1. f f When viewing a distant object through a converging lens, the image forms 2. at a position q < f ~ 4. at a position q > f ~ 3. at an exact position q = f 1. at a position q  0, close to the lens’ surface. 5. none of these!

2. f f When viewing a distant object through a converging lens, the image is 2. imaginary. 4. right-side up. 3. inverted. 1. real. 5. enlarged. 6. reduced.

3. A telescope has f o =985 mm and f e = 5 mm. Find the angular magnification of the telescope and its appropriate length. (a) (b)

4. The objective of a compound microscope has a focal length of f o = 0.40 cm while that of the eyepiece is f e = 3.0 cm. They are separated by L = 20.0 cm. A person with a normal eye (N = 25 cm) uses the microscope. a)Find the angular magnification. b)What is the greatest angular magnification achievable using the eyepiece alone (as a magnifying glass)?

5. collection of all points in a plane equidistant from a selected line called the directrix and point called the focus.

6. collection of all points in a plane whose distance from two fixed focii is a fixed, constant difference. 3 inches 2 inches R=4 inches R=3 inches

7. 4. at a position q > f ~ An object an infinity away comes to a focus right at the focal point. If p is a little less than infinity, then there’s a little left to 1/p so q is a little bit more than f. 3. inverted. 1. real. 6. reduced. Converging lenses can project images of objects outside their focal length to a screen or piece of film. Such images are real and always inverted. Above we decided q  f for p very large. Since M = - q/p notice with p>>q, the image is reduced (and the minus sign is you reminder it is inverted.