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By: Justin Mitchell and Daniel Harrast. Inscribed angle- an angle whose vertex is on a circle and whose sides contain chords of the circle. Intercepted.

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Presentation on theme: "By: Justin Mitchell and Daniel Harrast. Inscribed angle- an angle whose vertex is on a circle and whose sides contain chords of the circle. Intercepted."— Presentation transcript:

1 By: Justin Mitchell and Daniel Harrast

2 Inscribed angle- an angle whose vertex is on a circle and whose sides contain chords of the circle. Intercepted arc- the arc that lies in the interior of an inscribed angle and has endpoints on the angle. Intercepted arc Inscribed angle

3 The measure of an inscribed angle is one half the measure of its intercepted arc. CD A B m<ADB=1/2mAB

4 Ex. 1: Use inscribed angles  Find the indicated measure of m<T in P. Solution m<T= ½ mRS = ½ (48˚) = 24˚ Q R S T P 48˚

5 Find the indicated measure of m<A A B C 84˚ 42˚

6 Find mRS and < STR. What do you notice about <STR and <RUS? Solution From theorem 10.7, you know that mRS = 2m<RUS = 2(31˚) = 62˚. Also, m<STR = ½ mRS = ½ (62˚) = 31˚. So, <STR is congruent to <RUS. 31˚ S T U R

7  Find the indicated measure of mRS R Q S 67˚ 134˚

8 If two inscribed angles of a circle intercept the same arc, then the angles are congruent. A D B C <ADB is congruent to <ACB

9 Inscribed polygon: A polygon whose vertices all lie on a circle. Circumscribed circle: A circle that contains the vertices of the polygon. Circumscribed circle Inscribed polygon

10 If a right triangle is inscribed in a circle, then the hypotenuse is a diameter of the circle. Conversely, if one side of an inscribed triangle is a diameter of the circle, then the triangle is a right triangle and the angle opposite the diameter is a right angle. A B C Dm< ABC = 90˚. If and only if AC is a diameter of a circle.

11  A quadrilateral can be inscribed in a circle if and only if its opposite angles are supplementary. D,E,F and G lie on c if and only if m<D + m<F = m<E + m<G = 180˚. E D G F C

12 PQRS is inscribed in a circle, so opposite angles are supplementary. m<P + m<R = 180˚ 75˚+ y˚ = 180˚ y = 105˚ m<Q + m<S = 180˚ 80˚ + x˚ = 180˚ x = 100˚ Q R P S 80˚ y˚ 75˚ x˚


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