Download presentation

Presentation is loading. Please wait.

Published byKirsten Stanforth Modified over 2 years ago

1
Outline:4/11/07 Today: Finish Chapter 19 Coulomb Calculations Redox Applications è CAPA 18 due tonight… è CAPA 19 due Friday… è Special seminar Thursday pm è Special seminar Friday 4pm è Pick up Quiz 8 – from me è Pick up grade summary – in front

2
Outline:4/11/07 Today: Finish Chapter 19 Coulomb Calculations Redox Applications è CAPA 18 due tonight… è CAPA 19 due Friday… è Special seminar Thursday pm è Special seminar Friday 4pm è Pick up Quiz 8 – from me è Pick up grade summary – in front SC 1019 6-8pm Panel @ 8pm

3
Outline:4/11/07 Today: Finish Chapter 19 Coulomb Calculations Redox Applications è CAPA 18 due tonight… è CAPA 19 due Friday… è Special seminar Thursday pm è Special seminar Friday 4pm è Pick up Quiz 8 – from me è Pick up grade summary – in front

4
Quiz #7 n Average = 8.2 Good!

5
Chapter 19 practice problems: 19.1, 19.3, 19.5, 19.9, 19.11, 19.13, 19.15, 19.17, 19.19, 19.21, 19.23, 19.25, 19.27, 19.33, 19.35, 19.37, 19.39, 19.41, 19.45, 19.49, 19.53, 19.55, 19.63, 19.65, 19.67, 19.69, 19.73, 19.77, 19.81, 19.83, 19.85 19.1, 19.3, 19.5, 19.9, 19.11, 19.13, 19.15, 19.17, 19.19, 19.21, 19.23, 19.25, 19.27, 19.33, 19.35, 19.37, 19.39, 19.41, 19.45, 19.49, 19.53, 19.55, 19.63, 19.65, 19.67, 19.69, 19.73, 19.77, 19.81, 19.83, 19.85

6
Grade Summary Go over grade summary sheet Go over grade summary sheet n 8 quizzes / 70 pts (drop one) n 4 pts/seminar report extra credit n CAPA through 17; w/out a few handins n Exam 1, Exam 2 added at 20 or 15% n Final exam 60% or 75% or 90%... Please see me if there is an data entry error

7
Finish Chapter 19: n n Current = charge/time 1 Ampere = 1 Coulomb / second Calculational Example: n A lead-acid battery: PbO 2 +HSO 4 +2H + +Pb 2PbSO 4 +2H 2 O Assume 250 g of PbO 2 and that this battery supplies 6 Amps until it dies; how long will it last?

8
n n 250 g PbO 2 × 1 mol/ 239.2 g = 1.045 mol PbO 2 2.090 mol e × 96485 C/mol = 201654 C (time) × (6 C/sec) = 201654 C time = 3361 sec = 9.34 hours PbO 2 PbSO 4 (+4 +2) : 2e 1.045 mol PbO 2 × 2 mol e / mol PbO 2 = 2.090 mol e

9
Problem #3 - Worksheet #12: n n Current calculation…. n n Which equations? n n What is the limiting reagent? n n How many moles? n n How much time at 0.2 mA?

10
Worksheet #12 HgO Hg (+2 0) : 2e Zn ZnO (0 +2) : 2e n Moles of everything: 1 g HgO × 1mol/216.6g = 0.00462 mol 1 g Zn × 1mol/65.4g = 0.01530 mol What is the limiting reagent? HgO n Moles of electrons: 0.00462l mols HgO × 2 mols e /mol HgO

11
Moles e to Coulombs conversion: 0.00924 mol e × 96485 C/mol e = 891.5 C = 891.5 Amp. sec How long? 891.5 Amp. sec = (x sec)(0.2×10 3 Amp) x = 4.46×10 6 sec = 1238 hours Practice! Practice! Practice! Practice!

12
Redox applications: n n Batteries n n Fuel Cells n n Electroplating n n Ore Extraction/Mining n n Rust Protection n n Metallurgy/Alloys n n Electrolysis Read pp. 847 - 857 in textbook

Similar presentations

© 2017 SlidePlayer.com Inc.

All rights reserved.

Ads by Google