Presentation is loading. Please wait.

Presentation is loading. Please wait.

Heat Transfer Lecturer: Professor Stephen T. Thornton.

Similar presentations


Presentation on theme: "Heat Transfer Lecturer: Professor Stephen T. Thornton."— Presentation transcript:

1 Heat Transfer Lecturer: Professor Stephen T. Thornton

2 Reading Quiz 1 kg of water at 100 ° C is poured into a bucket that contains 4 kg of water at 0°C. Find the equilibrium temperature (neglect the influence of the bucket). A) 0°C B) 20 ° C C) 50 ° C D) 80 ° C E) 100 ° C

3 cold water mass is greater smaller temperature change Because the cold water mass is greater, it will have a smaller temperature change! The masses of cold/hot have a ratio of 4:1, so the temperature change must have a ratio of 1:4 (cold/hot). Reading Quiz 1 kg of water at 100 ° C is poured into a bucket that contains 4 kg of water at 0 ° C. Find the equilibrium temperature (neglect the influence of the bucket). A) 0 ° C B) 20 ° C C) 50 ° C D) 80 ° C E) 100 ° C Q 1 = Q 2 m 1 c  T 1 = m 2 c  T 2  T 1  T 2 = m 2 m 1 / /

4 Last Time Thermodynamic processes Isothermal, adiabatic Specific heat of gases Equipartition

5 Today Adiabatic expansion Heat transfer Conduction Convection Radiation

6 Conceptual Quiz: An ideal monatomic gas has a molar heat capacity C p at constant pressure. What is the molar heat capacity at constant volume for an ideal diatomic gas? A)C p B) C p + R C) C p –R D) C p + 3 R/ 2 E) C p - 3R/2

7 Answer: C We found C P – C V = R, so C V = C P – R. We found this for monatomic gases, but we also found experimentally it was true for diatomic gases.

8 Copyright © 2009 Pearson Education, Inc. Adiabatic Expansion of a Gas For an adiabatic expansion, dE int = -PdV, since there is no heat transfer, Q = 0. From the relationship between the change in internal energy and the molar heat capacity, dE int = nC V dT. So –PdV = nC V dT From the ideal gas law, d(PV) = PdV + VdP = nRdT. Combining and rearranging gives (C P /C V )PdV + VdP = 0.

9 Copyright © 2009 Pearson Education, Inc. Define: Integration of then gives the result (see textbook): γ is called the adiabatic gas constant

10 A Comparison Between Isotherms and Adiabats

11 Do Jug O’Air demo.

12 Heat Exchange  Conduction – molecules touch each other and exchange energy.  Convection – hot fluids rise  Radiation – electromagnetic radiation like light, infrared, ultraviolet radiation; all frequencies. These are very important!!

13 Heat conduction If we put a torch to a piece of metal, the molecules in the metal have increased kinetic energy. They collide with adjacent molecules, and the heat moves down the material via these collisions. Start demo. Some materials transport heat energy more easily than others. Metals are good heat conductors. Wood and plastics are poor.

14 Heat Conduction Through a Rod Q is proportional to A and temperatures T 2 – T 1 Q is proportional to 1/L where k is called the thermal conductivity W/(m K)

15 Copyright © 2009 Pearson Education, Inc. The constant k is called the thermal conductivity. Materials with large k are called conductors; those with small k are called insulators. Note: materials that are good heat conductors are also good electrical conductors. Why?

16 Do thermal conductivity demos

17 Note in the table on thermal conductivities that air is a very poor heat conductor. In fact, we could say it is a good heat insulator. This is why double pane windows are such good insulators both in the summer and winter. Glass panes are thin and conduct heat much better than air. The layer of air does wonders!

18 Conceptual Quiz: Which of the following configurations conducts heat more readily? A) The one on the left. B) The one on the right. C) They both conduct the same.

19 Answer: A Remember that heat flow Q is proportional to A/L, which both favors the left side. The rods on the left have the full  T, which also helps.

20 Countercurrent Heat Exchange in the Human Arm Same phenomenon happens with sea gulls, egrets and other wading birds.

21 Copyright © 2009 Pearson Education, Inc. Building materials are measured using R- values rather than thermal conductivity: Here, is the thickness of the material.

22 Heat Exchange  Conduction – molecules touch each other and exchange energy.  Convection – hot fluids rise  Radiation – electromagnetic radiation like light, infrared, ultraviolet radiation; all frequencies. These are very important!!

23 Heat convection Well known phenomenon because hot fluids rise due to their lower density. We take advantage of this by putting heat ducts on the floor. Do demo – convection chimney

24 Copyright © 2009 Pearson Education, Inc. Convection occurs when heat flows by the mass movement of molecules from one place to another. It may be natural or forced; both these examples are natural convection.

25 Heat radiation Have you ever sat in front of a campfire and wondered why your face is so warm, and your behind so cold? We have not yet studied light, but when we do next semester, you will learn that all objects emit electromagnetic radiation. Waves easily carry energy in the form of light, radar, microwave (cell phone), etc. Our existence depends on heat radiation from the Sun.

26 Do light the match (wood) demo. Example of radiation.

27 Heat radiation is noted in terms of radiated power P

28 = 1 is a perfect emitter and absorber, and is called a blackbody. = 0 is an ideal reflector. Inside of a thermos bottle is shiny and is a good reflector. The heat of the container emits radiation, but it is not absorbed by the outer wall.

29 The Thermos Bottle

30 Copyright © 2009 Pearson Education, Inc. If you are in the sunlight, the Sun’s radiation will warm you. In general, you will not be perfectly perpendicular to the Sun’s rays, and will absorb energy at the rate:

31 Copyright © 2009 Pearson Education, Inc. This cos θ effect is also responsible for the seasons.

32 Conceptual Quiz: Which of the following processes of heat transfer is independent of the area exposed? A) conduction B) convection C) radiation D) all of these E) none of these

33 Answer: E In one form or the other, all of the heat transfer mechanism depend on the area.

34 Conceptual Quiz You step out of a swimming pool on a hot day, where the air temperature is 90°F. Where will you feel cooler, in Phoenix (dry) or in Philadelphia (humid)? A) equally cool in both places B) Philadelphia C) Phoenix

35 In Phoenix, where the air is dry, more of the water will evaporate from your skin. This is a phase change, where the water must absorb the heat of vaporization, which it takes from your skin. That is why you feel cool as the water evaporates. Conceptual Quiz You step out of a swimming pool on a hot day, where the air temperature is 90°F. Where will you feel cooler, in Phoenix (dry) or in Philadelphia (humid)? A) equally cool in both places B) Philadelphia C) Phoenix

36 Conceptual Quiz: Do the rods in a previous question transmit an equal amount of heat when in the parallel configuration? A) No, because they have different heat conductivities. B) Yes, because the temperatures are different at the ends. C) No, because the temperatures are different at the ends. D) Yes, because they have the same areas and lengths.

37 Answer: A Look at the equation for thermal conduction. It depends on thermal (heat) conductivity.


Download ppt "Heat Transfer Lecturer: Professor Stephen T. Thornton."

Similar presentations


Ads by Google