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Atomic Physics and Lasers The idea of a photon –Black body radiation –Photoelectric Effect The structure of the atom How does a Laser work? Interaction.

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Presentation on theme: "Atomic Physics and Lasers The idea of a photon –Black body radiation –Photoelectric Effect The structure of the atom How does a Laser work? Interaction."— Presentation transcript:

1 Atomic Physics and Lasers The idea of a photon –Black body radiation –Photoelectric Effect The structure of the atom How does a Laser work? Interaction of lasers with matter –Laser safety Applications –Spectroscopy, detection of art forgery, flow cytometry, eye surgery.

2 The idea of a photon What is light? A wave? Well yes, but…. The wave picture failed to explain physical phenomena including : the spectrum of a blackbody the photoelectric effect line spectra emitted by atoms

3 Light from a hot object... Vibrational motion of particles produces light (we call the light “Thermal Radiation”)

4 The first clue that something was very, very wrong…Blackbody radiation What is a blackbody? What is a blackbody? An object which emits or absorbs all the radiation incident on it. An object which emits or absorbs all the radiation incident on it. Typical black bodiesTypical black bodies A light globeA light globe A box with a small hole in it.A box with a small hole in it.

5 Example of a Blackbody A BLACKBODY

6 We measure radiation as a function of frequency (wavelength) Example of a Blackbody

7 A Thermal Spectrum How does a thermal spectrum change when you change T?

8 Thermal Radiation Wavelength where flux is a maximum Total energy emitted by an object (or Luminosity W/m 2 ) T = Temp. in Kelvin k = 2.898 x 10 -3 m.K  = 5.7 x 10 -8 W/(m 2.K 4 ) Stefan’s Law Wien’s Law

9

10 The spectra we have looked at are for ideal objects that are perfect absorbers and emitters of light Matter at some temperature T Light and matter interact Light is perfectly absorbed Light is later emitted A BLACKBODY Oscillators

11 Problems with wave theory of light Take a Blackbody with a temperature, T Calculate how the spectrum would look if light behaved like a wave (Lord Rayleigh) Compare with what is actually observed FluxFlux FluxFlux Okay here Not so good here

12 We measure radiation as a function of frequency (wavelength) Example of a Blackbody

13 Problems with wave theory of light Take a Blackbody with a temperature, T Calculate how the spectrum would look if light behaved like a wave (Lord Rayleigh) Compare with what is actually observed FluxFlux FluxFlux Okay here Not so good here

14 Max Plank Max Plank Solved the problem in 1900 Oscillators cannot have any energy! They can be in states with fixed amounts of energy. The oscillators change state by emitting/absorbing packets with a fixed amounts of energy

15 Atomic Physics/Blackbody Max Planck (1858-1947) was impressed by the fact Max Planck (1858-1947) was impressed by the fact spectrum of a black body was a universal property. spectrum of a black body was a universal property. To get agreement between the experiment and the theory, Planck proposed a radical idea: Light comes in packets of energy called photons, and the energy is given by E= nhf To get agreement between the experiment and the theory, Planck proposed a radical idea: Light comes in packets of energy called photons, and the energy is given by E= nhf E =nhf The birth of the quantum theory = Planck’s hypothesis

16 The birth of the Photon In 1906, Einstein proved that Planck’s radiation law could be derived only if the energy of each oscillator is quantized. E n = nhf ; n = 0, 1, 2, 3, 4,... h=Planck’s constant= 6.626x10 -34 J.s f=frequency in Hz; E=energy in Joules (J). Einstein introduced the idea that radiation Einstein introduced the idea that radiation equals a collection of discrete energy quanta. equals a collection of discrete energy quanta. G.N. Lewis in 1926 named quanta “Photons”. G.N. Lewis in 1926 named quanta “Photons”.

17 Atomic Physics/Photon The energy of each photon: E = hf h=Planck’s constant f=frequency Ex. 1. Yellow light has a frequency of 6.0 x 10 14 Hz. Determine the energy carried by a quantum of this light. If the energy flux of sunlight reaching the earth’s surface is 1000 Watts per square meter, find the number of photons in sunlight that reach the earth’s surface per square meter per second. Ans. 2.5 eV and 2.5 x 10 21 photons / m 2 /s

18 Lecture 12

19 Shining light onto metals METAL Light in Nothing happens

20 Shining light onto metals METAL Different Energy Light in electrons come out

21 The Photoelectric Effect When light is incident on certain metallic surfaces, electrons are emitted = the Photoelectric Effect (Serway and Jewett 28.2) Einstein: A single photon gives up all its energy to a single electron E Photon = E Free + E Kinetic Need at least this much energy to free the electron Whatever is left makes it move

22 The Photoelectric Effect Frequency of Light Kinetic Energy of electron fofo Threshold frequency Different metals

23 Application of Photoelectric Effect Soundtrack on Celluloid film To speaker Metal plate

24 Another Blow for classical physics: Line Spectra The emission spectrum from a rarefied gas through which an electrical discharge passes consists of sharp spectral lines. Each atom has its own characteristic spectrum. Hydrogen has four spectral lines in the visible region and many UV and IR lines not visible to the human eye. The wave picture failed to explain these lines.

25 Atomic Physics/Line spectra 400 500 600 400 500 600 (nm) (nm) H The absorption spectrum for hydrogen; dark absorption lines occur at the same wavelengths as emission lines. Emission spectrum for hydrogen

26 Atomic Physics/Line Spectra 1 1 1 1 1  R (   n  m 2 ) R =Rydberg Constant = 1.09737x10 7 m -1 Lyman UV -13.6n=1 BalmerVisible -3.39 n=2 Paschen IR IR n=3-1.51 -0.85 n=4

27 So what is light? Both a wave and a particle. It can be both, but in any experiment only its wave or its particle nature is manifested. (Go figure!)

28 Two revolutions: The Nature of light and the nature of matter Light has both a particle and wave nature: Wave nature: –Diffraction, interference Particle nature –Black body radiation, photoelectric effect, line spectra Need to revise the nature of matter (it turns out that matter also has both a particle and wave nature

29 The spectrum from a blackbody 0 2 4 6 8 10 (10 -7 m) (10 -7 m) Relative Intensity 5000K 6000K Rayleigh- Jeans Jeans Observed Empirically:Empirically:  max)T = constant, Hotter = whiter l The wave picture (Rayleigh- Jeans) failed to explain the distribution of the energy versus wavelength. UV Catastrophe!!!!

30 Photoelectric Effect METAL Light in e Electron out

31 The Photoelectric Effect Photoelectric effect=When light is incident on certain metallic surfaces, photoelectrons are emitted. Einstein applied the idea of light quanta: In a photoemission process, a single photon gives up all its energy to a single electron. Energy of photon = Energy to free electron + KE of emitted electron

32 Atomic Physics/Photoelectric Effect hf = KE +   =work function; minimum energy needed to extract an electron. KE f, Hz f0f0f0f0 x x x x fo = threshold freq below which no photoemission occurs.

33 Atomic Physics/The Photoelectric Effect-Application Light Source Sound Track  speaker Phototube The sound on a movie film

34 incident.Photoelectric effect=When light is incident on certain metallic surfaces, photoelectrons are emitted. Einstein applied the idea of light quanta: In a photoemission process, a single photon gives up all its energy to a single electron. Energy of photon = Energy to free electron + KE of emitted electron The photoelectric effect

35 The Photoelectric Effect experiment Metal surfaces in a vacuum eject electrons when irradiated by UV light.

36 PE effect: 5 Experimental observations 1. If V is kept constant, the photoelectric current i p increases with increasing UV intensity. 2. Photoelectrons are emitted less than 1 nS after surface illumination 3. For a given surface material, electrons are emitted only if the incident radiation is at or above a certain frequency, independent of intensity. 4. The maximum kinetic energy, K max, of the photoelectrons is independent of the light intensity I. 5. The maximum kinetic energy, K max of the photoelectrons depends on the frequency of the incident radiation.

37 Failure of Classcial Theory Observation 1: is in perfect agreement with classical expectations Observation 2: Cannot explain this. Very weak intensity should take longer to accumulate energy to eject electrons Observation 3: Cannot explain this either. Classically no relation between frequency and energy. Observations 4 and 5: Cannot be explained at all by classical E/M waves.. Bottom line: Classical explanation fails badly.

38 Quantum Explanation. Einstein expanded Planck’s hypothesis and applied it directly to EM radiation EM radiation consists of bundles of energy (photons) These photons have energy E = hf φ, If an electron absorbs a photon of energy E = hf in order to escape the surface it uses up energy φ, called the work function of the metal φ φ is the binding energy of the electron to the surface This satisfies all 5 experimental observations.

39 hf = KE + φ hf = KE + φ ( φ =work function; minimum energy needed to extract an electron.) ( φ =work function; minimum energy needed to extract an electron.) fo = threshold freq, below which no photoemission occurs fo = threshold freq, below which no photoemission occurs KE f (Hz) f0f0f0f0 x x x x. Photoelectric effect

40 Light Source Sound Track  speaker Phototube Application: Film soundtracks

41 Example: A GaN based UV detector 5m5m This is a photoconductor

42 Response Function of UV detector

43 Choose the material for the photon energy required. Band-Gap adjustable by adding Al from 3.4 to 6.2 eV Band gap is direct (= efficient) Material is robust

44 The structure of a LED/Photodiode

45 Characterization of Detectors NEP= noise equivalent power = noise current (A/  Hz)/Radiant sensitivity (A/W) D = detectivity =  area/NEP IR cut-off maximum current maximum reverse voltage Field of view Junction capacitance

46 Photomultipliers hf e e e e e e PE effect Secondary electron emission Electron multiplication

47 Photomultiplier tube Combines PE effect with electron multiplication to provide very high detection sensitivity Can detect single photons. -V hf e Anode Dynode

48 Microchannel plates The principle of the photomultiplier tube can be extended to an array of photomultipliers This way one can obtain spatial resolution Biggest application is in night vision goggles for military and civilian use

49 http://hea-www.harvard.edu/HRC/mcp/mcp.html MCPs consist of arrays of tiny tubes Each tube is coated with a photomultiplying film The tubes are about 10 microns wide Microchannel plates

50 MCP array structure http://hea-www.harvard.edu/HRC/mcp/mcp.html

51 MCP fabrication http://hea-www.harvard.edu/HRC/mcp/mcp.html

52 Disadvantages of Photomultiplers as sensors Need expensive and fiddly high vacuum equipment Expensive Fragile Bulky

53 Photoconductors As well as liberating electrons from the surface of materials, we can excite mobile electrons inside materials The most useful class of materials to do this are semiconductors The mobile electrons can be measured as a current proportional to the intensity of the incident radiation Need to understand semiconductors….

54 Photoelecric effect with Energy Bands EfEf E vac Semiconductor Band gap: E g =E c -E v Metal EfEf E vac EcEc EvEv

55 Photoconductivity Semiconductor Ef Evac Ec Ev e To amplifier

56 Photoconductors E g (~1 eV) can be made smaller than metal work functions  (~5 eV) Only photons with Energy E=hf>E g are detected This puts a lower limit on the frequency detected Broadly speaking, metals work with UV, semiconductors with optical

57 Band gap Engineering Semiconductors can be made with a band gap tailored for a particular frequency, depending on the application. Wide band gap semiconductors good for UV light III-V semiconductors promising new materials

58 Example: A GaN based UV detector 5m5m This is a photoconductor

59 Lecture 13

60 incident.Photoelectric effect=When light is incident on certain metallic surfaces, photoelectrons are emitted. Einstein applied the idea of light quanta: In a photoemission process, a single photon gives up all its energy to a single electron. Energy of photon = Energy to free electron + KE of emitted electron The photoelectric effect

61 The Photoelectric Effect experiment Metal surfaces in a vacuum eject electrons when irradiated by UV light.

62 PE effect: 5 Experimental observations 1. If V is kept constant, the photoelectric current i p increases with increasing UV intensity. 2. Photoelectrons are emitted less than 1 nS after surface illumination 3. For a given surface material, electrons are emitted only if the incident radiation is at or above a certain frequency, independent of intensity. 4. The maximum kinetic energy, K max, of the photoelectrons is independent of the light intensity I. 5. The maximum kinetic energy, K max of the photoelectrons depends on the frequency of the incident radiation.

63 Failure of Classcial Theory Observation 1: is in perfect agreement with classical expectations Observation 2: Cannot explain this. Very weak intensity should take longer to accumulate energy to eject electrons Observation 3: Cannot explain this either. Classically no relation between frequency and energy. Observations 4 and 5: Cannot be explained at all by classical E/M waves.. Bottom line: Classical explanation fails badly.

64 Quantum Explanation. Einstein expanded Planck’s hypothesis and applied it directly to EM radiation EM radiation consists of bundles of energy (photons) These photons have energy E = hf φ, If an electron absorbs a photon of energy E = hf in order to escape the surface it uses up energy φ, called the work function of the metal φ φ is the binding energy of the electron to the surface This satisfies all 5 experimental observations.

65 hf = KE + φ hf = KE + φ ( φ =work function; minimum energy needed to extract an electron.) ( φ =work function; minimum energy needed to extract an electron.) fo = threshold freq, below which no photoemission occurs fo = threshold freq, below which no photoemission occurs KE f (Hz) f0f0f0f0 x x x x. Photoelectric effect

66 Light Source Sound Track  speaker Phototube Application: Film soundtracks

67 Example: A GaN based UV detector 5m5m This is a photoconductor

68 Response Function of UV detector

69 Choose the material for the photon energy required. Band-Gap adjustable by adding Al from 3.4 to 6.2 eV Band gap is direct (= efficient) Material is robust

70 The structure of a LED/Photodiode

71 Characterization of Detectors NEP= noise equivalent power = noise current (A/  Hz)/Radiant sensitivity (A/W) D = detectivity =  area/NEP IR cut-off maximum current maximum reverse voltage Field of view Junction capacitance

72 Photoconductors As well as liberating electrons from the surface of materials, we can excite mobile electrons inside materials The most useful class of materials to do this are semiconductors The mobile electrons can be measured as a current proportional to the intensity of the incident radiation Need to understand semiconductors….

73 Photoelecric effect with Energy Bands EfEf E vac Semiconductor Band gap: E g =E c -E v Metal EfEf E vac EcEc EvEv

74 Photoconductivity Semiconductor Ef Evac Ec Ev e To amplifier

75 Photodiodes Photoconductors are not always sensitive enough Use a sandwich of doped semiconductors to create a “depletion region” with an intrinsic electric field We will return to these once we know more about atomic structure

76 Orientation Previously, we considered detection of photons. Next, we develop our understanding of photon generation We need to consider atomic structure of atoms and molecules

77 Line Emission Spectra The emission spectrum from an exited material (flame, electric discharge) consists of sharp spectral lines Each atom has its own characteristic spectrum. Hydrogen has four spectral lines in the visible region and many UV and IR lines not visible to the human eye The wave picture of electromagnetic radiation completely fails to explain these lines (!)

78 Atomic Physics/Line Spectra The absorption spectrum for hydrogen: dark absorption lines occur at the same wavelengths as emission lines.

79 Atomic Physics/Line Spectra

80 Rutherford’s Model

81 Problem 1: From the Classical Maxwell’s Equation, an accelerating electron emits radiation, losing energy. This radiation covers a continuous range in frequency, contradicting observed line spectra. Problem 2: Rutherford’s model failed to account for the stability of the atom. +Ze Fatal problems !

82 Bohr’s Model Assumptions: Electrons can exist only in stationary states Dynamical equilibrium governed by Newtonian Mechanics Transitions between different stationary states are accompanied by emission or absorption of radiation with frequency  E = hf

83 Transitions between states hf E3 E1 E2 E 3 - E 2 = hf Nucleus

84 How big is the Bohr Hydrogen Atom? R n =a 0 n 2 /Z 2 R n =radius of atomic orbit number n a 0 =Bohr radius = 0.0629 nm Z=atomic numner of element Exercise: What is the diameter of the hydrogen atom?

85 What energy Levels are allowed?

86 Exercise A hydrogen atom makes a transition between the n=2 state and the n=1 state. What is the wavelength of the light emitted? Step1: Find out the energy of the photon: E 1 =13.6 eV E 2 =13.6/4=3.4 eV hence the energy of the emitted photon is 10.2 eV Step 2: Convert energy into wavelength. E=hf, hence f=E/h =10.2*1.6x10 -19 /6.63x10 -34 = 2.46x10 15 Hz Step 3: Convert from frequency into wavelength: =c/f =3x10 8 /2.46x10 15 = 121.5 nm

87 Emission versus absorption E initial E final Emission hf = E final - E initial E final E initial Absorption hf = E final - E initial Explains Hydrogen spectra

88 What happens when we have more than one electron?

89 Apply rules: Pauli principle: only two electrons per energy level Fill the lowest energy levels first In real atoms the energy levels are more complicated than suggested by the Bohr theory Empty

90 Atomic Physics – X-rays How are X-rays produced? High energy electrons are fired at high atomic number targets. Electrons will be decelerated emitting X-rays. Energy of electron given by the applied potential (E=qV)

91 The X-ray spectrum consists of two parts: 1. A continuous spectrum 2. A series of sharp lines. 0.5 A 0 Intensity X-rays

92 The continuous spectrum depends on the voltage across the tube and does not depend on the target material. The continuous spectrum depends on the voltage across the tube and does not depend on the target material. This continuous spectrum is explained by the decelerating electron as it enters the metal This continuous spectrum is explained by the decelerating electron as it enters the metal 15 keV 25 keV 0.83 A 0 0.5 A 0 Intensity X-rays

93 Atomic Physics/X-rays The characteristic spectral lines depend on the target material. These Provides a unique signature of the target’s atomic structure Bohr’s theory was used to understand the origin of these lines

94 Atomic Physics – X-rays The K-shell corresponds to n=1 The L-shell corresponds to n=2 M is n=2, and so on

95 Atomic Spectra – X-rays Example: Estimate the wavelength of the X-ray emitted from a tantalum target when an electron from an n=4 state makes a transition to an empty n=1 state (Z tantalum =73)

96 Emission from tantalum

97 Atomic Physics – X-rays The X-ray is emitted when an e from an n=4 states falls into the empty n=1 state E i = -13.6Z 2 /n 2 = -(73) 2 (13.6 eV)/ 4 2 = -4529 eV E f = -13.6(73) 2 /1 2 = -72464 eV hf = E i - E f = 72474-4529= 67945 eV = 67.9 keV What is the wavelength? Ans = 0.18 Å

98 Using X-rays to probe structure X-rays have wavelengths of the order of 0.1 nm. Therefore we expect a grating with a periodicity of this magnitude to strongly diffract X-rays. Crystals have such a spacing! Indeed they do diffract X-rays according to Bragg’s law 2dsin  = n We will return to this later in the course when we discuss sensors of structure

99 Line Width Real materials emit or absorb light over a small range of wavelengths Example here is Neon

100 Stimulated emission E2E2 E1E1 E 2 - E 1 = hf Two identical photons Same - frequency - direction - phase - polarisation

101 Lasers LASER - acronym for –Light Amplification by Stimulated Emission of Radiation –produce high intensity power at a single frequency (i.e. monochromatic)

102 Principles of Lasers Usually have more atoms in low(est) energy levels Atomic systems can be pumped so that more atoms are in a higher energy level. Requires input of energy Called Population Inversion: achieved via Electric discharge Optically Direct current

103 Population inversion N2N2 N1N1 Energy Lots of atoms in this level Few atoms in this level Want N 2 - N 1 to be as large as possible

104 Population Inversion (3 level System) E2 (pump state), t 2 E1 (metastable- state), t s E1 (Ground state) Laser output hf Pump light hf o t s >t 2

105 Light Amplification Light amplified by passing light through a medium with a population inversion. Leads to stimulated emission

106 Laser

107 Requires a cavity enclosed by two mirrors. Provides amplification Improves spectral purity Initiated by “spontaneous emission”

108 Laser Cavity Cavity possess modes Analagous to standing waves on a string Correspond to specific wavelengths/frequencies These are amplified

109 Spectral output

110 Properties of Laser Light. Can be monochromatic Coherent Very intense Short pulses can be produced

111 Types of Lasers Large range of wavelengths available: Ammonia (microwave) MASER CO 2 (far infrared) Semiconductor (near-infrared, visible) Helium-Neon (visible) ArF – excimer (ultraviolet) Soft x-ray (free-electron, experimental)

112 Lecture 16

113 Molecular Spectroscopy Molecular Energy Levels –Vibrational Levels –Rotational levels Population of levels Intensities of transitions General features of spectroscopy An example: Raman Microscopy –Detection of art forgery –Local measurement of temperature

114 Molecular Energies Classical Quantum Energy E0E0 E4E4 E3E3 E2E2 E1E1

115 Molecular Energy Levels Translation Nuclear Spin Electronic Spin Rotation Vibration Electronic Orbital Increasing Energy etc. Electronic orbital Vibrational E total + E orbital + E vibrational + E rotational +….. Rotational

116 Molecular Vibrations Longitudinal Vibrations along molecular axis E=(n+1/2)hf where f is the classical frequency of the oscillator where k is the ‘spring constant Energy Levels equally spaced How can we estimate the spring constant? m M r k k = f (r)  = Mm/(M+m) Atomic mass concentrated at nucleus

117 Molecular Vibrations E vib =(n+1/2)hf  f =0.273eV/(1/2(h)) = 2.07x10 13 Hz To determine k we need μ μ=(Mm)/(M+m) =(1.008) 2 /2(1.008) amu =(0.504)1.66x10 -27 kg =0.837x10 -27 kg k= μ(2πf) 2 =576 N/m m M r K K = f (r)  = Mm/(M+m) Hydrogen molecules, H 2, have ground state vibrational energy of 0.273eV. Calculate force constant for the H 2 molecule ( mass of H is 1.008 amu)

118 Molecular Rotations Molecule can also rotate about its centre of mass v 1 =  R 1 ; v 2 =  R 2 L = M 1 v 1 R 1 + M 2 v 2 R 2 = (M 1 R 1 2 + M 2 R 2 2 )  = I  E KE = 1/2M 1 v 1 2 +1/2M 2 v 2 2 = 1/2I  2 R1R1 R2R2 M1M1 M2M2

119 Molecular Rotations Hence, E rot = L 2 /2I Now in fact L 2 is quantized and L 2 =l(l+1)h 2 /4  2 Hence E rot =l(l+1)(h 2 /4  2 )/2I Show that  E rot =(l+1) h 2 /4  2 /I. This is not equally spaced Typically  E rot =50meV (i.e for H 2 )

120 Populations of Energy Levels Depends on the relative size of kT and  E ΔE<<kT ΔE=kT ΔE>kT ΔEΔE (Virtually) all molecules in ground state States almost equally populated

121 Intensities of Transitions Quantum Mechanics predicts the degree to which any particular transition is allowed. Intensity also depends on the relative population of levels Strong absorption Weak emission Transition saturated hv 2hv hv

122 General Features of Spectroscopy Peak Height or intensity Frequency Lineshape or linewidth

123 Raman Spectroscopy Raman measures the vibrational modes of a solid The frequency of vibration depends on the atom masses and the forces between them. Shorter bond lengths mean stronger forces. m M r K f vib = (K/  ) 1/2 K = f(r)  = Mm/(M+m)

124 Raman Spectroscopy Cont... Laser In Sample Lens Monochromator CCD array Incident photons typically undergo elastic scattering. Small fraction undergo inelastic  energy transferred to molecule. Raman detects change in vibrational energy of a molecule.

125 Raman Microscope

126 Pb white Ti white Tom Roberts, ‘Track To The Harbour’ dated 1899 Detecting Art Forgery Ti-white became available only circa 1920. The Roberts painting shows clear evidence of Ti white but is dated 1899

127 Raman Spectroscopy and the Optical Measurement of Temperature Probability that a level is occupied is proportional to exp(  E/kT)

128 Lecture 17

129 Optical Fibre Sensors Non-Electrical Explosion-Proof (Often) Non-contact Light, small, snakey => “Remotable” Easy(ish) to install Immune to most EM noise Solid-State (no moving parts) Multiplexing/distributed sensors.

130 Applications Lots of Temp, Pressure, Chemistry Automated production lines/processes Automotive (T,P,Ch,Flow) Avionic (T,P,Disp,rotn,strain,liquid level) Climate control (T,P,Flow) Appliances (T,P) Environmental (Disp, T,P)

131 Optical Fibre Principles Cladding: glass or Polymer Core: glass, silica, sapphire TIR keeps light in fibre Different sorts of cladding: graded index, single index, step index.

132

133

134

135 Optical Fibre Principles Snell’s Law: n 1 sin  1 =n 2 sin  2  crit = arcsin(n 2 /n 1 ) Cladding reduces entry angle Only some angles (modes) allowed

136 Optical Fibre Modes

137 Phase and Intensity Modulation methods Optical fibre sensors fall into two types: –Intensity modulation uses the change in the amount of light that reaches a detector, say by breaking a fibre. –Phase Modulation uses the interference between two beams to detect tiny differences in path length, e.g. by thermal expansion.

138 Intensity modulated sensors: Axial displacement: 1/r 2 sensitivity Radial Displacement

139 Microbending (1) Microbending –Bent fibers lose energy –(Incident angle changes to less than critical angle)

140 Microbending (2): Microbending –“Jaws” close a bit, less transmission – Give jaws period of light to enhance effect Applications: – Strain gauge – Traffic counting

141 More Intensity modulated sensors Frustrated Total Internal Reflection: –Evanescent wave bridges small gap and so light propagates –As the fibers move (say car passes), the gap increases and light is reflected Evanescent Field Decay @514nm

142 More Intensity modulated sensors Frustrated Total Internal Reflection: Chemical sensing –Evanescent wave extends into cladding –Change in refractive index of cladding will modify output intensity

143 Disadvantages of intensity modulated sensors Light losses can be interpreted as change in measured property −Bends in fibres −Connecting fibres −Couplers Variation in source power

144 Phase modulated sensors Bragg modulators: –Periodic changes in refractive index –Bragg wavelenght (λ b ) which satisfies λ b =2nD is reflected –Separation (D) of same order as than mode wavelength

145 Phase modulated sensors Multimode fibre with broad input spectrum Strain or heating changes n so reflected wavelength changes Suitable for distributed sensing λ b =2nD Period,D

146 Phase modulated sensors – distributed sensors

147 Temperature Sensors Reflected phosphorescent signal depends on Temperature Can use BBR, but need sapphire waveguides since silica/glass absorbs IR

148 Phase modulated sensors Fabry-Perot etalons: –Two reflecting surfaces separated by a few wavelengths –Air gap forms part of etalon –Gap fills with hydrogen, changing refractive index of etalon and changing allowed transmitted frequencies.

149 Digital switches and counters Measure number of air particles in air or water gap by drop in intensity –Environmental monitoring Detect thin film thickness in manufacturing –Quality control Counting things –Production line, traffic.

150 NSOM/AFM Combined SEM - 70nm aperture Bent NSOM/AFM Probe Optical resolution determined by diffraction limit (~λ) Illuminating a sample with the "near-field" of a small light source. Can construct optical images with resolution well beyond usual "diffraction limit", (typically ~50 nm.)

151 NSOM Setup Ideal for thin films or coatings which are several hundred nm thick on transparent substrates (e.g., a round, glass cover slip).

152 Lecture 12

153 Atomic Physics and Lasers The idea of a photon –Black body radiation –Photoelectric Effect The structure of the atom How does a Laser work? Interaction of lasers with matter –Laser safety Applications –Spectroscopy, detection of art forgery, flow cytometry, eye surgery.

154 The idea of a photon What is light? A wave? Well yes, but…. The wave picture failed to explain physical phenomena including : the spectrum of a blackbody the photoelectric effect line spectra emitted by atoms

155 Light from a hot object... Vibrational motion of particles produces light (we call the light “Thermal Radiation”)

156 The first clue that something was very, very wrong…Blackbody radiation What is a blackbody? What is a blackbody? An object which emits or absorbs all the radiation incident on it. An object which emits or absorbs all the radiation incident on it. Typical black bodiesTypical black bodies A light globeA light globe A box with a small hole in it.A box with a small hole in it.

157 Example of a Blackbody A BLACKBODY

158 We measure radiation as a function of frequency (wavelength) Example of a Blackbody

159 A Thermal Spectrum How does a thermal spectrum change when you change T?

160 Thermal Radiation Wavelength where flux is a maximum Total energy emitted by an object (or Luminosity W/m 2 ) T = Temp. in Kelvin k = 2.898 x 10 -3 m.K  = 5.7 x 10 -8 W/(m 2.K 4 ) Stefan’s Law Wien’s Law

161

162 The spectra we have looked at are for ideal objects that are perfect absorbers and emitters of light Matter at some temperature T Light and matter interact Light is perfectly absorbed Light is later emitted A BLACKBODY Oscillators

163 Problems with wave theory of light Take a Blackbody with a temperature, T Calculate how the spectrum would look if light behaved like a wave (Lord Rayleigh) Compare with what is actually observed FluxFlux FluxFlux Okay here Not so good here

164 Max Plank Max Plank Solved the problem in 1900 Oscillators cannot have any energy! They can be in states with fixed amounts of energy. The oscillators change state by emitting/absorbing packets with a fixed amounts of energy

165 Atomic Physics/Blackbody Max Planck (1858-1947) was impressed by the fact Max Planck (1858-1947) was impressed by the fact spectrum of a black body was a universal property. spectrum of a black body was a universal property. To get agreement between the experiment and the theory, Planck proposed a radical idea: Light comes in packets of energy called photons, and the energy is given by E= nhf To get agreement between the experiment and the theory, Planck proposed a radical idea: Light comes in packets of energy called photons, and the energy is given by E= nhf E =nhf The birth of the quantum theory = Planck’s hypothesis

166 The birth of the Photon In 1906, Einstein proved that Planck’s radiation law could be derived only if the energy of each oscillator is quantized. E n = nhf ; n = 0, 1, 2, 3, 4,... h=Planck’s constant= 6.626x10 -34 J.s f=frequency in Hz; E=energy in Joules (J). Einstein introduced the idea that radiation Einstein introduced the idea that radiation equals a collection of discrete energy quanta. equals a collection of discrete energy quanta. G.N. Lewis in 1926 named quanta “Photons”. G.N. Lewis in 1926 named quanta “Photons”.

167 Atomic Physics/Photon The energy of each photon: E = hf h=Planck’s constant f=frequency Ex. 1. Yellow light has a frequency of 6.0 x 10 14 Hz. Determine the energy carried by a quantum of this light. If the energy flux of sunlight reaching the earth’s surface is 1000 Watts per square meter, find the number of photons in sunlight that reach the earth’s surface per square meter per second. Ans. 2.5 eV and 2.5 x 10 21 photons / m 2 /s

168 Shining light onto metals METAL Light in Nothing happens

169 Shining light onto metals METAL Different Energy Light in electrons come out

170 The Photoelectric Effect When light is incident on certain metallic surfaces, electrons are emitted = the Photoelectric Effect (Serway and Jewett 28.2) Einstein: A single photon gives up all its energy to a single electron E Photon = E Free + E Kinetic Need at least this much energy to free the electron Whatever is left makes it move

171 The Photoelectric Effect Frequency of Light Kinetic Energy of electron fofo Threshold frequency Different metals

172 Application of Photoelectric Effect Soundtrack on Celluloid film To speaker Metal plate

173 Another Blow for classical physics: Line Spectra The emission spectrum from a rarefied gas through which an electrical discharge passes consists of sharp spectral lines. Each atom has its own characteristic spectrum. Hydrogen has four spectral lines in the visible region and many UV and IR lines not visible to the human eye. The wave picture failed to explain these lines.

174 Atomic Physics/Line spectra 400 500 600 400 500 600 (nm) (nm) H The absorption spectrum for hydrogen; dark absorption lines occur at the same wavelengths as emission lines. Emission spectrum for hydrogen

175 Atomic Physics/Line Spectra 1 1 1 1 1  R (   n  m 2 ) R =Rydberg Constant = 1.09737x10 7 m -1 Lyman UV -13.6n=1 BalmerVisible -3.39 n=2 Paschen IR IR n=3-1.51 -0.85 n=4

176 So what is light? Both a wave and a particle. It can be both, but in any experiment only its wave or its particle nature is manifested. (Go figure!)

177 Two revolutions: The Nature of light and the nature of matter Light has both a particle and wave nature: Wave nature: –Diffraction, interference Particle nature –Black body radiation, photoelectric effect, line spectra Need to revise the nature of matter (it turns out that matter also has both a particle and wave nature

178 The spectrum from a blackbody 0 2 4 6 8 10 (10 -7 m) (10 -7 m) Relative Intensity 5000K 6000K Rayleigh- Jeans Jeans Observed Empirically:Empirically:  max)T = constant, Hotter = whiter l The wave picture (Rayleigh- Jeans) failed to explain the distribution of the energy versus wavelength. UV Catastrophe!!!!

179 Photoelectric Effect METAL Light in e Electron out

180 The Photoelectric Effect Photoelectric effect=When light is incident on certain metallic surfaces, photoelectrons are emitted. Einstein applied the idea of light quanta: In a photoemission process, a single photon gives up all its energy to a single electron. Energy of photon = Energy to free electron + KE of emitted electron

181 Atomic Physics/Photoelectric Effect hf = KE +   =work function; minimum energy needed to extract an electron. KE f, Hz f0f0f0f0 x x x x fo = threshold freq below which no photoemission occurs.

182 Atomic Physics/The Photoelectric Effect-Application Light Source Sound Track  speaker Phototube The sound on a movie film

183 Lecture 13

184 incident.Photoelectric effect=When light is incident on certain metallic surfaces, photoelectrons are emitted. Einstein applied the idea of light quanta: In a photoemission process, a single photon gives up all its energy to a single electron. Energy of photon = Energy to free electron + KE of emitted electron The photoelectric effect

185 The Photoelectric Effect experiment Metal surfaces in a vacuum eject electrons when irradiated by UV light.

186 PE effect: 5 Experimental observations 1. If V is kept constant, the photoelectric current i p increases with increasing UV intensity. 2. Photoelectrons are emitted less than 1 nS after surface illumination 3. For a given surface material, electrons are emitted only if the incident radiation is at or above a certain frequency, independent of intensity. 4. The maximum kinetic energy, K max, of the photoelectrons is independent of the light intensity I. 5. The maximum kinetic energy, K max of the photoelectrons depends on the frequency of the incident radiation.

187 Failure of Classcial Theory Observation 1: is in perfect agreement with classical expectations Observation 2: Cannot explain this. Very weak intensity should take longer to accumulate energy to eject electrons Observation 3: Cannot explain this either. Classically no relation between frequency and energy. Observations 4 and 5: Cannot be explained at all by classical E/M waves.. Bottom line: Classical explanation fails badly.

188 Quantum Explanation. Einstein expanded Planck’s hypothesis and applied it directly to EM radiation EM radiation consists of bundles of energy (photons) These photons have energy E = hf φ, If an electron absorbs a photon of energy E = hf in order to escape the surface it uses up energy φ, called the work function of the metal φ φ is the binding energy of the electron to the surface This satisfies all 5 experimental observations.

189 hf = KE + φ hf = KE + φ ( φ =work function; minimum energy needed to extract an electron.) ( φ =work function; minimum energy needed to extract an electron.) fo = threshold freq, below which no photoemission occurs fo = threshold freq, below which no photoemission occurs KE f (Hz) f0f0f0f0 x x x x. Photoelectric effect

190 Light Source Sound Track  speaker Phototube Application: Film soundtracks

191 Example: A GaN based UV detector 5m5m This is a photoconductor

192 Response Function of UV detector

193 Choose the material for the photon energy required. Band-Gap adjustable by adding Al from 3.4 to 6.2 eV Band gap is direct (= efficient) Material is robust

194 The structure of a LED/Photodiode

195 Characterization of Detectors NEP= noise equivalent power = noise current (A/  Hz)/Radiant sensitivity (A/W) D = detectivity =  area/NEP IR cut-off maximum current maximum reverse voltage Field of view Junction capacitance

196 Photomultipliers hf e e e e e e PE effect Secondary electron emission Electron multiplication

197 Photomultiplier tube Combines PE effect with electron multiplication to provide very high detection sensitivity Can detect single photons. -V hf e Anode Dynode

198 Microchannel plates The principle of the photomultiplier tube can be extended to an array of photomultipliers This way one can obtain spatial resolution Biggest application is in night vision goggles for military and civilian use

199 http://hea-www.harvard.edu/HRC/mcp/mcp.html MCPs consist of arrays of tiny tubes Each tube is coated with a photomultiplying film The tubes are about 10 microns wide Microchannel plates

200 MCP array structure http://hea-www.harvard.edu/HRC/mcp/mcp.html

201 MCP fabrication http://hea-www.harvard.edu/HRC/mcp/mcp.html

202 Disadvantages of Photomultiplers as sensors Need expensive and fiddly high vacuum equipment Expensive Fragile Bulky

203 Photoconductors As well as liberating electrons from the surface of materials, we can excite mobile electrons inside materials The most useful class of materials to do this are semiconductors The mobile electrons can be measured as a current proportional to the intensity of the incident radiation Need to understand semiconductors….

204 Photoelecric effect with Energy Bands EfEf E vac Semiconductor Band gap: E g =E c -E v Metal EfEf E vac EcEc EvEv

205 Photoconductivity Semiconductor Ef Evac Ec Ev e To amplifier

206 Photoconductors E g (~1 eV) can be made smaller than metal work functions  (~5 eV) Only photons with Energy E=hf>E g are detected This puts a lower limit on the frequency detected Broadly speaking, metals work with UV, semiconductors with optical

207 Band gap Engineering Semiconductors can be made with a band gap tailored for a particular frequency, depending on the application. Wide band gap semiconductors good for UV light III-V semiconductors promising new materials

208 Example: A GaN based UV detector 5m5m This is a photoconductor

209 Response Function of UV detector

210 Choose the material for the photon energy required. Band-Gap adjustable by adding Al from 3.4 to 6.2 eV Band gap is direct (= efficient) Material is robust

211 Photodiodes Photoconductors are not always sensitive enough Use a sandwich of doped semiconductors to create a “depletion region” with an intrinsic electric field We will return to these once we know more about atomic structure

212 The structure of a LED/Photodiode

213 Characterization of Detectors NEP= noise equivalent power = noise current (A/  Hz)/Radiant sensitivity (A/W) D = detectivity =  area/NEP IR cut-off maximum current maximum reverse voltage Field of view Junction capacitance

214 Lecture 15

215 Orientation Previously, we considered detection of photons. Next, we develop our understanding of photon generation We need to consider atomic structure of atoms and molecules

216 Line Emission Spectra The emission spectrum from an exited material (flame, electric discharge) consists of sharp spectral lines Each atom has its own characteristic spectrum. Hydrogen has four spectral lines in the visible region and many UV and IR lines not visible to the human eye The wave picture of electromagnetic radiation completely fails to explain these lines (!)

217 Atomic Physics/Line Spectra The absorption spectrum for hydrogen: dark absorption lines occur at the same wavelengths as emission lines.

218 Atomic Physics/Line Spectra

219 Rutherford’s Model

220 Problem 1: From the Classical Maxwell’s Equation, an accelerating electron emits radiation, losing energy. This radiation covers a continuous range in frequency, contradicting observed line spectra. Problem 2: Rutherford’s model failed to account for the stability of the atom. +Ze Fatal problems !

221 Bohr’s Model Assumptions: Electrons can exist only in stationary states Dynamical equilibrium governed by Newtonian Mechanics Transitions between different stationary states are accompanied by emission or absorption of radiation with frequency  E = hf

222 Transitions between states hf E3 E1 E2 E 3 - E 2 = hf Nucleus

223 How big is the Bohr Hydrogen Atom? R n =a 0 n 2 /Z 2 R n =radius of atomic orbit number n a 0 =Bohr radius = 0.0629 nm Z=atomic numner of element Exercise: What is the diameter of the hydrogen atom?

224 What energy Levels are allowed?

225 Exercise A hydrogen atom makes a transition between the n=2 state and the n=1 state. What is the wavelength of the light emitted? Step1: Find out the energy of the photon: E 1 =13.6 eV E 2 =13.6/4=3.4 eV hence the energy of the emitted photon is 10.2 eV Step 2: Convert energy into wavelength. E=hf, hence f=E/h =10.2*1.6x10 -19 /6.63x10 -34 = 2.46x10 15 Hz Step 3: Convert from frequency into wavelength: =c/f =3x10 8 /2.46x10 15 = 121.5 nm

226 Emission versus absorption E initial E final Emission hf = E final - E initial E final E initial Absorption hf = E final - E initial Explains Hydrogen spectra

227 What happens when we have more than one electron?

228 Apply rules: Pauli principle: only two electrons per energy level Fill the lowest energy levels first In real atoms the energy levels are more complicated than suggested by the Bohr theory Empty

229 What happens when we have more than one electron? Apply rules: Pauli principle: only two electrons per energy level Fill the lowest energy levels first In real atoms the energy levels are more complicated than suggested by the Bohr theory Empty

230 Atomic Physics – X-rays How are X-rays produced? High energy electrons are fired at high atomic number targets. Electrons will be decelerated emitting X-rays. Energy of electron given by the applied potential (E=qV)

231 The X-ray spectrum consists of two parts: 1. A continuous spectrum 2. A series of sharp lines. 0.5 A 0 Intensity X-rays

232 The continuous spectrum depends on the voltage across the tube and does not depend on the target material. The continuous spectrum depends on the voltage across the tube and does not depend on the target material. This continuous spectrum is explained by the decelerating electron as it enters the metal This continuous spectrum is explained by the decelerating electron as it enters the metal 15 keV 25 keV 0.83 A 0 0.5 A 0 Intensity X-rays

233 Atomic Physics/X-rays The characteristic spectral lines depend on the target material. These Provides a unique signature of the target’s atomic structure Bohr’s theory was used to understand the origin of these lines

234 Atomic Physics – X-rays The K-shell corresponds to n=1 The L-shell corresponds to n=2 M is n=2, and so on

235 Atomic Spectra – X-rays Example: Estimate the wavelength of the X-ray emitted from a tantalum target when an electron from an n=4 state makes a transition to an empty n=1 state (Z tantalum =73)

236 Emission from tantalum

237 Atomic Physics – X-rays The X-ray is emitted when an e from an n=4 states falls into the empty n=1 state E i = -13.6Z 2 /n 2 = -(73) 2 (13.6 eV)/ 4 2 = -4529 eV E f = -13.6(73) 2 /1 2 = -72464 eV hf = E i - E f = 72474-4529= 67945 eV = 67.9 keV What is the wavelength? Ans = 0.18 Å

238 Using X-rays to probe structure X-rays have wavelengths of the order of 0.1 nm. Therefore we expect a grating with a periodicity of this magnitude to strongly diffract X-rays. Crystals have such a spacing! Indeed they do diffract X-rays according to Bragg’s law 2dsin  = n We will return to this later in the course when we discuss sensors of structure

239 Line Width Real materials emit or absorb light over a small range of wavelengths Example here is Neon

240 Stimulated emission E2E2 E1E1 E 2 - E 1 = hf Two identical photons Same - frequency - direction - phase - polarisation

241 Lasers LASER - acronym for –Light Amplification by Stimulated Emission of Radiation –produce high intensity power at a single frequency (i.e. monochromatic)

242 Principles of Lasers Usually have more atoms in low(est) energy levels Atomic systems can be pumped so that more atoms are in a higher energy level. Requires input of energy Called Population Inversion: achieved via Electric discharge Optically Direct current

243 Population inversion N2N2 N1N1 Energy Lots of atoms in this level Few atoms in this level Want N 2 - N 1 to be as large as possible

244 Population Inversion (3 level System) E2 (pump state), t 2 E1 (metastable- state), t s E1 (Ground state) Laser output hf Pump light hf o t s >t 2

245 Light Amplification Light amplified by passing light through a medium with a population inversion. Leads to stimulated emission

246 Laser

247 Requires a cavity enclosed by two mirrors. Provides amplification Improves spectral purity Initiated by “spontaneous emission”

248 Laser Cavity Cavity possess modes Analagous to standing waves on a string Correspond to specific wavelengths/frequencies These are amplified

249 Spectral output

250 Properties of Laser Light. Can be monochromatic Coherent Very intense Short pulses can be produced

251 Types of Lasers Large range of wavelengths available: Ammonia (microwave) MASER CO 2 (far infrared) Semiconductor (near-infrared, visible) Helium-Neon (visible) ArF – excimer (ultraviolet) Soft x-ray (free-electron, experimental)

252 Lecture 16

253 Molecular Spectroscopy Molecular Energy Levels –Vibrational Levels –Rotational levels Population of levels Intensities of transitions General features of spectroscopy An example: Raman Microscopy –Detection of art forgery –Local measurement of temperature

254 Molecular Energies Classical Quantum Energy E0E0 E4E4 E3E3 E2E2 E1E1

255 Molecular Energy Levels Translation Nuclear Spin Electronic Spin Rotation Vibration Electronic Orbital Increasing Energy etc. Electronic orbital Vibrational E total + E orbital + E vibrational + E rotational +….. Rotational

256 Molecular Vibrations Longitudinal Vibrations along molecular axis E=(n+1/2)hf where f is the classical frequency of the oscillator where k is the ‘spring constant Energy Levels equally spaced How can we estimate the spring constant? m M r k k = f (r)  = Mm/(M+m) Atomic mass concentrated at nucleus

257 Molecular Vibrations E vib =(n+1/2)hf  f =0.273eV/(1/2(h)) = 2.07x10 13 Hz To determine k we need μ μ=(Mm)/(M+m) =(1.008) 2 /2(1.008) amu =(0.504)1.66x10 -27 kg =0.837x10 -27 kg k= μ(2πf) 2 =576 N/m m M r K K = f (r)  = Mm/(M+m) Hydrogen molecules, H 2, have ground state vibrational energy of 0.273eV. Calculate force constant for the H 2 molecule ( mass of H is 1.008 amu)

258 Molecular Rotations Molecule can also rotate about its centre of mass v 1 =  R 1 ; v 2 =  R 2 L = M 1 v 1 R 1 + M 2 v 2 R 2 = (M 1 R 1 2 + M 2 R 2 2 )  = I  E KE = 1/2M 1 v 1 2 +1/2M 2 v 2 2 = 1/2I  2 R1R1 R2R2 M1M1 M2M2

259 Molecular Rotations Hence, E rot = L 2 /2I Now in fact L 2 is quantized and L 2 =l(l+1)h 2 /4  2 Hence E rot =l(l+1)(h 2 /4  2 )/2I Show that  E rot =(l+1) h 2 /4  2 /I. This is not equally spaced Typically  E rot =50meV (i.e for H 2 )

260 Populations of Energy Levels Depends on the relative size of kT and  E ΔE<<kT ΔE=kT ΔE>kT ΔEΔE (Virtually) all molecules in ground state States almost equally populated

261 Intensities of Transitions Quantum Mechanics predicts the degree to which any particular transition is allowed. Intensity also depends on the relative population of levels Strong absorption Weak emission Transition saturated hv 2hv hv

262 General Features of Spectroscopy Peak Height or intensity Frequency Lineshape or linewidth

263 Raman Spectroscopy Raman measures the vibrational modes of a solid The frequency of vibration depends on the atom masses and the forces between them. Shorter bond lengths mean stronger forces. m M r K f vib = (K/  ) 1/2 K = f(r)  = Mm/(M+m)

264 Raman Spectroscopy Cont... Laser In Sample Lens Monochromator CCD array Incident photons typically undergo elastic scattering. Small fraction undergo inelastic  energy transferred to molecule. Raman detects change in vibrational energy of a molecule.

265 Raman Microscope

266 Pb white Ti white Tom Roberts, ‘Track To The Harbour’ dated 1899 Detecting Art Forgery Ti-white became available only circa 1920. The Roberts painting shows clear evidence of Ti white but is dated 1899

267 Raman Spectroscopy and the Optical Measurement of Temperature Probability that a level is occupied is proportional to exp(  E/kT)

268 Population inversion N2N2 N1N1 Energy Lots of atoms in this level Few atoms in this level Want N 2 - N 1 to be as large as possible

269 Population Inversion (3 level System) E2 (pump state), t 2 E1 (metastable- state), t s E1 (Ground state) Laser output hf Pump light hf o t s >t 2

270 Light Amplification Light amplified by passing light through a medium with a population inversion. Leads to stimulated emission

271 Laser

272 Requires a cavity enclosed by two mirrors. Provides amplification Improves spectral purity Initiated by “spontaneous emission”

273 Laser Cavity Cavity possess modes Analagous to standing waves on a string Correspond to specific wavelengths/frequencies These are amplified

274 Spectral output

275 Lecture 17

276 Optical Fibre Sensors Non-Electrical Explosion-Proof (Often) Non-contact Light, small, snakey => “Remotable” Easy(ish) to install Immune to most EM noise Solid-State (no moving parts) Multiplexing/distributed sensors.

277 Applications Lots of Temp, Pressure, Chemistry Automated production lines/processes Automotive (T,P,Ch,Flow) Avionic (T,P,Disp,rotn,strain,liquid level) Climate control (T,P,Flow) Appliances (T,P) Environmental (Disp, T,P)

278 Optical Fibre Principles Cladding: glass or Polymer Core: glass, silica, sapphire TIR keeps light in fibre Different sorts of cladding: graded index, single index, step index.

279

280

281

282 Optical Fibre Principles Snell’s Law: n 1 sin  1 =n 2 sin  2  crit = arcsin(n 2 /n 1 ) Cladding reduces entry angle Only some angles (modes) allowed

283 Optical Fibre Modes

284 Phase and Intensity Modulation methods Optical fibre sensors fall into two types: –Intensity modulation uses the change in the amount of light that reaches a detector, say by breaking a fibre. –Phase Modulation uses the interference between two beams to detect tiny differences in path length, e.g. by thermal expansion.

285 Intensity modulated sensors: Axial displacement: 1/r 2 sensitivity Radial Displacement

286 Microbending (1) Microbending –Bent fibers lose energy –(Incident angle changes to less than critical angle)

287 Microbending (2): Microbending –“Jaws” close a bit, less transmission – Give jaws period of light to enhance effect Applications: – Strain gauge – Traffic counting

288 More Intensity modulated sensors Frustrated Total Internal Reflection: –Evanescent wave bridges small gap and so light propagates –As the fibers move (say car passes), the gap increases and light is reflected Evanescent Field Decay @514nm

289 More Intensity modulated sensors Frustrated Total Internal Reflection: Chemical sensing –Evanescent wave extends into cladding –Change in refractive index of cladding will modify output intensity

290 Disadvantages of intensity modulated sensors Light losses can be interpreted as change in measured property −Bends in fibres −Connecting fibres −Couplers Variation in source power

291 Phase modulated sensors Bragg modulators: –Periodic changes in refractive index –Bragg wavelenght (λ b ) which satisfies λ b =2nD is reflected –Separation (D) of same order as than mode wavelength

292 Phase modulated sensors Multimode fibre with broad input spectrum Strain or heating changes n so reflected wavelength changes Suitable for distributed sensing λ b =2nD Period,D

293 Phase modulated sensors – distributed sensors

294 Temperature Sensors Reflected phosphorescent signal depends on Temperature Can use BBR, but need sapphire waveguides since silica/glass absorbs IR

295 Phase modulated sensors Fabry-Perot etalons: –Two reflecting surfaces separated by a few wavelengths –Air gap forms part of etalon –Gap fills with hydrogen, changing refractive index of etalon and changing allowed transmitted frequencies.

296 Digital switches and counters Measure number of air particles in air or water gap by drop in intensity –Environmental monitoring Detect thin film thickness in manufacturing –Quality control Counting things –Production line, traffic.

297 NSOM/AFM Combined SEM - 70nm aperture Bent NSOM/AFM Probe Optical resolution determined by diffraction limit (~λ) Illuminating a sample with the "near-field" of a small light source. Can construct optical images with resolution well beyond usual "diffraction limit", (typically ~50 nm.)

298 NSOM Setup Ideal for thin films or coatings which are several hundred nm thick on transparent substrates (e.g., a round, glass cover slip).

299 Lecture 18 Not sure what goes here

300 Atomic Physics – X-rays How are X-rays produced? High energy electrons are fired at high atomic number targets. Electrons will be decelerated emitting X-rays. Energy of electron given by the applied potential (E=qV)

301 The X-ray spectrum consists of two parts: 1. A continuous spectrum 2. A series of sharp lines. 0.5 A 0 Intensity X-rays

302 The continuous spectrum depends on the voltage across the tube and does not depend on the target material. The continuous spectrum depends on the voltage across the tube and does not depend on the target material. This continuous spectrum is explained by the decelerating electron as it enters the metal This continuous spectrum is explained by the decelerating electron as it enters the metal 15 keV 25 keV 0.83 A 0 0.5 A 0 Intensity X-rays

303 Atomic Physics/X-rays The characteristic spectral lines depend on the target material. These Provides a unique signature of the target’s atomic structure Bohr’s theory was used to understand the origin of these lines

304 Atomic Physics – X-rays The K-shell corresponds to n=1 The L-shell corresponds to n=2 M is n=2, and so on

305 Atomic Spectra – X-rays Example: Estimate the wavelength of the X-ray emitted from a tantalum target when an electron from an n=4 state makes a transition to an empty n=1 state (Z tantalum =73)

306 Emission from tantalum

307 Atomic Physics – X-rays The X-ray is emitted when an e from an n=4 states falls into the empty n=1 state E i = -13.6Z 2 /n 2 = -(73) 2 (13.6 eV)/ 4 2 = -4529 eV E f = -13.6(73) 2 /1 2 = -72464 eV hf = E i - E f = 72474-4529= 67945 eV = 67.9 keV What is the wavelength? Ans = 0.18 Å

308 Using X-rays to probe structure X-rays have wavelengths of the order of 0.1 nm. Therefore we expect a grating with a periodicity of this magnitude to strongly diffract X-rays. Crystals have such a spacing! Indeed they do diffract X-rays according to Bragg’s law 2dsin  = n We will return to this later in the course when we discuss sensors of structure

309 Line Width Real materials emit or absorb light over a small range of wavelengths Example here is Neon

310 Stimulated emission E2E2 E1E1 E 2 - E 1 = hf Two identical photons Same - frequency - direction - phase - polarisation

311 Lasers LASER - acronym for –Light Amplification by Stimulated Emission of Radiation –produce high intensity power at a single frequency (i.e. monochromatic)

312 Principles of Lasers Usually have more atoms in low(est) energy levels Atomic systems can be pumped so that more atoms are in a higher energy level. Requires input of energy Called Population Inversion: achieved via Electric discharge Optically Direct current

313 Population inversion N2N2 N1N1 Energy Lots of atoms in this level Few atoms in this level Want N 2 - N 1 to be as large as possible

314 Population Inversion (3 level System) E2 (pump state), t 2 E1 (metastable- state), t s E1 (Ground state) Laser output hf Pump light hf o t s >t 2

315 Light Amplification Light amplified by passing light through a medium with a population inversion. Leads to stimulated emission

316 Laser

317 Requires a cavity enclosed by two mirrors. Provides amplification Improves spectral purity Initiated by “spontaneous emission”

318 Laser Cavity Cavity possess modes Analagous to standing waves on a string Correspond to specific wavelengths/frequencies These are amplified

319 Spectral output

320 Lecture 16

321 Molecular Spectroscopy Molecular Energy Levels –Vibrational Levels –Rotational levels Population of levels Intensities of transitions General features of spectroscopy An example: Raman Microscopy –Detection of art forgery –Local measurement of temperature

322 Molecular Energies Classical Quantum Energy E0E0 E4E4 E3E3 E2E2 E1E1

323 Molecular Energy Levels Translation Nuclear Spin Electronic Spin Rotation Vibration Electronic Orbital Increasing Energy etc. Electronic orbital Vibrational E total + E orbital + E vibrational + E rotational +….. Rotational

324 Molecular Vibrations Longitudinal Vibrations along molecular axis E=(n+1/2)hf where f is the classical frequency of the oscillator where k is the ‘spring constant Energy Levels equally spaced How can we estimate the spring constant? m M r k k = f (r)  = Mm/(M+m) Atomic mass concentrated at nucleus

325 Molecular Vibrations E vib =(n+1/2)hf  f =0.273eV/(1/2(h)) = 2.07x10 13 Hz To determine k we need μ μ=(Mm)/(M+m) =(1.008) 2 /2(1.008) amu =(0.504)1.66x10 -27 kg =0.837x10 -27 kg k= μ(2πf) 2 =576 N/m m M r K K = f (r)  = Mm/(M+m) Hydrogen molecules, H 2, have ground state vibrational energy of 0.273eV. Calculate force constant for the H 2 molecule ( mass of H is 1.008 amu)

326 Molecular Rotations Molecule can also rotate about its centre of mass v 1 =  R 1 ; v 2 =  R 2 L = M 1 v 1 R 1 + M 2 v 2 R 2 = (M 1 R 1 2 + M 2 R 2 2 )  = I  E KE = 1/2M 1 v 1 2 +1/2M 2 v 2 2 = 1/2I  2 R1R1 R2R2 M1M1 M2M2

327 Molecular Rotations Hence, E rot = L 2 /2I Now in fact L 2 is quantized and L 2 =l(l+1)h 2 /4  2 Hence E rot =l(l+1)(h 2 /4  2 )/2I Show that  E rot =(l+1) h 2 /4  2 /I. This is not equally spaced Typically  E rot =50meV (i.e for H 2 )

328 Populations of Energy Levels Depends on the relative size of kT and  E ΔE<<kT ΔE=kT ΔE>kT ΔEΔE (Virtually) all molecules in ground state States almost equally populated

329 Intensities of Transitions Quantum Mechanics predicts the degree to which any particular transition is allowed. Intensity also depends on the relative population of levels Strong absorption Weak emission Transition saturated hv 2hv hv

330 General Features of Spectroscopy Peak Height or intensity Frequency Lineshape or linewidth

331 Raman Spectroscopy Raman measures the vibrational modes of a solid The frequency of vibration depends on the atom masses and the forces between them. Shorter bond lengths mean stronger forces. m M r K f vib = (K/  ) 1/2 K = f(r)  = Mm/(M+m)

332 Raman Spectroscopy Cont... Laser In Sample Lens Monochromator CCD array Incident photons typically undergo elastic scattering. Small fraction undergo inelastic  energy transferred to molecule. Raman detects change in vibrational energy of a molecule.

333 Raman Microscope

334 Pb white Ti white Tom Roberts, ‘Track To The Harbour’ dated 1899 Detecting Art Forgery Ti-white became available only circa 1920. The Roberts painting shows clear evidence of Ti white but is dated 1899

335 Raman Spectroscopy and the Optical Measurement of Temperature Probability that a level is occupied is proportional to exp(  E/kT)

336 Lecture 17

337 Optical Fibre Sensors Non-Electrical Explosion-Proof (Often) Non-contact Light, small, snakey => “Remotable” Easy(ish) to install Immune to most EM noise Solid-State (no moving parts) Multiplexing/distributed sensors.

338 Applications Lots of Temp, Pressure, Chemistry Automated production lines/processes Automotive (T,P,Ch,Flow) Avionic (T,P,Disp,rotn,strain,liquid level) Climate control (T,P,Flow) Appliances (T,P) Environmental (Disp, T,P)

339 Optical Fibre Principles Cladding: glass or Polymer Core: glass, silica, sapphire TIR keeps light in fibre Different sorts of cladding: graded index, single index, step index.

340

341

342

343 Optical Fibre Principles Snell’s Law: n 1 sin  1 =n 2 sin  2  crit = arcsin(n 2 /n 1 ) Cladding reduces entry angle Only some angles (modes) allowed

344 Optical Fibre Modes

345 Phase and Intensity Modulation methods Optical fibre sensors fall into two types: –Intensity modulation uses the change in the amount of light that reaches a detector, say by breaking a fibre. –Phase Modulation uses the interference between two beams to detect tiny differences in path length, e.g. by thermal expansion.

346 Intensity modulated sensors: Axial displacement: 1/r 2 sensitivity Radial Displacement

347 Microbending (1) Microbending –Bent fibers lose energy –(Incident angle changes to less than critical angle)

348 Microbending (2): Microbending –“Jaws” close a bit, less transmission – Give jaws period of light to enhance effect Applications: – Strain gauge – Traffic counting

349 More Intensity modulated sensors Frustrated Total Internal Reflection: –Evanescent wave bridges small gap and so light propagates –As the fibers move (say car passes), the gap increases and light is reflected Evanescent Field Decay @514nm

350 More Intensity modulated sensors Frustrated Total Internal Reflection: Chemical sensing –Evanescent wave extends into cladding –Change in refractive index of cladding will modify output intensity

351 Disadvantages of intensity modulated sensors Light losses can be interpreted as change in measured property −Bends in fibres −Connecting fibres −Couplers Variation in source power

352 Phase modulated sensors Bragg modulators: –Periodic changes in refractive index –Bragg wavelenght (λ b ) which satisfies λ b =2nD is reflected –Separation (D) of same order as than mode wavelength

353 Phase modulated sensors Multimode fibre with broad input spectrum Strain or heating changes n so reflected wavelength changes Suitable for distributed sensing λ b =2nD Period,D

354 Phase modulated sensors – distributed sensors

355 Temperature Sensors Reflected phosphorescent signal depends on Temperature Can use BBR, but need sapphire waveguides since silica/glass absorbs IR

356 Phase modulated sensors Fabry-Perot etalons: –Two reflecting surfaces separated by a few wavelengths –Air gap forms part of etalon –Gap fills with hydrogen, changing refractive index of etalon and changing allowed transmitted frequencies.

357 Digital switches and counters Measure number of air particles in air or water gap by drop in intensity –Environmental monitoring Detect thin film thickness in manufacturing –Quality control Counting things –Production line, traffic.

358 NSOM/AFM Combined SEM - 70nm aperture Bent NSOM/AFM Probe Optical resolution determined by diffraction limit (~λ) Illuminating a sample with the "near-field" of a small light source. Can construct optical images with resolution well beyond usual "diffraction limit", (typically ~50 nm.)

359 NSOM Setup Ideal for thin films or coatings which are several hundred nm thick on transparent substrates (e.g., a round, glass cover slip).

360 Lecture 18 Not sure what goes here

361 Atomic Physics – X-rays How are X-rays produced? High energy electrons are fired at high atomic number targets. Electrons will be decelerated emitting X-rays. Energy of electron given by the applied potential (E=qV)

362 The X-ray spectrum consists of two parts: 1. A continuous spectrum 2. A series of sharp lines. 0.5 A 0 Intensity X-rays

363 The continuous spectrum depends on the voltage across the tube and does not depend on the target material. The continuous spectrum depends on the voltage across the tube and does not depend on the target material. This continuous spectrum is explained by the decelerating electron as it enters the metal This continuous spectrum is explained by the decelerating electron as it enters the metal 15 keV 25 keV 0.83 A 0 0.5 A 0 Intensity X-rays

364 Atomic Physics/X-rays The characteristic spectral lines depend on the target material. These Provides a unique signature of the target’s atomic structure Bohr’s theory was used to understand the origin of these lines

365 Atomic Physics – X-rays The K-shell corresponds to n=1 The L-shell corresponds to n=2 M is n=2, and so on

366 Atomic Spectra – X-rays Example: Estimate the wavelength of the X-ray emitted from a tantalum target when an electron from an n=4 state makes a transition to an empty n=1 state (Z tantalum =73)

367 Emission from tantalum

368 Atomic Physics – X-rays The X-ray is emitted when an e from an n=4 states falls into the empty n=1 state E i = -13.6Z 2 /n 2 = -(73) 2 (13.6 eV)/ 4 2 = -4529 eV E f = -13.6(73) 2 /1 2 = -72464 eV hf = E i - E f = 72474-4529= 67945 eV = 67.9 keV What is the wavelength? Ans = 0.18 Å

369 Using X-rays to probe structure X-rays have wavelengths of the order of 0.1 nm. Therefore we expect a grating with a periodicity of this magnitude to strongly diffract X-rays. Crystals have such a spacing! Indeed they do diffract X-rays according to Bragg’s law 2dsin  = n We will return to this later in the course when we discuss sensors of structure

370 Line Width Real materials emit or absorb light over a small range of wavelengths Example here is Neon

371 Stimulated emission E2E2 E1E1 E 2 - E 1 = hf Two identical photons Same - frequency - direction - phase - polarisation

372 Lasers LASER - acronym for –Light Amplification by Stimulated Emission of Radiation –produce high intensity power at a single frequency (i.e. monochromatic)

373 Principles of Lasers Usually have more atoms in low(est) energy levels Atomic systems can be pumped so that more atoms are in a higher energy level. Requires input of energy Called Population Inversion: achieved via Electric discharge Optically Direct current

374 Properties of Laser Light. Can be monochromatic Coherent Very intense Short pulses can be produced

375 Types of Lasers Large range of wavelengths available: Ammonia (microwave) MASER CO 2 (far infrared) Semiconductor (near-infrared, visible) Helium-Neon (visible) ArF – excimer (ultraviolet) Soft x-ray (free-electron, experimental)

376 Lecture 16

377 Molecular Spectroscopy Molecular Energy Levels –Vibrational Levels –Rotational levels Population of levels Intensities of transitions General features of spectroscopy An example: Raman Microscopy –Detection of art forgery –Local measurement of temperature

378 Molecular Energies Classical Quantum Energy E0E0 E4E4 E3E3 E2E2 E1E1

379 Molecular Energy Levels Translation Nuclear Spin Electronic Spin Rotation Vibration Electronic Orbital Increasing Energy etc. Electronic orbital Vibrational E total + E orbital + E vibrational + E rotational +….. Rotational

380 Molecular Vibrations Longitudinal Vibrations along molecular axis E=(n+1/2)hf where f is the classical frequency of the oscillator where k is the ‘spring constant Energy Levels equally spaced How can we estimate the spring constant? m M r k k = f (r)  = Mm/(M+m) Atomic mass concentrated at nucleus

381 Molecular Vibrations E vib =(n+1/2)hf  f =0.273eV/(1/2(h)) = 2.07x10 13 Hz To determine k we need μ μ=(Mm)/(M+m) =(1.008) 2 /2(1.008) amu =(0.504)1.66x10 -27 kg =0.837x10 -27 kg k= μ(2πf) 2 =576 N/m m M r K K = f (r)  = Mm/(M+m) Hydrogen molecules, H 2, have ground state vibrational energy of 0.273eV. Calculate force constant for the H 2 molecule ( mass of H is 1.008 amu)

382 Molecular Rotations Molecule can also rotate about its centre of mass v 1 =  R 1 ; v 2 =  R 2 L = M 1 v 1 R 1 + M 2 v 2 R 2 = (M 1 R 1 2 + M 2 R 2 2 )  = I  E KE = 1/2M 1 v 1 2 +1/2M 2 v 2 2 = 1/2I  2 R1R1 R2R2 M1M1 M2M2

383 Molecular Rotations Hence, E rot = L 2 /2I Now in fact L 2 is quantized and L 2 =l(l+1)h 2 /4  2 Hence E rot =l(l+1)(h 2 /4  2 )/2I Show that  E rot =(l+1) h 2 /4  2 /I. This is not equally spaced Typically  E rot =50meV (i.e for H 2 )

384 Populations of Energy Levels Depends on the relative size of kT and  E ΔE<<kT ΔE=kT ΔE>kT ΔEΔE (Virtually) all molecules in ground state States almost equally populated

385 Intensities of Transitions Quantum Mechanics predicts the degree to which any particular transition is allowed. Intensity also depends on the relative population of levels Strong absorption Weak emission Transition saturated hv 2hv hv

386 General Features of Spectroscopy Peak Height or intensity Frequency Lineshape or linewidth

387 Raman Spectroscopy Raman measures the vibrational modes of a solid The frequency of vibration depends on the atom masses and the forces between them. Shorter bond lengths mean stronger forces. m M r K f vib = (K/  ) 1/2 K = f(r)  = Mm/(M+m)

388 Raman Spectroscopy Cont... Laser In Sample Lens Monochromator CCD array Incident photons typically undergo elastic scattering. Small fraction undergo inelastic  energy transferred to molecule. Raman detects change in vibrational energy of a molecule.

389 Raman Microscope

390 Pb white Ti white Tom Roberts, ‘Track To The Harbour’ dated 1899 Detecting Art Forgery Ti-white became available only circa 1920. The Roberts painting shows clear evidence of Ti white but is dated 1899

391 Raman Spectroscopy and the Optical Measurement of Temperature Probability that a level is occupied is proportional to exp(  E/kT)

392 Lecture 16

393 Molecular Spectroscopy Molecular Energy Levels –Vibrational Levels –Rotational levels Population of levels Intensities of transitions General features of spectroscopy An example: Raman Microscopy –Detection of art forgery –Local measurement of temperature

394 Molecular Energies Classical Quantum Energy E0E0 E4E4 E3E3 E2E2 E1E1

395 Molecular Energy Levels Translation Nuclear Spin Electronic Spin Rotation Vibration Electronic Orbital Increasing Energy etc. Electronic orbital Vibrational E total + E orbital + E vibrational + E rotational +….. Rotational

396 Molecular Vibrations Longitudinal Vibrations along molecular axis E=(n+1/2)hf where f is the classical frequency of the oscillator where k is the ‘spring constant Energy Levels equally spaced How can we estimate the spring constant? m M r k k = f (r)  = Mm/(M+m) Atomic mass concentrated at nucleus

397 Molecular Vibrations E vib =(n+1/2)hf  f =0.273eV/(1/2(h)) = 2.07x10 13 Hz To determine k we need μ μ=(Mm)/(M+m) =(1.008) 2 /2(1.008) amu =(0.504)1.66x10 -27 kg =0.837x10 -27 kg k= μ(2πf) 2 =576 N/m m M r K K = f (r)  = Mm/(M+m) Hydrogen molecules, H 2, have ground state vibrational energy of 0.273eV. Calculate force constant for the H 2 molecule ( mass of H is 1.008 amu)

398 Molecular Rotations Molecule can also rotate about its centre of mass v 1 =  R 1 ; v 2 =  R 2 L = M 1 v 1 R 1 + M 2 v 2 R 2 = (M 1 R 1 2 + M 2 R 2 2 )  = I  E KE = 1/2M 1 v 1 2 +1/2M 2 v 2 2 = 1/2I  2 R1R1 R2R2 M1M1 M2M2

399 Molecular Rotations Hence, E rot = L 2 /2I Now in fact L 2 is quantized and L 2 =l(l+1)h 2 /4  2 Hence E rot =l(l+1)(h 2 /4  2 )/2I Show that  E rot =(l+1) h 2 /4  2 /I. This is not equally spaced Typically  E rot =50meV (i.e for H 2 )

400 Populations of Energy Levels Depends on the relative size of kT and  E ΔE<<kT ΔE=kT ΔE>kT ΔEΔE (Virtually) all molecules in ground state States almost equally populated

401 Intensities of Transitions Quantum Mechanics predicts the degree to which any particular transition is allowed. Intensity also depends on the relative population of levels Strong absorption Weak emission Transition saturated hv 2hv hv

402 General Features of Spectroscopy Peak Height or intensity Frequency Lineshape or linewidth

403 Raman Spectroscopy Raman measures the vibrational modes of a solid The frequency of vibration depends on the atom masses and the forces between them. Shorter bond lengths mean stronger forces. m M r K f vib = (K/  ) 1/2 K = f(r)  = Mm/(M+m)

404 Raman Spectroscopy Cont... Laser In Sample Lens Monochromator CCD array Incident photons typically undergo elastic scattering. Small fraction undergo inelastic  energy transferred to molecule. Raman detects change in vibrational energy of a molecule.

405 Raman Microscope

406 Pb white Ti white Tom Roberts, ‘Track To The Harbour’ dated 1899 Detecting Art Forgery Ti-white became available only circa 1920. The Roberts painting shows clear evidence of Ti white but is dated 1899

407 Raman Spectroscopy and the Optical Measurement of Temperature Probability that a level is occupied is proportional to exp(  E/kT)

408 Lecture 17

409 Optical Fibre Sensors Non-Electrical Explosion-Proof (Often) Non-contact Light, small, snakey => “Remotable” Easy(ish) to install Immune to most EM noise Solid-State (no moving parts) Multiplexing/distributed sensors.

410 Applications Lots of Temp, Pressure, Chemistry Automated production lines/processes Automotive (T,P,Ch,Flow) Avionic (T,P,Disp,rotn,strain,liquid level) Climate control (T,P,Flow) Appliances (T,P) Environmental (Disp, T,P)

411 Optical Fibre Principles Cladding: glass or Polymer Core: glass, silica, sapphire TIR keeps light in fibre Different sorts of cladding: graded index, single index, step index.

412

413

414

415 Optical Fibre Principles Snell’s Law: n 1 sin  1 =n 2 sin  2  crit = arcsin(n 2 /n 1 ) Cladding reduces entry angle Only some angles (modes) allowed

416 Optical Fibre Modes

417 Phase and Intensity Modulation methods Optical fibre sensors fall into two types: –Intensity modulation uses the change in the amount of light that reaches a detector, say by breaking a fibre. –Phase Modulation uses the interference between two beams to detect tiny differences in path length, e.g. by thermal expansion.

418 Intensity modulated sensors: Axial displacement: 1/r 2 sensitivity Radial Displacement

419 Microbending (1) Microbending –Bent fibers lose energy –(Incident angle changes to less than critical angle)

420 Microbending (2): Microbending –“Jaws” close a bit, less transmission – Give jaws period of light to enhance effect Applications: – Strain gauge – Traffic counting

421 More Intensity modulated sensors Frustrated Total Internal Reflection: –Evanescent wave bridges small gap and so light propagates –As the fibers move (say car passes), the gap increases and light is reflected Evanescent Field Decay @514nm

422 More Intensity modulated sensors Frustrated Total Internal Reflection: Chemical sensing –Evanescent wave extends into cladding –Change in refractive index of cladding will modify output intensity

423 Disadvantages of intensity modulated sensors Light losses can be interpreted as change in measured property −Bends in fibres −Connecting fibres −Couplers Variation in source power

424 Phase modulated sensors Bragg modulators: –Periodic changes in refractive index –Bragg wavelenght (λ b ) which satisfies λ b =2nD is reflected –Separation (D) of same order as than mode wavelength

425 Phase modulated sensors Multimode fibre with broad input spectrum Strain or heating changes n so reflected wavelength changes Suitable for distributed sensing λ b =2nD Period,D

426 Phase modulated sensors – distributed sensors

427 Temperature Sensors Reflected phosphorescent signal depends on Temperature Can use BBR, but need sapphire waveguides since silica/glass absorbs IR

428 Phase modulated sensors Fabry-Perot etalons: –Two reflecting surfaces separated by a few wavelengths –Air gap forms part of etalon –Gap fills with hydrogen, changing refractive index of etalon and changing allowed transmitted frequencies.

429 Digital switches and counters Measure number of air particles in air or water gap by drop in intensity –Environmental monitoring Detect thin film thickness in manufacturing –Quality control Counting things –Production line, traffic.

430 NSOM/AFM Combined SEM - 70nm aperture Bent NSOM/AFM Probe Optical resolution determined by diffraction limit (~λ) Illuminating a sample with the "near-field" of a small light source. Can construct optical images with resolution well beyond usual "diffraction limit", (typically ~50 nm.)

431 NSOM Setup Ideal for thin films or coatings which are several hundred nm thick on transparent substrates (e.g., a round, glass cover slip).

432 Lecture 18 Not sure what goes here


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