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Length of a Path The weight (length) of a path is the sum of the weights of its edges. adcbe Path p: 7 2 1 5 Edge weights: w(a, b) = 7, w(b, c) = 2, w(c,

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Presentation on theme: "Length of a Path The weight (length) of a path is the sum of the weights of its edges. adcbe Path p: 7 2 1 5 Edge weights: w(a, b) = 7, w(b, c) = 2, w(c,"— Presentation transcript:

1 Length of a Path The weight (length) of a path is the sum of the weights of its edges. adcbe Path p: Edge weights: w(a, b) = 7, w(b, c) = 2, w(c, d) = 1, w(d, e) = 5 Path weight w(p) = = 15 A shortest path from vertex u to vertex v has the minimum weight among all paths connecting u to v.

2 Single-Source Shortest Paths path s s-a s-a-b s-a-b-c s-a-d s-a-b-e s-a-b-e-f weight s a b c d e f Problem Given a graph G = (V, E), where every edge e has a weight w(e), and a source vertex s in V, find the shortest path from s to every other vertex. a s b e f d c source

3 Applications Transportation (shortest route from Ames to Phoenix?) Network routing (how to direct packets to a destination across a network?) Telecommunications Speech interpretation (best interpretation of a spoken sentence) Robot path planning Medical imaging Building block for network algorithms...

4 Shortest-Paths Tree a s b e f d c The unique simple path from s to any vertex v in the tree is a shortest path from s to v. The vertices in the tree are exactly those reachable from s in G. Similar to the breadth-first tree (where all edges have weight 1).

5 Negative Weights  --   s a c e b d f g h j i unreachable from s negative-weight cycle source The shortest path may have length either  or – .

6 No Cycle in a Shortest Path A shortest path cannot contain a negative-weight cycle. A shortest path cannot contain a positive-weight cycle because otherwise the removal of such a cycle would reduce the path weight. Any zero-weight cycle in a shortest path can be removed. We only consider shortest path of at most |V| – 1 edges.

7 Optimal Substructure Any subpath of a shortest path is the shortest of all paths between the two intermediate vertices. u y x v shortest path from u to v: shortest path from x to y Greedy algorithm or dynamic programming? (Both are used in solving different versions of the shortest path problem.)

8 Representing Shortest Paths d(v) = length of the shortest path from s to v found so far (an upper bound on the weight of the eventual shortest path).  (v) = the predecessor of v in the above path (used for backtracking the shortest path from s to v in the end). During the execution of a shortest-path algorithm, maintain two arrays: Initialization for each vertex v in G do d[v]    [v]  NIL d[s]  0

9 Relaxation Test if the shortest path to v found so far can be improved by going through u. s w v u (v)(v) s w v u (v)(v) d[v] > d[u] + w(u, v) Relax(u, v) if d[v] > d[u] + w(u, v) then d[v]  d[u] + w(u, v)  [v]  u Shortest path algorithms differ in the number of times the edges are relaxed and the order in which they are relaxed.

10 The Bellman-Ford Algorithm Edge weights may be negative. It detects any negative-weight cycle reachable from the source. Each edge is relaxed |V| – 1 times. Bellman-Ford(G, s) Initialize(G, s) for i  1 to |V| – 1 do for each edge (u, v)  E do Relax(u, v) for each edge (u, v)  E do if d[v] > d[u] + w(u, v) then return false // negative-weight cycle found! return true // no negative-weight cycle Running time  (VE)

11 An Example 0     s t yz x Source: s Order of edge relaxation: (t, x), (t, y), (t, z), (x, t), (y, x), (y, z), (z, x), (z, s), (s, t), (s, y)

12 Round 1 0  7  s t yz x d[y] = 7  [y] = s d[t] = 6  [t] = s

13 Round s t yz x Relax (t, x), (t, y), (t, z), (x, t). d[x] = 11  [x] = t d[z] = 2  [z] = t

14 Round 2 (cont’d) s t yz x Relax (y, x), (y, z), (z, x), (z, s), (z, s), (s, t), (s, y). d[x] = 4  [x] = y

15 Round s t yz x d[t] = 2  [t] = x

16 Round s t yz x d[z] = -2  [z] = t (unchanged)

17 Detecting Negative-Weight Cycle 0    s a b c Order of edge relaxation: (s, a), (b, c), (b, a), (a, b), (s, c) s a b c s a b c s a b c s a b c d[a] > d[b] + w(b, a): a negative cycle exists!

18 Correctness Assume G has no negative-weight cycles reachable from s. After |V| – 1 rounds of relaxation, d[v] is the length of a shortest path from s to v for every vertex v. For any vertex v, a path from s to v exists if and only if Bellman-Ford terminates with d[v] < . If G has no negative-weight cycles reachable from s, then Bellman-Ford returns true, d[v] records the shortest path length for every vertex v, and all  [v] induce a shortest-paths tree. Otherwise, the algorithm returns false.


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