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Solving Linear Systems (in three variables)

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Presentation on theme: "Solving Linear Systems (in three variables)"— Presentation transcript:

1 Solving Linear Systems (in three variables)
Section 1.4 beginning on page 30

2 A Linear Equation in Three Variables

3 What Does This Look Like?

4 Solving Algebraically

5 Examples Solve each system:
(−1,5,2) 𝑁𝑜 𝑆𝑜𝑙𝑢𝑡𝑖𝑜𝑛 Infinitely Many Solutions (𝑥,𝑥+3,0)

6 Real Life Problem Example 4: An amphitheater charges $75 for each seat in Section A, $55 for each seat in Section B, and $30 for each lawn seat. There are three times as many seats in Section B as in Section A. The revenue from selling all 23,000 seats is $870,000. How many seats are in each section of the amphitheater? Declare your variables: X = Number of seats in Section A Y = Number of seats in Section B Z = Number of seats on the Lawn Write three equations using the information provided: One equation can represent the relationship between the number of seats in section b and section a One equation can represent the total number of seats One equation can represent the revenue from selling out 𝑦=3𝑥 𝑥+𝑦+𝑧=23,000 75𝑥+55𝑦+30𝑧=870,000 There are 1500 seats in Section A, 4500 seats in Section B, and lawn seats.

7 Monitoring Progress Solve the system. 𝑥−2𝑦+𝑧=−11 3𝑥+2𝑦−𝑧=7 −𝑥+2𝑦+4𝑧=−9
2) 𝑥+𝑦−𝑧=−1 4𝑥+4𝑦−4𝑧=−2 3𝑥+2𝑦+𝑧=0 3) 𝑥+𝑦+𝑧=8 𝑥−𝑦+𝑧=8 2𝑥+𝑦+2𝑧=16 (−1,3,−4) 𝑁𝑜 𝑆𝑜𝑙𝑢𝑡𝑖𝑜𝑛 (8−𝑧,0,𝑧)


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