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Chapter 6 Chemical Reactions Chemistry 101. Chemical Reactions Chemical change = Chemical reaction Substance(s) is used up (disappear) New substance(s)

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Presentation on theme: "Chapter 6 Chemical Reactions Chemistry 101. Chemical Reactions Chemical change = Chemical reaction Substance(s) is used up (disappear) New substance(s)"— Presentation transcript:

1 Chapter 6 Chemical Reactions Chemistry 101

2 Chemical Reactions Chemical change = Chemical reaction Substance(s) is used up (disappear) New substance(s) is formed. Different physical and chemical properties.

3 Chemical Reactions

4 Evidence for chemical reactions 1.Color changes 2.A solid is formed (precipitation) 3.Bubbles form (gas) 4.Heat (and/or flame) is produced, or heat is absorbed

5 A + B  C + D Reactants Products Chemical Reactions Chemical Equation

6 Chemical Reactions Products contain the same atoms as reactants. Rearrangement of atoms

7 Solid (s) Liquid (l) Gas (g) Aqueous (aq) Ca(OH) 2 (s) + 2HCl(g)  CaCl 2 (s) + H 2 O(l) Chemical Equation Physical States (forms)

8 Chemical equation gives us some information: 1.Identities of the reactants and products. 2.Relative amounts of the reactants and products. 3.Physical states of the reactants and products. 4.Stoichiometry Chemical Equation

9 Type of chemical reactions A + B  AB 1. Synthesis reaction (combination) 2H 2 + O 2  2H 2 O AB  A + B 2. Decomposition (analysis) 2NaCl  2Na + Cl 2 A + BC  AC + B 3. Single replacement reaction Fe + CuSO 4  FeSO 4 + Cu AB + CD  AD + CB 4. Double replacement reaction NaCl + AgNO 3  NaNO 3 + AgCl

10 5. Combustion C 3 H 8 + 5O 2  3CO 2 + 4H 2 O + Heat AB + xO 2  yCO 2 + zH 2 O + Heat (Energy) Type of chemical reactions

11 Why balancing? Balance a chemical equation All chemical equations should be balanced.

12 Balance a chemical equation Low of conservation of mass Atoms are neither destroyed nor created. They shift from one substance to another.

13 Always double check! Balance a chemical equation 1.Begin with atoms that appear in only one compound on the left and right. 2.If an atom occurs as a free element, balance it last. 3.Change only coefficients (not formulas). C 3 H 8 (g) + O 2 (g)  CO 2 (g) + H 2 O(g) last

14 Balance a chemical equation C 3 H 8 (g) + 5O 2 (g)  3CO 2 (g) + 4H 2 O(g) 2C 3 H 8 (g) + 10O 2 (g)  6CO 2 (g) + 8H 2 O(g) 22 3C 3 H 8 (g) + 15O 2 (g)  9CO 2 (g) + 12H 2 O(g) 33 Lowest set of numbers

15 Examples for Balancing __ C 2 H 5 OH(l) + __ O 2 (g)  __ CO 2 (g) + __ H 2 O(g) __ PbCl 2 (aq) + __ K 2 SO 4 (aq)  __ PbSO 4 (s) + __ KCl(aq) __ CaC 2 (s) + __ H 2 O(l)  __ Ca(OH) 2 (s) + __ C 2 H 2 (g)

16 __ Fe(s) + ____ O 2 (g)  __ Fe 2 O 3 (s) Examples for Balancing __ Fe(s) + ____ O 2 (g)  __ Fe 2 O 3 (s) Notes: Always use the lowest possible integer numbers. If you get a fraction, multiply it out.

17 Examples for Balancing __ B 4 H 10 (g) + ____ O 2 (g)  __ B 2 O 3 (g) + __ H 2 O(g)

18 “Solid potassium reacts with water to form hydrogen gas and potassium hydroxide dissolved in solution.” Write and balance the chemical equation for this reaction. K(s) + H 2 O(l) → KOH(aq) + H 2 11 2 2 Examples for Balancing 2 1


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