Download presentation

Presentation is loading. Please wait.

Published byDillon Leaks Modified about 1 year ago

1
Polymer Viscoelasticity & Rheology Minshiya P. Assistant Professor M E S Keveeyam College Valanchery

2
Incompressible – the density is constant Irrotational – the flow is smooth, no turbulence Nonviscous – fluid has no internal friction ( η = 0) Steady flow – the velocity of the fluid at each point is constant in time. Ideal or Newtonian fluids

3
Under fixed and constant stress – strian or deformation increases continuosly Strain is non recoverable (zero yield value) Strain, ε = f(σ, t) Ideal or Newtonian fluids

5
σs (T) α dv/dr σs (T) = ηdv/dr = (1/φ) dv/dr ------- (1) η = 1/φ = σs/dv/dr --------(2) η : coeff of viscosity or viscosity or internal friction of the liquid φ : fluidity eqn (1) & (2) : Newton’s law Ideal or Newtonian fluids

6
d ε /dt = dv/dr ----- (3) d ε /dt :Strain rate Strain rate : rate of change in strain (deformation) of a material with respect to time (1) σs = η d ε /dt = (1/φ) d ε /dt ------ (4) Shear stress α rate of shear strain

7
Non-Newtonian fluid A non-Newtonian fluid is a fluid whose flow properties differ in any way from those of Newtonian fluids. Viscosity dependent on shear rate or shear rate history Eg:- Many salt solutions, molten polymers & many commonly found substances such as ketchup, custard, toothpaste, starch suspensions, paint, blood, and shampoo

8
Newtonian V/s Non –Newtonian Newtonian fluid Relation between shear stress and shear rate is linear, passing through the origin The constant of proportionality being the coefficient of viscosity Non -Newtonian fluid Relation between the shear stress and the shear rate is different Can even be time-dependent. Coefficient of viscosity cannot be defined. The concept of viscosity is used to characterize the shear properties of a fluid Inadequate to describe non-Newtonian fluids

9
Types of non-Newtonian behaviour τyτy

10
Ideal or Elastic solids Force needed to extend or compress a spring by some amount is proportional to that amount is a constant characteristic of the spring, stiffness. Hooke's law

11
Ideal or Elastic solids Under stress, deformed instantaneously and experiences an internal force that oppose the deformation and restore it to its original state if the external force (stress) is no longer applied Strain α Applied stress F/A = k ∆L/ L 0 σ = EεE : Youngs modulus

12
Under a constant stress, an ideal elastic solid deform immediately to a fixed & constant level in eqm with applied stress and will not deform or strain further with time. Ideal or Elastic solids

13
Stress–strain curve 1. Ultimate strength 2. Yield strength – corresponds to yield point 3. Rupture 4. Strain hardening region 5. Necking region A: Engineering stress (F/A 0 ) B: True stress (F/A)

14
Also termed as tensile strength (TS) or ultimate strength : maximum stress that a material can withstand while being stretched or pulled before failing or breaking. 1. Ultimate tensile strength (UTS)

15
2. Yield (engineering) Yield strength or yield point : The stress at which a material begins to deform plastically Prior to the yield point the material will deform elastically and will return to its original shape when the applied stress is removed. Once the yield point is passed, some fraction of the deformation will be permanent and non- reversible.

16
3. Fracture * Separation of an object or material into two, or more, pieces under the action of stress * The fracture of a solid almost always occurs due to the development of certain displacement discontinuity surfaces within the solid. * Displacement develops in this case perpendicular to the surface of displacement, it is called a normal tensile crack or simply a crack * Displacement develops tangentially to the surface of displacement, it is called a shear crack, slip band, or dislocation.

17
4. Strain hardening Also known as Work hardening (cold working) Strengthening of a metal by plastic deformation. This occurs because of dislocation movements and dislocation generation within the crystal structure of the material. Most non-brittle metals (with high melting point) & several polymers can be strengthened

18
5. Necking Necking: a mode of tensile deformation Relatively large amounts of strain localize disproportionately in a small region of the material The resulting prominent decrease in local cross-sectional area provides the basis for the name "neck" A PE sample with a stable neck

19
Viscoelasticity & Rheology Pure Newtonian viscosity & pure elastic behaviour are ideal All motions of real bodies have flow and elastisity Elastoviscous liquids or viscoelastic solids Polymers are viscoelastic

20
Polymer viscoelasticity Inter-relationship among elasticity, flow & molecular motion Time dependent flow behaviour Creep & Stress relaxation

21
OVERVIEW POLYMERS TREATED AS SOLIDS Strength Stiffness Toughness POLYMERS TREATED AS FLUIDS Viscosity of polymer melts Elastic properties of polymer melts VISCOELASTIC PROPERTIES Creep Stress relaxation

22
Stress Relaxation and Creep – Chemical versus Physical Processes – Analysis with Springs and Dashpots – Relaxation and Retardation Times – Physical Aging of Glassy Polymers

23
Creep 3 kg Time Deformation under a constant load as a function of time Creep or Creep strain may be either fully recoverable with time or involve permanant deformation with partial recovery

24
Stress Relaxation Constant deformation experiment Stress decreases with time Slowly drops to zero as the material undergo permanant set to the stretched length 3 kg4 kg5 kg6 kg Time

25
Reasons for Stress Relaxation and Creep 1. Chain Scission: Oxidation, Hydrolysis.

26
2. Bond Interchange: Polyester, Polysiloxane Polyamides, Polyethers Reasons for Stress Relaxation and Creep (Contd.)

27
3. Segmental Relaxations: Thirion Relaxation Reasons for Stress Relaxation and Creep (Contd.)

28
Viscous Flow: slippage of chains past one another, fast reptation All physical reasons for stress relaxation and creep are related to molecular motion (strain) induced by stress, therefore, must be related to conformational changes

29
Mechanical models of viscoelsatic materials Maxwell & Kelvin (Voigt) Element Using Springs (purely elastic) and Dashpots (purely viscous) For a spring σ = E ε (Hooke’s Law) For a dashpot σ = η dε/dt (Newton’s Law)

30
Springs Stretched instantaneously under stress & holding that stress indefinitely Store energy and respond instantaneously. SpringDashpot Under stress piston moves through the fluid Rate α stress No recovery on removing Dissipate energy in the form of heat.

31
Maxwell & Kelvin (Voigt) Element

32
Maxwell Model Spring & Dashpot are in series Developed to explain the behavior of pitch and tar Maxwell assumed that such materials can undergo viscous flow and also respond elastically Combine Hooke’s and Newton’s laws E η Creep Experiment

33
Strains are additive, ie; ε = ε elast + ε visc ε(t) = σ/G + σt/η 1 st term -- instantaneous elastic response 2 nd term -- the viscous retarded response. Both elements feel the same stress Residual stress at time t, σ = σ 0 exp ( -t/λ) λ : relaxation time, σ 0 : initial stress E η ε = σ /E Creep Experiment - Maxwell Model (contd)

34
Kelvin (Voigt) Element Spring & dashpot are in parallel Combine Hooke’s and Newton’s laws Both elements feel the same strain Stress is additive, ie; σ = σ elast + σ visc σ = ε Ε + η dε/dt Creep Experiment

35
Both spring & dashpot undergo concerted motion Dashpot slowly responds to the stress & viscous flow decreases asymptotically Strain rate at Dashpot, d ε /dt = σ/ η Spring bears all the stress – spring & dashpot stop deforming together- creep stops Overall stress is constant ε(t) = σ 0 [1 - exp(-t /η)] This is a Creep Experiment. The strain reaches a limiting value at long times. Creep Experiment - Kelvin (Voigt) Element

36
Stress Relaxation Experiments Maxwell Element Apply an instantaneous deformation, ε 0 and keep it constant, record the decaying stress: ε = ε elast + ε visc dε/dt = (1/G) dσ/dt + σ/η E η

37
Since the shear strain is kept constant dσ/dt = -Gσ/η σ(t) = σ 0 exp(-Gt/η) Stress relaxation modulus G(t) = σ(t) / ε 0 This is a Stress Relaxation Experiment. The quantity τ 1 = η/G has units of time and is called the Relaxation Time Stress Relaxation Experiments (contd.)

38
Stress Relaxation Stress-Strain Behaviors Maxwel Model Kelvin-Voigt Models

39
Stress Relaxation and Creep The Four Element Model Combination of Maxwell and Kelvin elements in series Used to describe the viscoelastic deformation of polymers in simple terms

40
The Four Element Model OA: Instantaneous extension (Maxwell element, E1) AB: Creep or retarded deformation (Kelvin element ) BC1: Instantaneous & partial recovery (Maxwell element E1) C1D:Time dependant recovery (Creep recovery) – t1 to t2 (Kelvin element) DE: Permanant deformation Note that the recovery is not complete. A B C1C1 D ---------------------- -------- ---------------- C2C2 C3C3 E t1t1 t2t2 F

41
Relaxation time Maxwell Model Spring & Dashpot are in series ε = ε elast + ε visc dε/dt = 1/E dσ /dt + σ /η dσ /dt = E dε/dt - E σ /η = E dε/dt - σ /λ : λ = η/E – Relaxation time

42
Relaxation time: Order of magnitude of time required for a certain proportion of polymer chain to relax (ie; to responds to the external stress ) Time required for a chemical reaction to takes place Bond interchange, degradation, hydrolysis & oxidation

43
Retardation time Kelvin (Voigt) Element Spring & dashpot are in parallel σ = σ elast + σ visc σ = ε Ε + η dε/dt ε= σ/E - η/E dε/dt Under cont stress the eqn integrated to ε= σ/E (1-e - (E/ η)t ) ε= σ/E (1-e - t/τ ) : τ = η/E Retardation time

44
For four element model under cont stress ε = ε 1 + ε 2 + ε 3 ε= σ/E 1 + σ/E 2 (1-e - t/τ ) + (σ /η 3 ) t elastic term Viscoelastic effectViscous effect Retardation time: time required for E 2 & η 2 in kelvin element to deform 1-1/e or 63.21 % of the total expected creep

45
Time-Temperature Superposition Principle – Method of Superposition – WLF Equation and Application

46
Time-Temperature Superposition The Stress relaxation modulus depends on temperature and time.

47
First: Choose an arbitrary reference temperature T 0. Second: Shift, along the time axis, the stress relaxation modulus curve recorded at T just above or below T 0, so that these two curves superpose partially. Third: Repeat the procedure until all curves have been shifted to be partially superposed with the previous ones. Four: Keep track of aT, the amount a curve recorded at T is shifted. No shift for curve recorded at T 0.

Similar presentations

© 2017 SlidePlayer.com Inc.

All rights reserved.

Ads by Google