1. Service Delivery 3 Hydraulics

2. Aim To ensure students can explain the principles of obtaining and delivering water.

3. Learning Outcomes At the end of the session students will be able to: Understand the relationship between atmospheric pressure and suction lift Describe the principal characteristics of pressure Describe how friction causes pressure loss Explain the term ‘jet reaction’ Carry out basic fireground calculations.

4. Calculating areas. Area = wXh Area = vertical hXw a b Area = a+bXh 2 w hh w

5. Calculating volumes. h r   r  h Volume = 2

6. Calculating volumes. Volume = hXwXd w h d

7. Calculating volumes. Water Volume = 2 x a x d 3

8. Pressure is perpendicular to any surface on which it acts. Atmospheric Pressure

9. Pressure at any point in a fluid at rest is of the same intensity in all directions. Pressure Gauges

10. Pressure applied from outside to a fluid contained in a vessel is transmitted equally in all directions. Pressure Pressure gauges

11. Downward pressure of a fluid in an open vessel is proportional to depth. 1m 2m 3m

12. The downward pressure of a fluid in an open vessel is proportional to the density of the fluid. Mercury 10mm Water 136mm

13. The downward pressure of a fluid on the bottom of a vessel is independent of the shape of the vessel.

14. Atmospheric pressure approx 1bar Water vacuum Lifting water by atmospheric pressure.

15. Theoretical lift Approximately 10 metres - assuming a perfect vacuum can be created and the water is cool and pure.

16. Pressure and head The height to which water is lifted or pumped is referred to as the head To raise a column of water 1 metre in height requires a pressure of 0.1bar. This applies to both ‘suction head’ and ‘delivery head’.

17. Factors limiting suction lift Lifting water from it’s existing level to the pump inlet Overcoming frictional resistance to the water Turbulence at the pump eye Creation of flow.

18. Practical lift Because of these factors the maximum practical suction lift is generally regarded as 8 metres.

19. Lifting practically. 7m 3m water 2m 8m water

20. Five principal laws govern the loss of pressure due to friction.

21. Friction loss varies directly with the length of the hose 12 Hose lengths Friction loss 0.2b 0.4b.

22. For the same velocity friction loss decreases with the increase in diameter 45mm70mm90mm.

23. Friction loss increases directly with the square of the velocity 2000 litres/min pressure loss 6bar 1000 litres/min pressure loss 1.5bar.

24. Friction loss increases with the interior roughness of the pipe.

25. For all practical purposes, friction loss is independent of pressure.

26. Calculating jet pressures Pressure loss due to friction; 70mm non-percolating hose 0.2 bars per 25 metre length.

27. Pressure loss due to head For every metre in height that water is pumped 0.1bar of pressure is lossed.

28. Question What pressure will be required at the pump to supply 3 bars pressure at the branch. 6 lengths of hose are being used to supply a branch deployed at a height of 15m

29. Answer Nozzle pressure required 6 bars Pressure loss due to head 0.1b X 15 = 1.5b Pressure loss due to friction 0.2b X 6 = 1.2b Pump pressure required 8.7bars

30. Fireground flow rate calculation 45mm diameter hose = 300 litres/min 70mm diameter hose = 600 litres/min

31. Function of a branch and nozzle To convert pressure energy into velocity energy and ensure that an effective jet of water leaves the nozzle.

32. Achieved by reducing the cross-sectional area that the water is flowing through 45mm diameter hoseline 20mm diameter nozzle.

33. Advantages of higher nozzle pressures A greater striking power is achieved A longer reach can be obtained A larger volume of water is applied.

34. Factors affecting the pressures adopted The type and size of nozzle used The type of jet required The intensity of the wind.

35. Jet Reaction The mass of water per second passing through the nozzle The squared diameter of the nozzle. The magnitude of the reaction is dependant on;

36. Jet Reaction

37. = 1.57 x p x d 10 2

38. R = 1.57× 7 × (25x25) 10 = 687 Newtons. 1.57 x p x d 10 2 Using a 25mm nozzle at 7 bars pressure

39. R = 1.57× 7 × (12.5x12.5) 10 = 172 Newtons. 1.57 x p x d 10 2 Using a 12.5mm nozzle at 7 bars pressure

40. Confirmation Assessments will be based on this lesson and the corresponding study note Learning Outcomes Understand the relationship between atmospheric pressure and suction lift Describe the principal characteristics of pressure Describe how friction causes pressure loss Explain the term ‘jet reaction’ Carry out basic fireground calculations.

41. THE END