1. 1. An image of a distant object formed by a single converging lens ____.
A. can be focused on a screen.
B. can be projected on a wall.
C. is upside down.
D. is real.
E. all of the above.

2. 1. An image of a distant object formed by a single converging lens ____.
A. can be focused on a screen.
B. can be projected on a wall.
C. is upside down.
D. is real.
E. all of the above.

3. 2. An image formed by a single diverging lens ____.
A. is upside down.
B. is larger than the object.
C. can be projected on a wall.
D. is virtual.
E. all of the above.

4. 2. An image formed by a single diverging lens ____.
A. is upside down.
B. is larger than the object.
C. can be projected on a wall.
D. is virtual.
E. all of the above.

5. 3. A magnifying glass is usually a ____.
A. converging lens.
B. combination of diverging and converging lenses.
C. diverging lens.

6. 3. A magnifying glass is usually a ____.
A. converging lens.
B. combination of diverging and converging lenses.
C. diverging lens.

7. 4. Which instrument is a human eye most similar to?
A. camera
B. microscope
C. telescope
D. slide projector

8. 4. Which instrument is a human eye most similar to?
A. camera
B. microscope
C. telescope
D. slide projector

9. 1. An object is placed 6.0 cm in front of a converging lens of focal length 4.0 cm. Draw a ray diagram to show the location and orientation of the image formed. What is its type and orientation?

10. First draw a line parallel to the principle axis which refracts through the focal point.

11. First draw a line parallel to the principle axis which refracts through the focal point.

12. Then draw a line through the optical center of the lens
Then draw a line through the optical center of the lens. Where they cross is the image.

13. This image is real and inverted (case 4)
This image is real and inverted (case 4). We use the equations to find the actual distance and size of the image.

14. 2. The focal length of a double convex lens is 4. 0 cm. An object 2
2. The focal length of a double convex lens is 4.0 cm. An object 2.0 cm high is 10.0 cm from the lens. Draw a ray diagram of this situation. Calculate the location and size of the image. What is its type and orientation?

15. First draw a line parallel to the principle axis which refracts through the focal point.

16. First draw a line parallel to the principle axis which refracts through the focal point.

17. Then draw a line through the optical center of the lens
Then draw a line through the optical center of the lens. Where they cross is the image.

18. This image is real and inverted
This image is real and inverted . We use the equations to find the actual distance and size of the image.

19. 1 1 1 ------ = ------ + ------ f do di 1 1 1 ------ = ------ + ------ 4 10 di di = 6.67 cm

20. hi. di -------. =. ------- ho. do hi. 6. 67 cm -------
hi di = ho do hi cm = cm cm hi = 1.3 cm, mag = 0.667

21. 3. A double convex lens has a focal length of 5. 0 cm. An object 0
3. A double convex lens has a focal length of 5.0 cm. An object 0.75 cm high is 3.0 cm from the lens. Draw a ray diagram of this situation. Calculate the location and size of the image. What is its type and orientation?

22. First draw a line parallel to the principle axis which refracts through the focal point.

23. First draw a line parallel to the principle axis which refracts through the focal point.

24. Then draw a line through the optical center of the lens
Then draw a line through the optical center of the lens. Where they cross is the image.

25. Image is virtual, upright, and larger.
Case 6, a magnifying glass.

26. 1 1. 1 ------. =. ------. +. ------ f. do. di 1 1. 1 ------. =. ------
= f do di = di di = -7.5 cm

27. hi. di -------. =. ------- ho. do hi. -7. 5 cm. ---------
hi di = ho do hi cm = cm cm hi = 1.88 cm, mag = -2.5

28. 4. A concave lens has a focal length of 6. 0 cm. An object is placed 7
4. A concave lens has a focal length of 6.0 cm. An object is placed 7.0 cm from the lens. Draw a ray diagram of this situation. Calculate the location and size of the image. What is its type and orientation? What is the magnification of this lens?

29. First draw a line parallel to the principle axis which refracts through the focal point.

30. First draw a line parallel to the principle axis which refracts through the focal point.

31. Then draw a line through the optical center of the lens
Then draw a line through the optical center of the lens. Where they cross is the image.

32. This image is virtual, upright, and smaller
This image is virtual, upright, and smaller. We use the equations to find the actual distance and size of the image.

33. 1. 1. 1 ------. =. ------. +. ------ f. do. di 1. 1. 1 ------. =
= f do di = di di = -3.2 cm

34. hi. di -------. =. ------- ho. do hi. -3. 2 cm. ---------
hi di = ho do hi cm = ho cm mag = 0.46

35. 5. What type of lenses are used to correct for farsightedness and nearsightedness?
Farsightedness is corrected using a converging lens (convex).
Nearsightedness is corrected using a diverging lens (concave).