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Net Ionic Equations. Aqueous solutions of Sodium Hydroxide and Copper (II) Chloride combine to form an aqueous solution of sodium chloride and solid blue.

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Presentation on theme: "Net Ionic Equations. Aqueous solutions of Sodium Hydroxide and Copper (II) Chloride combine to form an aqueous solution of sodium chloride and solid blue."— Presentation transcript:

1 Net Ionic Equations

2 Aqueous solutions of Sodium Hydroxide and Copper (II) Chloride combine to form an aqueous solution of sodium chloride and solid blue Copper Hydroxide 1.Write a skeleton equation 2.Balance the equation. 3.Identify the spectator ions. 4.Write the total ionic equation. 5.Write the net ionic equation.

3 Aqueous solutions of Sodium Hydroxide and Copper (II) Chloride combine to form an aqueous solution of sodium chloride and solid blue Copper Hydroxide

4 Na(OH) (aq) + CuCl 2(aq) Na + 1 OH -1 Cu + 2 Cl - 1

5 Na(OH) (aq) + CuCl 2(aq)  NaCl (aq) + Cu(OH) 2 (s) Na + 1 OH -1 Cu + 2 Cl - 1 The Copper and Hydroxide Join to form solid Copper Hydroxide Equation Not Balanced Precipitate OH -1

6 Na(OH) (aq) + CuCl 2(aq)  NaCl (aq) + Cu(OH) 2 (s) Balance the skeleton Equation NaOHCuClNaOHCuCl

7 Na(OH) (aq) + CuCl 2(aq)  NaCl (aq) + Cu(OH) 2 (s) Balance the skeleton Equation NaOHCuClNaOHCuCl

8 2Na(OH) (aq) + CuCl 2(aq)  NaCl (aq) + Cu(OH) 2 (s) Balance the skeleton Equation NaOHCuClNaOHCuCl

9 2Na(OH) (aq) + CuCl 2(aq)  2NaCl (aq) + Cu(OH) 2 (s) Balanced Molecular Formula NaOHCuClNaOHCuCl

10 Spectator Ions? They don’t take part in the reaction. Na + 1 OH -1 Cu + 2 Cl - 1 OH -1 Cl - 1 Na + 1 OH -1 Na + 1 Cl - 1 Na + 1 Cl - 1 OH -1 Cu + 2 Na + 1 OH -1 Cu + 2 Cl - 1 OH -1 Na + 1 OH -1 Cu + 2 Cl - 1 OH -1 Na + 1

11 WRITING TOTAL AND NET IONIC EQUATIONS 1.Balanced molecular equation. 2.Disassociate the aqueous ionic compounds (strong electrolytes) indicating the correct formula, number and charge of each. 3.Bring down all compounds with (s), (l), or (g) unchanged. 4.This is a total Ionic Equation. For a net ionic equation cross out the spectator ions.

12 2Na(OH) (aq) + CuCl 2(aq)  2NaCl (aq) + Cu(OH) 2 (s) 1.Balanced molecular equation. 2.Disassociate the aqueous ionic compounds (strong electrolytes) indicating the correct formula, number and charge of each. 3.Bring down all compounds with (s), (l), or (g) unchanged. 4.This is a total Ionic Equation. For a net ionic equation cross out the spectator ions.

13 2Na(OH) (aq) + CuCl 2(aq)  2NaCl (aq) + Cu(OH) 2 (s) 2Na 1+ (aq) + 2(OH) 1- (aq) + Cu 2+ (aq) + 2Cl 1- (aq)  2Na 1+ (aq) + 2Cl 1- (aq) + Cu(OH) 2(s) 1.Balanced molecular equation. 2.Disassociate the aqueous ionic compounds (strong electrolytes) indicating the correct formula, number and charge of each. 3.Bring down all compounds with (s), (l), or (g) unchanged. 4.This is a total Ionic Equation. For a net ionic equation cross out the spectator ions.

14 2Na(OH) (aq) + CuCl 2(aq)  2NaCl (aq) + Cu(OH) 2 (s) 2Na 1+ (aq) + 2(OH) 1- (aq) + Cu 2+ (aq) + 2Cl 1- (aq)  2Na 1+ (aq) + 2Cl 1- (aq) + Cu(OH) 2(s) 1.Balanced molecular equation. 2.Disassociate the aqueous ionic compounds (strong electrolytes) indicating the correct formula, number and charge of each. 3.Bring down all compounds with (s), (l), or (g) unchanged. 4.This is a total Ionic Equation. For a net ionic equation cross out the spectator ions.

15 2Na(OH) (aq) + CuCl 2(aq)  2NaCl (aq) + Cu(OH) 2 (s) 2Na 1+ (aq) + 2(OH) 1- (aq) + Cu 2+ (aq) + 2Cl 1- (aq)  2Na 1+ (aq) + 2Cl 1- (aq) + Cu(OH) 2(s) 1.Balanced molecular equation. 2.Disassociate the aqueous ionic compounds (strong electrolytes) indicating the correct formula, number and charge of each. 3.Bring down all compounds with (s), (l), or (g) unchanged. 4.This is a total Ionic Equation. For a net ionic equation cross out the spectator ions.

16 2Na(OH) (aq) + CuCl 2(aq)  2NaCl (aq) + Cu(OH) 2 (s) 2Na 1+ (aq) + 2(OH) 1- (aq) + Cu 2+ (aq) + 2Cl 1- (aq)  2Na 1+ (aq) + 2Cl 1- (aq) + Cu(OH) 2(s) 1.Balanced molecular equation. 2.Disassociate the aqueous ionic compounds (strong electrolytes) indicating the correct formula, number and charge of each. 3.Bring down all compounds with (s), (l), or (g) unchanged. 4.This is a total Ionic Equation. For a net ionic equation cross out the spectator ions.

17 2Na(OH) (aq) + CuCl 2(aq)  2NaCl (aq) + Cu(OH) 2 (s) 2Na 1+ (aq) + 2(OH) 1- (aq) + Cu 2+ (aq) + 2Cl 1- (aq)  2Na 1+ (aq) + 2Cl 1- (aq) + Cu(OH) 2(s) 1.Balanced molecular equation. 2.Disassociate the aqueous ionic compounds (strong electrolytes) indicating the correct formula, number and charge of each. 3.Bring down all compounds with (s), (l), or (g) unchanged. 4.This is a total Ionic Equation. For a net ionic equation cross out the spectator ions.

18 2Na(OH) (aq) + CuCl 2(aq)  2NaCl (aq) + Cu(OH) 2 (s) 2Na 1+ (aq) + 2(OH) 1- (aq) + Cu 2+ (aq) + 2Cl 1- (aq)  2Na 1+ (aq) + 2Cl 1- (aq) + Cu(OH) 2(s) 1.Balanced molecular equation. 2.Disassociate the aqueous ionic compounds (strong electrolytes) indicating the correct formula, number and charge of each. 3.Bring down all compounds with (s), (l), or (g) unchanged. 4.This is a total Ionic Equation. For a net ionic equation cross out the spectator ions.

19 2Na(OH) (aq) + CuCl 2(aq)  2NaCl (aq) + Cu(OH) 2 (s) 2Na 1+ (aq) + 2(OH) 1- (aq) + Cu 2+ (aq) + 2Cl 1- (aq)  2Na 1+ (aq) + 2Cl 1- (aq) + Cu(OH) 2(s) 1.Balanced molecular equation. 2.Disassociate the aqueous ionic compounds (strong electrolytes) indicating the correct formula, number and charge of each. 3.Bring down all compounds with (s), (l), or (g) unchanged. 4.This is a total Ionic Equation. For a net ionic equation cross out the spectator ions. 2(OH) 1- (aq) + Cu 2+ (aq)  Cu(OH) 2(s)

20 ANOTHER EXAMPLE

21 BaCl 2(aq)

22 BaCl 2(aq) + Na 2 (SO 4 ) 

23 BaCl 2(aq) + Na 2 (SO 4 )  2NaCl (aq)

24 BaCl 2(aq) + Na 2 (SO 4 )  2NaCl (aq) + BaSO 4(s)

25 BaCl 2(aq) + Na 2 (SO 4 ) (aq)  2NaCl (aq) + BaSO 4(s) BALANCED MOLECULAR FORMULA 1. Balanced molecular equation. 2. Show the disassociated ions individually. 3. Bring down all compounds with (s), (l), or (g) unchanged. 4. Cross out the spectator ions.

26 BaCl 2(aq) + Na 2 (SO 4 ) (aq)  2NaCl (aq) + BaSO 4(s) BALANCED MOLECULAR FORMULA Ba 2+ (aq) + 2Cl 1- (aq) + 2Na 1+ (aq) + SO 4 2- (aq)  2Na 1+ (aq) + 2Cl 1- (aq) + BaSO 4(s) TOTAL IONIC EQUATION 1. Balanced molecular equation. 2. Show the disassociated ions individually. 3. Bring down all compounds with (s), (l), or (g) unchanged. 4. Cross out the spectator ions.

27 BaCl 2(aq) + Na 2 (SO 4 ) (aq)  2NaCl (aq) + BaSO 4(s) BALANCED MOLECULAR FORMULA Ba 2+ (aq) + 2Cl 1- (aq) + 2Na 1+ (aq) + SO 4 2- (aq)  2Na 1+ (aq) + 2Cl 1- (aq) + BaSO 4(s) TOTAL IONIC EQUATION Ba 2+ (aq) + 2Cl 1- (aq) + 2Na 1+ (aq) + SO 4 2- (aq)  2Na 1+ (aq) + 2Cl 1- (aq) + BaSO 4(s) CROSS OUT SPECTATOR IONS 1. Balanced molecular equation. 2. Show the disassociated ions individually. 3. Bring down all compounds with (s), (l), or (g) unchanged. 4. Cross out the spectator ions.

28 BaCl 2(aq) + Na 2 (SO 4 ) (aq)  2NaCl (aq) + BaSO 4(s) BALANCED MOLECULAR FORMULA Ba 2+ (aq) + 2Cl 1- (aq) + 2Na 1+ (aq) + SO 4 2- (aq)  2Na 1+ (aq) + 2Cl 1- (aq) + BaSO 4(s) TOTAL IONIC EQUATION Ba 2+ (aq) + 2Cl 1- (aq) + 2Na 1+ (aq) + SO 4 2- (aq)  2Na 1+ (aq) + 2Cl 1- (aq) + BaSO 4(s) CROSS OUT SPECTATOR IONS Ba 2+ (aq) + SO 4 2- (aq)  BaSO 4(s) NET IONIC EQUATION 1. Balanced molecular equation. 2. Show the disassociated ions individually. 3. Bring down all compounds with (s), (l), or (g) unchanged. 4. Cross out the spectator ions.

29 Assignment An aqueous solution of aluminum chloride and sodium hydroxide react to form solid aluminum hydroxide. 1.Write a skeleton equation 2.Balance the equation (molecular formula) 3.Write the total ionic equation. 4.Identify the spectator ions. 5.Write the net ionic equation. An aqueous solution of aluminum chloride and sodium hydroxide react to form solid aluminum hydroxide. 1.Write a skeleton equation 2.Balance the equation (molecular formula) 3.Write the total ionic equation. 4.Identify the spectator ions. 5.Write the net ionic equation.


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