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2-May-15Created by Mr. Lafferty Maths Dept. Algebra www.mathsrevision.com Removing Brackets & Simplifying Factors Simple Factorising S4.

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Presentation on theme: "2-May-15Created by Mr. Lafferty Maths Dept. Algebra www.mathsrevision.com Removing Brackets & Simplifying Factors Simple Factorising S4."— Presentation transcript:

1 2-May-15Created by Mr. Lafferty Maths Dept. Algebra Removing Brackets & Simplifying Factors Simple Factorising S4

2 2-May-15Created by Mr. Lafferty Maths Dept. Starter Questions Starter Questions 6cm 2cm 3cm S4

3 2-May-15Created by Mr. Lafferty Maths Dept. Learning Intention Success Criteria 1. Explain how to remove brackets and simplify. 1. Understand how to remove brackets Algebra Removing Brackets & Simplifying 3. Tidy up after removing brackets. 2. Apply rules integer numbers. S4

4 S4 3(b + 5) =3b + 15 Example 1 4(w - 2) =4w - 8 Example 2 2-May-15Created by Mr. Removing a Single Bracket

5 S4 -2(h + 5) =-2h - 10 Example 3 -(g - 9) =-g + 9 Example 4 2-May-15Created by Mr. Removing a Single Bracket Be careful with negatives !!

6 S4 8 +2(h + 3) =8 + 6 Example 4 2-May-15Created by Mr. Removing a Single Bracket Be careful only multiply everything inside the bracket + 2h Now tidy up ! + 14= 2h

7 S4 -2(y - 1) + 4 =-2y + 4 Example 5 2-May-15Created by Mr. Removing a Single Bracket Be careful only multiply everything inside the bracket + 2 Now tidy up ! + 6= -2y

8 S4 y - (4 - y) =y + y Example 6 2-May-15Created by Mr. Removing a Single Bracket Be careful only multiply everything inside the bracket - 4 = 2y - 4 Now tidy up !

9 S4 a(y - 1) =ay - a Example 7 p(w - 6) =pw - 6p Example 8 2-May-15Created by Mr. Removing a Single Bracket

10 S4 x(x + 3) =x2x2 + 3x Example 9 3q(3q -2m) =9q 2 - 6mq Example 10 2-May-15Created by Mr. Removing a Single Bracket

11 2-May-15Created by Mr. Lafferty Maths Dept. Now try Ex 1 Ch15 (page 172) Algebra Removing Brackets & Simplifying S4

12 Starter Questions 2-May-15Created by Mr. Q1.Multiply out (a)a (6h – 3x) Q2.True or false Q3.Write down all the number that divide into 12 without leaving a remainder. S4

13 2-May-15Created by Mr. Learning Intention Success Criteria 1.To identify factors using factor pairs 1.To explain that a factor divides into a number without leaving a remainder 2.To explain how to find Highest Common Factors 2.Find HCF for two numbers by comparing factors. Factors Using Factors S4

14 2-May-15Created by Mr. Factors Factors Example :Find the factors of 56. F56 =1 and 56 2 and 28 Numbers that divide into 56 without leaving a remainder 4 and 14 7 and 8 S4

15 Factors 2-May-15Created by Mr. Highest Common Factor We need to write out all factor pairs in order to find the Highest Common Factor. Highest Common Factor Largest Same Number S4

16 F12 = 1 and 12 2 and F8 =1 and Factors 2-May-15Created by Mr. Example :Find the HCF of 8 and 12. HCF = 4 Highest Common Factor S4

17 F2b = 1 and 2b 2 and b F ab =1 and ab a and b Factors Example :Find the HCF of ab and 2b. HCF = b Highest Common Factor S4

18 2 and 5x F4x =1, and 4x Factors 2-May-15Created by Mr. Example :Find the HCF of 4x and x 2. HCF = x Fx 2 = 1 and x2x2 Highest Common Factor F5 = 1 and 5 Example :Find the HCF of 5 and 10x. HCF = 5 F10x = 1, and 10x 5 and 2x 10 and x 2 and 2x 4 and x x and x S4

19 2-May-15Created by Mr. Factors Find the HCF for these terms (a)16w and 24w (b) 9y 2 and 6y (c) 4h and 12h 2 (d)ab 2 and a 2 b 8w 3y 4h ab S4

20 2-May-15Created by Mr. Lafferty Now try Ex 2 Ch15 (page 173) Factors S4

21 Starter Questions 2-May-15Created by Mr. Q1.Expand outa (4y – 3x)-2y Q2.Write out in full Q3.True or False all the factors of 5x 2 are 1, x, 5 S4

22 2-May-15 Created by Mr. Learning Intention Success Criteria 1.To identify the HCF for given terms. 1.To show how to factorise terms using the Highest Common Factor and one bracket term. 2.Factorise terms using the HCF and one bracket term. Factorising Using Factors S4

23 2-May-15Created by Mr. Factorising Example Factorise 3x Find the HCF for 3x and HCF goes outside the bracket3( ) 3.To see what goes inside the bracket divide each term by HCF 3x ÷ 3 = x15 ÷ 3 = 53( x + 5 ) Check by multiplying out the bracket to get back to where you started S4

24 2-May-15Created by Mr. Factorising Example 1.Find the HCF for 2x 2, 4xy and 62 2.HCF goes outside the bracket2( ) 3.To see what goes inside the bracket divide each term by HCF 2x 2 ÷ 2 = x 2 4xy ÷ 2 = 2xy 2(x 2 - 2xy +3) Factorise 2x 2 – 4xy + 6 S4 6 ÷ 2 = 3 Check by multiplying out the bracket to get back to where you started

25 2-May-15Created by Mr. Factorising Factorise the following : (a)3x + 6 (b) 4xy – 2x (c) 6a + 7a 2 (d)xy 2 -xy + 4x 3(x + 2) 2x(2y – 1) a(6 + 7a) x(y 2 – y + 4) Be careful ! S4

26 2-May-15 Created by Mr. Now try Ex 3 Ch15 (page 175) Factorising S4


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