Download presentation

Published byMorgan Wilson Modified over 2 years ago

1
**Reciprocal lattice How to construct reciprocal lattice**

Meaning of reciprocal lattice Relation between reciprocal lattice and diffraction Geometrical relation between reciprocal lattice and original lattice

2
**parallel d2 d1 Does it really form a lattice? Draw it to convince**

How to construct a reciprocal lattice from a crystal (1) Pick a set of planes in a crystal parallel Plane set 2 d2 d1 Plane set 1 Does it really form a lattice? Draw it to convince yourself! Plane set 3 d3

3
**Example: a monoclinic crystal **

Reciprocal lattice (a* and c*) on the plane containing a and c vectors. (b is out of the plane) c b a (-100) (100) (001) c (102) (001) c (002) O (002) a O O a (00-2) c (00-2) (002) O a (001) c c* (101) c (002) (002) * O a a* (10-1) (00-1) a (00-2) 2D form a 3-D reciprocal lattice

4
**Lattice point in reciprocal space**

Integer Lattice points in real space

5
**Reciprocal lattice cells for cubic crystals:**

Simple cubic: z y x (002)? z z (010) (100) y y a a x x a (110) (001) y y Simple cubic x x

6
**Base centered cubic (BCC):**

z y x

7
(111) (111) O O (111) FCC corner Up and down O (222) F and B L and R

8
**Vector: dot and cross product v v.u = |v||u|cos **

You should do the same for a FCC and show it forms a BCC lattice! (Homework!) Vector: dot and cross product v v.u = |v||u|cos Projection of v onto u and times each other (scaler)! u |v|cos vu = |v||u|sin w |v|sin |v||u|sin is the area of the parallelogram. w v and u u

9
**Relationships between a, b, c and a*, b*, c*:**

Monoclinic: plane y-axis (b) : c c*. c c* Similarly, b d001 a cc* = |c*|ccos, |c*| = 1/d001 ccos = d001 cc* = 1

10
** The Weiss zone law or zone equation: **

Similarly, aa* = 1 and bb* =1. c* //ab, Define c* = k (ab), k : a constant. cc* = 1 ck(ab) = 1 k = 1/[c(ab)]=1/V. V: volume of the unit cell Similarly, one gets The Weiss zone law or zone equation: A plane (hkl) lies in a zone [uvw] (the plane contains the direction [uvw]). d*hkl (hkl) d*hkl ruvw = 0

11
**Define the unit vector in the d*hkl direction i, d*hkl**

nth plane ruvw Define the unit vector in the d*hkl direction i, d*hkl r2 uvw r1

12
** Reciprocal Lattice: Fourier transform of the spatial**

wavefunction of the original lattice wave process (e. g. electromagnetic) in the crystal Crystal: periodic Physical properties function of a crystal Crystal translation vector Periodic function Exponential Fourier Series

13
**If k (reciprocal) lattice ; T original lattice!**

u, v, w: integer Translation vectors of the original crystal lattice for all T If h, k, l: integer Vectors of the reciprocal lattice always integer If k (reciprocal) lattice ; T original lattice! Vice versa!

14
**k (in general): momentum space vector; G: reciprocal lattice points**

In crystallography In SSP k (in general): momentum space vector; G: reciprocal lattice points

15
**Proof: the reciprocal lattice of BCC is FCC**

Use primitive translation vectors only BCC FCC x y z corner Up and down F and B L and R

16
BCC

17
**The vector set is the same as the FCC primitive**

translation vector. Unit of the reciprocal lattice is 1/length.

18
**Mathematics of Interference**

Sum of two waves: assume A1 = A2 = A R new amplitude AR

19
**Geometrical analysis of Interference**

term rotation vector A

20
**Complex Wave Representation of Interference**

assume A1 = A2 = A

21
**Diffraction conditions and reciprocal lattices: **

Theorem: The set of reciprocal lattice vectors G determines the possible X-ray reflections. k r r k k

22
**Complex exponential form**

Complex number What happen to the time dependent term? X-ray wavelength ~ 0.1 nm ~ 3x1018 1/s Detectors get the average intensity! Detectors measured the intensity only! A lot of time, examining is enough!

23
**Fourier expansion n(r) 0 for G = k otherwise, = 0**

Path difference Similarly, Phase angle dV Phase angle = (2/)rsin = kr r O Fourier expansion n(r) 0 for G = k otherwise, = 0 The diffraction condition is G = k. k + G = k’

24
**G: reciprocal lattice, -G: reciprocal lattice? ____**

Bragg condition? k G (hkl) plane or k k dhkl Bragg law G = k.

25
**More geometric relation between direct lattice and**

reciprocal lattice: e1, e2, e3: contravariant basis vector of R3 covariant basis vectors e1, e2, e3 (reciprocal lattice) ei and ei are not normal, but mutually orthonormal: For any vector v:

26
**v can be expressed in two (reciprocal) ways:**

Einstein’s summation convention, omitting No proof here, but you can check whether these relation is correct or not? Use BCC or FCC lattice as examples, next page!

27
**Use the BCC lattice as examples**

Assume You can check the other way around.

28
where Similarly, Prove

29
**gij: metric tensor in direct lattice**

a, b, c and , , : direct lattice parameters (standard definition of the Bravais lattice) det|gij| = V2.

30
Matrix inversion:

31
**Inverting the matrix gij.**

gij : metric tensor in reciprocal lattice a*, b*, c* and *, *, *: reciprocal lattice parameters These two are the same!

32
One gets relation like Similarly, ……………..

33
**d-spacing of (hkl) plane for any crystal system**

34
Example：FCC BCC (1) Find the primitive unit cell of the selected structure (2) Identify the unit vectors

35
**Volume of F.C.C. is a3. There are four atoms**

per unit cell! the volume for the primitive of a F.C.C. structure is ?

36
Similarly, B.C.C. See page 23

37
**Using primitive translation vector to do the**

reciprocal lattice calculation: Case: FCC BCC

39
not Why? (hkl) defined using unit cell! (hkl) is defined using primitive cell! (HKL)

40
** Find out the relation between the (hkl) and **

Example Find out the relation between the (hkl) and [uvw] in the unit cell defined by and the (HKL) and [UVW] in the unit cell defined by . In terms of matrix

41
**Find out the relation between (hkl) and (HKL). **

Assume there is the first plane intersecting the a axis at a/h and the b axis at b/k. In the length of |a|, there are h planes. In the length of |b|, there are k planes. How many planes can be inserted in the length |A|? Ans. h + 2k H = 1h + 2k + 0l Similarly, K = -1h + 1k +0l and L = 0h + 0k + 1l A B b 2k a b/k a/h h A/(h+2k) or

43
There are the same! Or

44
**We proof the other way around!**

45
**Interplanar spacing (defined based on unit cell)**

Cubic: Tetragonal: Orthorombic: Hexagonal:

46
Get the metric tensor! Perform the inversion of the matrix! Comparing the inversion of the metric tensor in direct lattice with the metric tensor in reciprocal lattice Geometrical relation between reciprocal lattice and direct lattice can be obtained!

Similar presentations

OK

EEE539 Solid State Electronics 1. Crystal Structure Issues that are addressed in this chapter include: Periodic array of atoms Fundamental types of.

EEE539 Solid State Electronics 1. Crystal Structure Issues that are addressed in this chapter include: Periodic array of atoms Fundamental types of.

© 2017 SlidePlayer.com Inc.

All rights reserved.

Ads by Google

Ppt on latest technology in electrical engineering Ppt on indian sign language Download ppt on area of parallelogram and triangles Ppt on places in our neighbourhood clip Ppt on reflection in java Head mounted display ppt online Ppt on latest technology in computer science Ppt on ram and rom definition Ppt on nature and human soul Ppt on different dance forms of india