

29. 29 If a sinusoidal generator has a maximum voltage of 170V, what is the root- mean-square voltage of the generator?

30. 30 R setting Actual R  10 ohm30 ohm60 ohm100 ohm V app (V) V ind (V) V R (V) Table 2: Calculated Data cosf f(degrees) V L = Vsinf V r = Vcosf - V R r = RV r /V R L = RV L /(wV R )

31. 31 Alternating Current Generators  m = NBAcos .

32. 32 Generators  m = NBAcos  : (  =  t +  when rotating ) emf = -d  m /dt = -NBA  (-sin(  t +  )) emf = NBA  sin(  t +  ) (emf) peak = NBA .

33. 33 AC Generator applied to Resistor