Presentation on theme: "Unit 3 Work, Power, and Machines"— Presentation transcript:
1Unit 3 Work, Power, and Machines P. ScienceUnit 3Work, Power, and MachinesSPS8: Students will determine relationships among force, mass, and motion.SPS8.e: Calculate amounts of work and mechanical advantage using simple machines.
2I. WorkWhen a force causes an object to move – work is done.
4If the object does not move then no work is done.W = F x dIf d = 0any number times 0 is 0so no work.
5Work also depends on direction. The force has to be in the same direction as the motion or no work is done on the object.Lifting the BooksCarrying the BooksForceForce& MotionThe same& MotionperpendicularWork is Not DoneWork is done
6The SI unit for work is Joules (J). F = N= kg m/s d = mSoW = F x d = Nm1 J = 1kg x m2/s2 = 1 Nm
7Work or Not? Carrying a box across the ramp. A mouse pushing a piece of cheese with its nose across the floor.No workWork is done.
8What’s Work?A scientist delivers a speech to an audience of his peers.A body builder lifts 350 pounds above his head.A mother carries her baby from room to room.A father pushes a baby in a carriage.A woman carries a 20 kg grocery bag to her car.
9What’s Work?A scientist delivers a speech to an audience of his peers. NoA body builder lifts 350 pounds above his head. YesA mother carries her baby from room to room. NoA father pushes a baby in a carriage. YesA woman carries a 20 km grocery bag to her car. No
10Distance must be in direction of force! WorkWork is thetransfer of energy through motionforce exerted through a distanceW = FdW: work (J)F: force (N)d: distance (m)1 J = 1kg x m2/s2 = 1 NmDistance must be in direction of force!
11WorkBrett’s backpack weighs 30 N. How much work is done on the backpack when he lifts it 1.5 m from the floor to his back?GIVEN:F = 30 Nd = 1.5 mW = ?WORK:W = F·dW = (30 N)(1.5 m)W = 45 JFWd
12d Work W F GIVEN: WORK: F = W/d F =(375 Nm)/(75m) F = 5.0 N If it takes 375 J of work to push a box 75 m what is the force used to push the box?GIVEN:d = 75 mW = 375 J or 375 NmF = ?WORK:F = W/dF =(375 Nm)/(75m)F = 5.0 NFWd
13d Work W F GIVEN: m = 40 kg d = 1.4 m - during d = 2.2 m - after W = ? A dancer lifts a 40 kg ballerina 1.4 m in the air and walks forward 2.2 m. How much work is done on the ballerina during and after the lift?GIVEN:m = 40 kgd = 1.4 m - duringd = 2.2 m - afterW = ?WORK:W = F·d F = m·aF =(40kg)(9.8m/s2)=392 NW = (392 N)(1.4 m)W = 549 J during liftNo work after lift. “d” is not in the direction of the force.FWd
14Power The rate at which work is done. Remember that a rate is something that occurs over time.
15workPower = timeORWP = tThe SI unit for Power is watts (W).
16A watt is the amountof power required to do1 J of work in 1 s.SoP= W/tunit for P= J/sWatts = J/s
17Power t W P GIVEN: P = ? W = 375 J t = 15 s WORK: P = W/t How much power is used to do 375 J of work in 15 seconds?GIVEN:P = ?W = 375 Jt = 15 sWORK:P = W/tP = 375 J/ 15 sP = 25 J/s or 25 WPWt
18Power t W P GIVEN: P = 25 W or 25 J/s W = 450 J t = ? WORK: t = W/P If 25 W of power is used to do 450 J of work how long did it take to do the work?GIVEN:P = 25 W or 25 J/sW = 450 Jt = ?WORK:t = W/Pt = (450 J) /(25 J/s)t = 18 sPWt
19Making Work Easier II. Simple Machines Lever Pulley Wheel & Axle Inclined PlaneScrewWedge
21Machine – a device thatmakes doing work easier by…
22increasing the force that can be applied to an object. (car jack)
23increasing the distance over which the force can be applied. (ramp)
24by changing the direction of the applied force. (opening the blinds)
25A. LeverLevera bar that is free to pivot about a fixed point, or fulcrum.“Give me a place to stand and I will move the Earth.”– ArchimedesEngraving from Mechanics Magazine, London, 1824Effort armYou apply your force.ResistancearmWork is done here.Fulcrum
26A. Lever Ideal Mechanical Advantage (IMA) assumes a frictionless machineEffort arm lengthResistancearm lengthLe must be greater than Lr in order to multiply the force.
27First Class Lever First Class Lever the fulcrum is in the middle changes direction of forceEx: pliers, seesaw
28Second Class Lever Second Class Lever The output (resistance) is in the middlealways increases forceEx: wheelbarrow, nutcracker
29Third Class Lever Third Class Levers Input (effort) force is in the middlealways increases distanceEx: hammer, bat, human body
30Think FOIL Fulcrum in middle = 1st class lever Output in middle = 2nd class leverInput in middle = 3rd class leverLEVERS
31B. PulleyPulleygrooved wheel with a rope or chain running along the groovea “flexible first-class lever”FLeLr
32B. Pulley Ideal Mechanical Advantage (IMA) equal to the number of rope segments if pulling up.Equal to one less than the number of rope segments (minus 1) if pulling down.IMA = 0IMA = 1IMA = 2
33B. Pulley Fixed Pulley IMA = 1 does not increase force only changes direction of force
34B. Pulley Movable Pulley IMA = 2 increases force doesn’t change direction
35B. Pulley Block & Tackle (Pulley System) combination of fixed & movable pulleysincreases forcemay or may not change direction
36C. Wheel and Axle Wheel and Axle two wheels of different sizes that rotate togethera pair of “rotating levers”WheelAxle
37C. Wheel and Axle Ideal Mechanical Advantage (IMA) effort force is applied to wheelaxle moves less distance but with greater forceeffort radiusresistance radius
38D. Inclined Plane Inclined Plane sloping surface used to raise objects hl
39E. ScrewScrewinclined plane wrapped in a spiral around a cylinder
40F. WedgeWedgea moving inclined plane with 1 or 2 sloping sides
43How do machines make work easier? Three (3) Ways:1. Machines increase Force (total distance traveled is greater).2. Machines increase distance (a greater force is required).3. Machines change direction.
44III. Using Machines Compound Machines Efficiency Mechanical Advantage
45A. Compound Machines Compound Machine combination of 2 or more simple machines
46A. Compound Machines Rube Goldberg Machine A Rube Goldberg machine is a contraption, invention, device, or apparatus that is a deliberately over-engineered or overdone machine that performs a very simple task in a very complex fashion, usually including a chain reaction. The expression is named after American cartoonist and inventor Rube Goldberg.
48B. Work In Effort force – FE (Force in) The force applied to the machine (usually by you).Work in – Win (Force in x distance in)The work done by you on the machine.
49C. Work Out Resistance force – FR (Force out) The force applied by the machine toovercome resistance.Work out – Wout(Force out x distance out)The work done bythe machine.
50D. Ideal Machine Win = Wout 100% energy transfer. There is no such thing as an idealmachine – you always lose someenergy (through friction, airresistance, etc.).
51E. Efficiencya measure of how much of the work put into a machine is changed into useful output work by the machine. (less heat from friction)
52Efficiency =(Wout /Win ) x 100%Win is always greater than Wout
53Efficiency Efficiency measure of how completely work input is converted to work outputalways less than 100% due to friction
54Efficiency Practice Problem If a machine requires 26.0 J of work input to operate and produces 22.0 J of work output, what is it’s efficiency?Formula:Wout x 100%WinGiven:Wout is 22.0 JWin is 26.0 JCalculation:22.0 J X 100% = 84.6%26.0 J
55F. Mechanical Advantage How much a machine multiplies force or distance.output force (FR)MA = input force (FE)Orinput distanceoutput distance
56LR MA of Levers MA = Length of effort arm Length of resistance arm or Remember that Length is the same as distanceorLELR
57MA of Inclined Planes Resistance distance length of slope or _l_ effort distanceResistance distanceorlength of slope or _l_height of slope h
58Mechanical AdvantageThe number of times a force exerted on a machine is multiplied by the machine.FORCEMechanical advantage (MA) = resistance forceeffort forceDISTANCEMechanical advantage (MA) = effort distance resistance distance
59Mechanical Advantage dr de MA MA =de ÷ dr de = 12 m dr = 3 m What is the mechanical advantage of the following simple machine?3 m12 mGIVEN:de = 12 mdr = 3 mMA = ?WORK:MA =de ÷ drMA = (12 m) ÷ (3 m)MA = 4MAdedr
60Mechanical Advantage Fe Fr MA MA = Fr ÷ Fe Fe = 150 N Fr = 9900 N Determine the mechanical advantage of an automobile jack that lifts a 9900 N car with an input force of 150 N.GIVEN:Fe = 150 NFr = 9900 NMA = ?WORK:MA = Fr ÷ FeMA = (9900 N) ÷ (150 N)MA = 66MAFrFe
61Mechanical Advantage dr de MA MA =de ÷ dr de = 6.0 m dr = 1.5 m Calculate the mechanical advantage of a ramp that is 6.0 m long and 1.5 m high.GIVEN:de = 6.0 mdr = 1.5 mMA = ?WORK:MA =de ÷ drMA = (6.0 m) ÷ (1.5 m)MA = 4MAdedr
62Mechanical Advantage Fe Fr MA MA = Fr ÷ Fe Fe = 20 N Fr = 500 N A worker applies an effort force of 20 N to open a window with a resistance force of 500 N. What is the crowbar’s MA?GIVEN:Fe = 20 NFr = 500 NMA = ?WORK:MA = Fr ÷ FeMA = (500 N) ÷ (20 N)MA = 25MAFrFe
63Mechanical Advantage Fe Fr MA Fe = ? Fe = Fr ÷ MA Fr = 2000 N Find the effort force needed to lift a N rock using a jack with a mechanical advantage of 10.GIVEN:Fe = ?Fr = 2000 NMA = 10WORK:Fe = Fr ÷ MAFe = (2000 N) ÷ (10)Fe = 200 NMAFrFe
64Mechanical Advantage Fe Fr MA MA =Fr ÷ Fe Fe = 25 N Fr = 500 N What is the mechanical advantage of the following simple machine?GIVEN:Fe = 25 NFr = 500 NMA = ?WORK:MA =Fr ÷ FeMA = (500N) ÷ (25N)MA = 20MAFrFe
65Shortcut for MA of Pulleys Mechanical Advantage of Pulleys is very easy.Count the number of rope segments visible.If rope is pulling down subtract 1.If rope is pulling up do nothing.Example:5 rope segmentsPulling down, so subtract 1.Mechanical Advantage = 5-1= 4
66Pulley A Pulley B 2 rope segments Subtract 1 b/c pulling down MA = 2-1=1Pulley BPulling up do nothingMA=2Pulley PulleyA B