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Example 3: Determination of M r = 3/8. Example 4: Pavement Thickness Given M r = 10,000 psi (69 MPa) and ESAL = 10 6, design the thickness of a pavement.

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Presentation on theme: "Example 3: Determination of M r = 3/8. Example 4: Pavement Thickness Given M r = 10,000 psi (69 MPa) and ESAL = 10 6, design the thickness of a pavement."— Presentation transcript:

1 Example 3: Determination of M r = 3/8

2 Example 4: Pavement Thickness Given M r = 10,000 psi (69 MPa) and ESAL = 10 6, design the thickness of a pavement with a HMA surface over a type-II emulsifies asphalt base Combined thickness = 10.5 inch (267 mm)

3 Cont. Example 4: Pavement Thickness Calculate the minimum HMA thickness = 3 inch Calculate the thickness of emulsified asphalt base = 10.5 -3 = 7.5 inch Traffic Level ESAL Type II and III mm(in.) 10 4 50(2) 10 5 50(2) 10 6 75(3) 10 7 100(4) >10 7 130(5) Minimum Thickness of Asphalt Concrete Over Emulsified Asphalt Bases Subgrade base Surface 3 in 7.5 in

4 Considered as a cold mix asphalt = Fine aggregate + Emulsion

5 Marshall Method- Numerical Example

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