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2.5 The Point-Slope Form of the Equation of a Line.

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Presentation on theme: "2.5 The Point-Slope Form of the Equation of a Line."— Presentation transcript:

1 2.5 The Point-Slope Form of the Equation of a Line

2 Point-Slope Form of the Equation of a Line
The point-slope equation of a nonvertical line with slope m that passes through the point is Blitzer, Algebra for College Students, 6e – Slide #2 Section 2.5

3 Point-Slope Form EXAMPLE Write the point-slope form and then the slope-intercept form of the equation of the line with slope -3 that passes through the point (2,-4). SOLUTION Substitute the given values Simplify This is the equation of the line in point-slope form. Distribute Subtract 4 from both sides This is the equation of the line in slope-intercept form. Blitzer, Algebra for College Students, 6e – Slide #3 Section 2.5

4 Point-Slope Form EXAMPLE Write the point-slope form and then the slope-intercept form of the equation of the line that passes through the points (2,-4) and (-3,6). SOLUTION First I must find the slope of the line. That is done as follows: Blitzer, Algebra for College Students, 6e – Slide #4 Section 2.5

5 Point-Slope Form CONTINUED Now I can find the two forms of the equation of the line. In find the point-slope form of the line, I can use either point provided. I’ll use (2,-4). Substitute the given values Simplify This is the equation of the line in point-slope form. Distribute Subtract 4 from both sides This is the equation of the line in slope-intercept form. Blitzer, Algebra for College Students, 6e – Slide #5 Section 2.5

6 Equations of Lines Equations of Lines Standard Form Ax + By = C
Slope-Intercept Form y = mx + b Horizontal Line y = b Vertical Line x = a Point-slope Form Blitzer, Algebra for College Students, 6e – Slide #6 Section 2.5

7 Deciding which form to use:
Begin with the slope-intercept form if you know: Begin with the point-slope form if you know: The slope of the line and the y-intercept or Two points on the line, one of which is the y -intercept The slope of the line and a point on the line other than the y-intercept Two points on the line, neither of which is the y-intercept Blitzer, Algebra for College Students, 6e – Slide #7 Section 2.5

8 Parallel and Perpendicular Lines
1) If two lines are parallel, then they have the same slope. 2) If two nonvertical lines are perpendicular, then the product of their slopes is -1. 3) A horizontal line having zero slope is perpendicular to a vertical line having undefined slope. Blitzer, Algebra for College Students, 6e – Slide #8 Section 2.5

9 Parallel and Perpendicular Lines
One line is perpendicular to another line if its slope is the negative reciprocal of the slope of the other line. The following lines are perpendicular: y = 2x + 6 and y = -(1/2)x – 4 are perpendicular. y = -4x +5 and y = (1/4)x + 3 are perpendicular. Blitzer, Algebra for College Students, 6e – Slide #9 Section 2.5

10 Parallel and Perpendicular Lines
Two lines are parallel if they have the same slope. The following lines are parallel: y = 2x + 6 and y = 2x – 4 are parallel. y = -4x +5 and y = -4x + 3 are parallel. Blitzer, Algebra for College Students, 6e – Slide #10 Section 2.5

11 Parallel and Perpendicular Lines
EXAMPLE Write an equation of the line passing through (2,-4) and parallel to the line whose equation is y = -3x + 5. SOLUTION Since the line I want to represent is parallel to the given line, they have the same slope. Therefore the slope of the new line is also m = -3. Therefore, the equation of the new line is: y – 2 = -3(x – (-4)) Substitute the given values y – 2 = -3(x + 4) Simplify y – 2 = -3x - 12 Distribute y = -3x - 10 Add 2 to both sides Blitzer, Algebra for College Students, 6e – Slide #11 Section 2.5

12 Parallel and Perpendicular Lines
Your Turn Write an equation of the line passing through (-2,5) and parallel to the line whose equation is y = -3x + 1. Blitzer, Algebra for College Students, 6e – Slide #12 Section 2.5

13 Parallel and Perpendicular Lines
EXAMPLE Write an equation of the line passing through (2,-4) and perpendicular to the line whose equation is y = -3x + 5. SOLUTION The slope of the given equation is m = -3. Therefore, the slope of the new line is , since Therefore, the using the slope m = and the point (2,-4), the equation of the line is as follows: Blitzer, Algebra for College Students, 6e – Slide #13 Section 2.5

14 Parallel and Perpendicular Lines
CONTINUED Substitute the given values Simplify Distribute Subtract 4 from both sides Common Denominators Common Denominators Simplify Blitzer, Algebra for College Students, 6e – Slide #14 Section 2.5

15 Parallel and Perpendicular Lines
Your Turn Write an equation of the line passing through (3,-5) and perpendicular to the line whose equation is x + 4y =8. Blitzer, Algebra for College Students, 6e – Slide #15 Section 2.5

16 2.5 Assignment p. 150 (2-44 even, even)


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