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PROBABILITIES FROM TWO WAY TABLES StuStaffTotal American107105212 European331245 Asian5547102 Total195164359 12) What is the probability that the driver is a student?

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PROBABILITIES FROM TWO WAY TABLES StuStaffTotal American107105212 European331245 Asian5547102 Total195164359 13) What is the probability that the driver drives a European car?

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PROBABILITIES FROM TWO WAY TABLES StuStaffTotal American107105212 European331245 Asian5547102 Total195164359 14) What is the probability that the driver is staff and drives an Asian car?

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PROBABILITIES FROM TWO WAY TABLES StuStaffTotal American107105212 European331245 Asian5547102 Total195164359 15) What is the probability that the driver drives an American or Asian car? Disjoint?

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PROBABILITIES FROM TWO WAY TABLES StuStaffTotal American107105212 European331245 Asian5547102 Total195164359 16) What is the probability that the driver is staff or drives an Asian car? Disjoint?

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PROBABILITIES FROM TWO WAY TABLES StuStaffTotal American107105212 European331245 Asian5547102 Total195164359 17) If the driver is a student, what is the probability that they drive an American car? Condition

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PROBABILITIES FROM TWO WAY TABLES StuStaffTotal American107105212 European331245 Asian5547102 Total195164359 18) What is the probability that the driver is a student if the driver drives a European car? Condition

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Example 19: Management has determined that customers return 12% of the items assembled by inexperienced employees, whereas only 3% of the items assembled by experienced employees are returned. Due to turnover and absenteeism at an assembly plant, inexperienced employees assemble 20% of the items. Construct a tree diagram or a chart for this data.

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ReturnedNot returned Total Experienced2.477.680 Inexperienced2.417.620 Total4.895.2100

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Example 19: Management has determined that customers return 12% of the items assembled by inexperienced employees, whereas only 3% of the items assembled by experienced employees are returned. Due to turnover and absenteeism at an assembly plant, inexperienced employees assemble 20% of the items. Construct a tree diagram or a chart for this data. What is the probability that an item is returned? If an item is returned, what is the probability that an inexperienced employee assembled it? P(returned) = 4.8/100 = 0.048 P(inexperienced|returned) = 2.4/4.8 = 0.5

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Only 5% of male high school basketball, baseball, and football players go on to play at the college level. Of these, only 1.7% enters major league professional sports. Of the athletes that do not play college sports, only 0.1% enters major league professional sports. What is the probability that a high school athlete will play professional sports? What is the probability that a high school athlete does not play college sports if he plays professional sports? Play collegeNot play college 1.7% of 50 total Play pro.85.951.8 Not play pro49.15949.05998.2 Total 50950 1000 Make up a population size! 1.7% of 50 5% of 1000 P(play pro) = P(play college & Play pro) or P(not play college & play pro) =.05(.017) + (.95)(.001) =.0018 P(not play college | plays pro) = P(not play college & play pro) / P(play pro) =.95/1.8 =.5278

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People leaving a football match were asked if they supported Manchester United or Newcastle. They were also asked if they were happy. The probability supporting Manchester United is.46. The probability that they support Manchester United and are unhappy is.29. The probability that they support Newcastle and are happy is.33. Manchester United NewcastleTotals Happy Unhappy Totals 460 290 1000 330170 500 540 500 210

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