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Selection on an Index of Traits I= X b j z j =b T z æ 2 I =æ(b T z;b T z)=b T æ(z;z)b=b T Pbæ 2 A I =æ A (b T z;b T z)=b T æ A (z;z)b=b T Gb h 2 I = æ.

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Presentation on theme: "Selection on an Index of Traits I= X b j z j =b T z æ 2 I =æ(b T z;b T z)=b T æ(z;z)b=b T Pbæ 2 A I =æ A (b T z;b T z)=b T æ A (z;z)b=b T Gb h 2 I = æ."— Presentation transcript:

1 Selection on an Index of Traits I= X b j z j =b T z æ 2 I =æ(b T z;b T z)=b T æ(z;z)b=b T Pbæ 2 A I =æ A (b T z;b T z)=b T æ A (z;z)b=b T Gb h 2 I = æ 2 A I æ 2 I = b T Gb b T Pb A common way to select on a number of traits at once is to base selection decisions on a simple index of trait values, The resulting phenotypic and additive-genetic variance for this synthetic trait are; This gives the resulting heritability of the index as

2 Class problem Enter G and P matrices from Example 33.1 in R. For Compute additive and phenotypic variance, and h 2 for the index

3 R I ={h 2 I æ I ={¢ b T Gb b T Pb p b T Pb={¢ b T Gb p b T Pb S j = { æ I X k b k P jk S= { æ I Pb Thus, the response in the index due to selection is How does selection on I translate into selection on the underlying traits? Since R = GP -1 S, the response vector for the underlying means becomes R=GP °1 S= { æ I Gb={¢ Gb p b T Pb -

4 Class problem For a selection intensity of i = 2.06 (upper 5% selected) compute the response in the index and the vectors of selection differentials and responses (S and R) for the vector of traits.

5 Changes in the additive variance of the index Bulmer’s equation holds for the index: We can also apply multivariate Bulmer to follow the changes in the variance-covariance matrix of the components:

6 The Smith-Hazel Index Suppose we wish the maximize the response on the linear combination a T z of traits This is done by selecting those individuals with the largest breeding value for this index, namely Hence, we wish to find a phenotypic index I = b T z So that the correlation between H and I in an Individual is maximized. Key: This vector of weights b is typically rather different from a!

7 The Smith-Hazel Index Smith and Hazel show that the maximal gain is obtained by selection on the index b T z where Thus, to maximize the response in a T z in the next generation, we choose those parents with the largest breeding value for this trait, H = a T g. This is done by choosing individuals with the largest values of I = b s T z.

8 In-class problem We wish to improve the index Compute the Smith-Hazel weights (using previous P, G) Compute the response for the SH index with truncation selection saving the upper 5% Compare this response to that selecting directly on I=a T z

9 Heritability index : b i = a i h 2 i Other indices Estimated index:Base-index: Elston (or weight-free) index: Retrospective index: since R = Gb, b = G -1 R

10 Problem with Smith-Hazel Require accurate estimate of P, G! Values of P, G change each generation from LD! Dealing with negative eigenvalues of H = P -1 G Bending:

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12 Restricted and Desired-gains Indices Instead of maximizing the response on a index, we may (additionally) wish to restrict change in certain traits or have a desired gain in specific traits in mind Suppose for our soybean bean data, we wish no response in trait 1 Class Problem: Suppose weights are a T = (0,1,1), i.e, no weight on trait 1. Compute the response in trait one under this index.

13 Morely (1955): Change trait z 1 while z 2 constant Want b 1, b 2 such that no response in trait 2 Setting b 1 = 1 and solving gives weights Note sign typo in Equation 33.36

14 Kempthorne-Nordskog restricted index Suppose we wish the first k traits to be unchanged. Since response of an index is proportional to Gb, the constraint is CGb r =0, where C is an m X k matrix with ones on the diagonals and zeros elsewhere. Kempthorne-Nordskog showed that b r is obtained by where G r = CG

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17 Tallis restriction index More generally, suppose we specify the desired gains for k combinations of traits, Here the constraint is CR = CGb r = d Solution is

18 Desired-gain indices Suppose we desire a gain of R, then since R = Gb, The desired-gains index is b = G -1 R

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20 Class problem Compute b for desired gains (in our soybean traits) of (1,-2,0)

21 Non-linear indices Care is required in considering the improvement goals when using a nonlinear merit function, as apparently subtle differences in the desired outcomes can become critical A related concern is whether we wish to maximize the additive Genetic value in merit in the parents or in their offspring. Again, with a linear index these are equivalent, as the mean breeding value of the parents u equals the mean value in their offspring. This is not the case with nonlinear merit.

22 Quadratic selection index

23 Linearization

24 Fitting the best linear index to a nonlinear merit function

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26 Sets of response vectors and selection differentials Given a fixed selection intensity i, we would like to know the set of possible R (response vectors) or S (selection vectors) Substituting the above value of b into recovers Hence, This equation describes a quadratic surface of possible, R values, Similarly,

27 Key: Optimal weights a function of intensity of selection

28 Sequential Approaches for Multitrait selection Tandem Selection Independent Culling Selection of extremes Index selection generally optimal, but may be economic reasons for other approaches

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30 Multistage selection Selecting on traits that appear in different life stages Optimal selection schemes Cotterill and James optimal 2-stage. Select 1st on x, (save p 1 ), then then on y (save p 2 = p/p 1 ). Goal optimize the breeding value for merit g.

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