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Centripetal Acceleration. Acceleration in a circular path at constant speed a c =(v t 2 )/r Centripetal acceleration=(tangential speed) 2 /radius of circular.

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Presentation on theme: "Centripetal Acceleration. Acceleration in a circular path at constant speed a c =(v t 2 )/r Centripetal acceleration=(tangential speed) 2 /radius of circular."— Presentation transcript:

1 Centripetal Acceleration

2 Acceleration in a circular path at constant speed a c =(v t 2 )/r Centripetal acceleration=(tangential speed) 2 /radius of circular path Centripetal acceleration is always directed toward the center

3 Centripetal Force The net force that is directed toward the center of an object’s circular path F c =mv t 2 /r Centripetal force=mass x (tangential speed) 2 / radius of circular path

4 Torque Torquea quantity that measures the ability of a Force to rotate an object around an axis Torque = Force x lever arm x sin   Fdsin  Measured in Nm. Maximum Torque occurs at To increase Torque- increase either Force or lever arm distance or both.

5 For a system to be balanced, the torques must be balanced.  clockwise) =  (counter-clockwise) Ex: Two students sitting on a see-saw. One student m=40 kg, d = 3 m. Second student m=45 kg, d = ?


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