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Experiment to develop the relationship between the pressure and volume of a gas. Include: Boyle’s Law Experiment to develop the relationship between the.

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Presentation on theme: "Experiment to develop the relationship between the pressure and volume of a gas. Include: Boyle’s Law Experiment to develop the relationship between the."— Presentation transcript:

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2 Experiment to develop the relationship between the pressure and volume of a gas. Include: Boyle’s Law Experiment to develop the relationship between the volume and temperature of a gas. Include: Charles’ Law, Absolute zero, Kelvin scale, ideal gas Additional KEY Terms Inverse relationship Direct relationship

3 BOYLE’S LAW: The volume of a given amount of gas (held at a constant temperature) varies inversely with the pressure. P α1 V

4 Pressure (kPa) Volume (mL) BOYLE’S LAW – Pressure vs. Volume

5 What will be the volume of 40 L of gas (held at a constant temperature) if the pressure is doubled? Reduced to 1/3 rd ? P α1 V 1/3 α 1 1/3 2 α1 2 1 = 3 1/3 120 L 20 L

6 PV = k = P1V1P1V1 P2V2P2V2 P α1 V

7 If 3 L of gas is initially at a pressure of 1 atm, what would be the new pressure required for a volume of 0.5 L? 6 atm of pressure will change 3 L of a gas at 1 atm to 0.5 L. = P1V1P1V1 P2V2P2V2 = (1)(3)P2P2 (0.5)

8 A syringe contains 20 mL of a gas at 100 kPa. The pressure in the syringe is changed to 25 kPa. What is the new volume of the gas? The gas will expand to 80 mL. = P1V1P1V1 P2V2P2V2 = (100)(20)V2V2 (25)

9 Absolute Zero

10 Jacques Charles (1746-1823) Volume of gas changed with only 1 o C change in temperature. An increase of 273°C, doubled the volume. V α T CHARLES’S LAW: Volume of a given gas (held at a constant pressure) varies directly with the temperature

11 Temperature ( o C) Volume (mL) CHARLES’S LAW – Temp vs. Volume ?

12 William Thomson (1824-1907) Created Kelvin Scale where 0 K represents the lowest possible temperature (–273°C) called Absolute Zero predicts that with zero kinetic energy comes zero volume called an ideal gas model T K = T C + 273 T C = T K - 273 Stated as “315 Kelvin”- no degrees

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14 = V1V1 V2V2 T2T2 T1T1 **All temperatures must be in Kelvin. V α T V = k T

15 What is the new volume of a gas if 100 mL of the gas at 25°C is cooled to –25°C? 25°C + 273 = 298 K –25°C + 273 = 248 K The new volume is 83.2 mL. = V1V1 V2V2 T2T2 T1T1 = 100 V2V2 -25 25 = 100 83.2 mL (248) 298

16 If the volume of a gas at –73°C is doubled to 48.0 L, calculate the final temperature in degrees Celsius. 400 K – 273 = 127°C –73°C + 273 = 200 K = V1V1 V2V2 T2T2 T1T1 = 24.0 48.0 400 K (200)

17 Boyle described the inverse relationship between the pressure and volume of a gas at a constant temperature. Charles described the direct relationship between the temperature and volume of a gas at a constant pressure. William Thomson (Lord Kelvin) developed the Kelvin temperature scale. At zero Kelvin (absolute zero), the volume of a gas will theoretically be zero. When solving gas problems the temperature must always be converted to Kelvin.

18 CAN YOU / HAVE YOU? Experiment to develop the relationship between the pressure and volume of a gas. Include: Boyle’s Law Experiment to develop the relationship between the volume and temperature of a gas. Include: Charles’ Law, Absolute zero, Kelvin scale, ideal gas Additional KEY Terms Inverse relationship Direct relationship


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