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Learning Outcomes Distinguish between Power and Energy. And use the equation Energy = Power x Time Use the equations: Units Used (kWh) = Power (kW) x Time.

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Presentation on theme: "Learning Outcomes Distinguish between Power and Energy. And use the equation Energy = Power x Time Use the equations: Units Used (kWh) = Power (kW) x Time."— Presentation transcript:

1 Learning Outcomes Distinguish between Power and Energy. And use the equation Energy = Power x Time Use the equations: Units Used (kWh) = Power (kW) x Time (h) Cost (p) = Units used x Cost per unit (p) Use data to make comparisons of different sources of domestic energy.

2 Key Words: Power: The rate of flow of energy Energy: The ability to do work

3 Others 2% Fridge/ freezer 15% Television 2.5% Water heater25% Oven 5% Drag the appropriate labels to the correct boxes in order to complete the graph showing the percentage use of electricity in the home. Washing machine <1% Computer <1% Tumble dryer3.5% Dish washer1.5% Bulbs 25%

4 Remember that there are1000W for every 1kW. So, 2kW = 2000W = 2000J/s
The power rating of a bulb is 60W. This means that 60 Joules of electrical energy is used every second to produce light and heat energy. The power rating of a kettle is 2kW. This means that 2000 Joules of electrical energy is used every second to produce heat energy and to boil the water. Remember that there are1000W for every 1kW. So, 2kW = 2000W = 2000J/s 0.1kW = 100W = 100J/s 3.7kW = 3700W = 3700J/s 0.02kW = 20W = 20J/s The unit of power is the Watt (W), and 1W is equivalent to 1J of energy per second.

5 You will need to be able to use: Power (W) = voltage (v)  current (A)
HIGHER Electrical power is the measure of how fast electrical energy can be transformed into other energies. You will need to be able to use: Power (W) = voltage (v)  current (A) If the mains voltage is 240V, what is the power of a sound system, if there is 0.4A of current flowing through it? The current flowing through a toaster is 4.2A, The mains voltage is 240V. What is the power of the toaster? Answer Answer Power (W) = current (A)  voltage (V) = 4.2  240 = 1008W ( about 1kW ) Power(W) = current (A)  voltage (V) = 0.4  240 = 96W

6 This small power station is producing 250kW of electricity.
HIGHER This small power station is producing 250kW of electricity. This step-up transformer is increasing the voltage to 25,000V. What will the current be through the cables? Answer Step-up-transformer Power (W) = current (A)  voltage (V) 250,000 = current  25,000 250,000 = current = 10A 25,000

7 I pay my electricity bill every month by direct debit
I pay my electricity bill every quarter How much energy do we use?

8 Power 100W There are 1000W in every 1kW
Power is the rate of doing work, or the rate of energy transfer and is measured in Watts. There are 1000W in every 1kW

9 Click here for the answer
Highest value 100W 0.05kW 0.4kW 1kW 30W 20kW 650W Click here for the answer Lowest value

10 Highest value 20kW 20,000W 1kW 1,000W 650W 650W 0.4kW 400W 100W 100W 0.05kW 50W 30W 30W Lowest value

11 energy transfer = power  time
There are 1000W in every 1kW energy transfer = power  time So, a 100W light bulb will transfer 100J of electrical energy into a total of 100J of light and heat energy per second. And a 2kW kettle will transfer 2,000J of electrical energy into a total of 2,000J of heat energy per second. In fact, 1W = 1J/s

12 Units used (kWh) = power (kW)  time (h)
This was the type of electric meter that would have measured the amount of electricity used in your home. It measured the electrical energy used in units of 1kWh (equivalent to a 1000W device running for 1 hour). You are then billed on the number of units used in total for a given period. kWh 391M Units used (kWh) = power (kW)  time (h)

13 0567 Units used (kWh) = power (kW)  time (h)
These days, digital electric meters are the norm. But although it looks different, the amount of electricity used is still measured in kWh. 0567 kWh Units used (kWh) = power (kW)  time (h) cost = units used  cost per unit

14 Below are the meter readings taken at particular times during the year for a 3 bedroom house.
0567 kWh 2207 kWh 3519 kWh 4517 kWh September 9th (2010) January 9th (2011) May 9th (2011) September 9th (2011) 1. Calculate the number of units (KWh) used during each period. 2. Calculate the total number of units (KWh) used during the year. 3. During what period was the most electricity used, and can you explain why? 4. If one unit (1kWh) costs 8.3p, what is the average cost per day for this house?

15 Units used (kWh) = power (kW)  time (h)
If a single 100W light bulb was switched on for a total of 4 hours, and the cost of a unit of electricity (1kWh) is 8p then….. Units used (kWh) = power (kW)  time (h) = 0.1 4 = 0.4 cost = units used  cost per unit = 0.4 8 = 3.2p This doesn’t seem much, but this is for only one 100W light bulb that is on for 4 hours – how many light bulbs do you have switched on in your home during the day?

16 Different Shoes How would today’s lesson be different if it was taught by: A third world (LEDC) farmer A climate change scientist A money saving expert


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