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October 3, 2007 I have no voice today…

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Presentation on theme: "October 3, 2007 I have no voice today…"— Presentation transcript:

1 October 3, 2007 I have no voice today…
Hence, those dreadful slides, so that I do not need to speak much… or cancel the class… These slides are in the course web site, under Chapter 8.

2 A few reminders Assignment 4, due Wednesday, October 10, by 5 pm
Assignement 5 will be due, Friday, October 19 Today’s Office Hours: 1 – 4 pm

3 Assignment 4 P. 203 #66 Should be a straightforward application of the Kinetic-Energy Theorem, where you use W = Fd, and you look for F. P.203 #74 Use P = W/t and KE Theorem. P. 237 #64 similar to P. 236 #52, discussed later today. P.236 #38 similar to Example 8-10, discussed next.

4 Equation of the day

5 where

6 and

7 Potential Energy Defined for conservative force as
Example: Gravitational Force

8 P. 226, Example 8-10 A block of mass m1 = 2.4 kg is connected to a second block of mass m2 = 1.8 kg. When the blocks are released from rest, they move through a distance d = 0.5 m, at which point m2 hits the floor. Given that the coefficient of kinetic friction between m1 and m2 is mk = 0.45, find the speed of the blocks just before m2 lands.

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10 P. 236, Problem 52 A 61-kg skier encounters a dip in the snow’s surface that had a circular cross section with a radius of curvature of 12 m. If the skier’s speed at point A in the Figure is 8.0 m/s, what is the normal force exerted vy the snow on the skier at point B? Ignore frictional forces.

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12 P. 238, Problem 81 An ice cube is placed on top of an overturned spherical bowl of radius r as shown in the Figure. If the ice cube slides downward from rest at the top of the bowl, at what angle q does it separate from the bowl? In other words, at what angle does the normal force between the ice cube and the bowl go to zero?

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